Derivative of Sine of Function

Theorem
Let $u$ be a differentiable real function of $x$.

Then:
 * $\map {\dfrac \d {\d x} } {\sin u} = \cos u \dfrac {\d u} {\d x}$

where $\sin$ is the sine function and $\cos$ is the cosine function.

Also see

 * Derivative of Cosine of Function


 * Derivative of Tangent of Function
 * Derivative of Cotangent of Function


 * Derivative of Secant of Function
 * Derivative of Cosecant of Function