Set with Dispersion Point is Biconnected

Theorem
Let $T = \left({S, \tau}\right)$ be a topological space.

Let $H \subseteq S$ be a connected set in $T$.

Let $p \in H$ be a dispersion point of $H$.

Then $H$ is biconnected.

Proof
$H$ is not biconnected.

Then by definition there exist disjoint non-degenerate connected sets $U, V$ such that $H = U \cup V$.

, let $p \in U$.

Then $V \subset H \setminus \left\{ {p}\right\}$.

As $p$ is a dispersion point of $H$, $H \setminus \left\{ {p}\right\}$ is totally disconnected.

Thus, by definition, $H \setminus \left\{ {p}\right\}$ contains no non-degenerate connected sets.

But this contradicts our definition of $V$, as $V \subset H \setminus \left\{ {p}\right\}$.

It follows by Proof by Contradiction that $H$ is biconnected.