Effect of Sequence of Elementary Row Operations on Determinant

Theorem
Let $\hat o_1, \ldots, \hat o_m$ be a finite sequence of elementary row operations.

Here, $\hat o_i$ denotes an elementary row operation on a square matrix of order $n$ over a commutative ring with unity $\struct {R, +, \circ}$.

Here, $i \in \set {1, \ldots, m}$.

Then there exists $c \in R$ such that for all square matrices of order $n$ $\mathbf A$ over $R$:


 * $\map \det {\mathbf A} = c \map \det {\mathbf A'}$

where $\mathbf A'$ is the square matrix of order $n$ that results from applying the elementary row operations $\hat o_1, \ldots, \hat o_m$ on $\mathbf A$.

Proof
Proof by induction on $m$, the number of elementary row operations in the sequence $\hat o_1, \ldots, \hat o_m$.

Basis for the Induction
Suppose $m = 1$, so there is only one elementary row operation $\hat o$ in the sequence.

Let $r_i$ denote the $i$'th row of $\mathbf A$.

Suppose that $\hat o$ is of the type $r_i \to a r_i$, where $a \in R$ and $i \in \set {1, \ldots, n}$.

From Effect of Elementary Row Operations on Determinant, it follows that:


 * $\map \det {\mathbf A} = a \map \det {\mathbf A'}$

Suppose that $\hat o$ is of the type $r_i \to r_i + ar_j$, where $a \in R$ and $i, j \in \set {1, \ldots, n}, i \ne j$.

From Effect of Elementary Row Operations on Determinant, it follows that


 * $\map \det {\mathbf A} = \map \det {\mathbf A'} = 1_R \map \det {\mathbf A'}$

where $1_R$ denotes the identity element of $\struct {R, \circ}$.

Suppose that $\hat o$ is of the type $r_i \leftrightarrow r_j$.

From Effect of Elementary Row Operations on Determinant, it follows that


 * $\map \det {\mathbf A} = -\map \det {\mathbf A'} = -1_R \map \det {\mathbf A'}$

where the last equality follows from Product with Ring Negative: Corollary.

This is the basis for the induction.

Induction Hypothesis
For $m \in \N$, let $\hat o_1, \ldots, \hat o_m$ be a finite sequence of elementary row operations.

This is the induction hypothesis:

There exists $c \in R$ such that for all matrices of order $n$ $\mathbf A$:


 * $\map \det {\mathbf A} = c \map \det {\mathbf A'}$

where $\mathbf A'$ is the matrix of order $n$ that results from using the elementary row operations $\hat o_1, \ldots, \hat o_m$ on $\mathbf A$.

Induction Step
This is the induction step:

Let $\hat o_1, \ldots, \hat o_m, \hat o_{m + 1}$ be a finite sequence of elementary row operations.

Let $r_i$ denote the $i$'th row of $\mathbf A'$.

Let $\mathbf A''$ denote the matrix of order $n$ that results from using the elementary row operation $\hat o_{m + 1}$ on $A'$.

Then $\mathbf A''$ is equal to the matrix that results from using the elementary row operations $\hat o_1, \ldots, \hat o_m, \hat o_{m + 1}$ on $A$.

Suppose that $\hat o_{m + 1}$ is of the type $r_i \to ar_i$, where $a \in R$ and $i \in \set {1, \ldots, n}$.

Then:

Suppose that $\hat o_{m + 1}$ is of the type $r_i \to r_i + a r_j$, where $a \in R$ and $i, j \in \set {1, \ldots, n}, i \ne j$.

Then:

Suppose that $\hat o_{m + 1}$ is of the type $r_i \leftrightarrow r_j$.

Then:

Then the induction step is proved for all three types of elementary row operations.