Primitive of Reciprocal of Root of x squared plus a squared/Inverse Hyperbolic Sine Form

Theorem

 * $\ds \int \frac {\d x} {\sqrt {x^2 + a^2} } = \arsinh {\frac x a} + C$

Proof
Let:

Also see

 * Primitive of $\dfrac 1 {\sqrt {x^2 - a^2} }$: Inverse Hyperbolic Cosine Form
 * Primitive of $\dfrac 1 {\sqrt {a^2 - x^2} }$