Primitive of Inverse Hyperbolic Cotangent of x over a over x squared

Theorem

 * $\displaystyle \int \frac {\coth^{-1} \dfrac x a \rd x} {x^2} = \frac {-\coth^{-1} \dfrac x a} x + \frac 1 {2 a} \map \ln {\frac {x^2} {x^2 - a^2} } + C$

Proof
With a view to expressing the primitive in the form:
 * $\displaystyle \int u \frac {\d v} {\d x} \rd x = u v - \int v \frac {\d u} {\d x} \rd x$

let:

and let:

Then:

Also see

 * Primitive of $\dfrac {\sinh^{-1} \frac x a} {x^2}$


 * Primitive of $\dfrac {\cosh^{-1} \frac x a} {x^2}$


 * Primitive of $\dfrac {\tanh^{-1} \frac x a} {x^2}$