Change of Base of Logarithm/Base 10 to Base e/Form 1

Theorem
Let $\ln x$ be the natural (base $e$) logarithm of $x$.

Let $\log_{10} x$ be the common (base $10$) logarithm of $x$.

Then:
 * $\ln x = \left({\ln 10}\right) \left({\log_{10} x}\right) = 2 \cdotp 30258 \, 50929 \, 94 \ldots \log_{10} x$

Proof
From Change of Base of Logarithm:
 * $\log_a x = \log_a b \ \log_b x$

Substituting $a = e$ and $b = 10$ gives:
 * $\ln x = \left({\ln 10}\right) \left({\log_{10} x}\right)$

The Natural Logarithm of 10:
 * $\ln 10 = 2 \cdotp 30258 \, 50929 \, 94 \ldots$

can be calculated or looked up.