Independent Set can be Augmented by Larger Independent Set/Corollary

Theorem
Let $M = \struct {S, \mathscr I}$ be a matroid.

Let $X \subseteq S$ be an independent subset of $M$. Let $B \subseteq S$ be a base of $M$.

Then:
 * $\exists Z \subseteq B \setminus X : \card{X \cup Z} = \card B : X \cup Z$ is a base of $M$

Proof
From Leigh.Samphier/Sandbox/Cardinality of Independent Set of Matroid is Smaller or Equal to Base:
 * $\card X \le \card B$

Case 1: $\card X < \card B$
From Independent Set can be Augmented by Larger Independent Set:
 * $\exists Z \subseteq B \setminus X : X \cup Z \in \mathscr I : \card {X \cup Z} = \card B$

Case 2: $\card X = \card B$
Let $Z = \O$.

Then:
 * $Z \subseteq B \setminus X : X \cup Z \in \mathscr I : \card {X \cup Z} = \card B$

From Leigh.Samphier/Sandbox/Independent Subset is Base if Cardinality Equals Cardinality of Base:
 * $X \cup Z$ is a base of $M$