Primitive of x over Root of x squared minus a squared

Theorem

 * $\displaystyle \int \frac {x \rd x} {\sqrt {x^2 - a^2} } = \sqrt {x^2 - a^2} + C$

for $\size x > a$.

Proof
Let:

Also see

 * Primitive of $\dfrac x {\sqrt {x^2 + a^2} }$
 * Primitive of $\dfrac x {\sqrt {a^2 - x^2} }$