Union of Subclass is Subclass of Union of Class

Theorem
Let $A$ and $B$ be classes.

Let $\ds \bigcup A$ and $\ds \bigcup B$ denote the union of $A$ and union of $B$ respectively.

Let $A$ be a subclass of $B$:
 * $A \subseteq B$

Then $\ds \bigcup A$ is a subclass of $\ds \bigcup B$:
 * $\ds \bigcup A \subseteq \ds \bigcup B$

Proof
Let $x \in \ds \bigcup A$.

Then:
 * $\exists y \in A: x \in y$

But as $A \subseteq B$ it follows that $y \in B$.

That is:
 * $\exists y \in B: x \in y$

That is:
 * $x \in \ds \bigcup B$

Hence the result by definition of subclass.