Groups of Order 30/Mistake

Source Work

 * Chapter $13$: Direct products:
 * Theorem $13.8$
 * Theorem $13.8$

Mistake

 * To show that $x$ normalises $K$, note that
 * $x x^5 x^{-1} = x$, and $x y x^{-1} = x y^{-1} x^{-1} = y x^{11} x^{-1} = y x^{10} \in N$.''

Correction
There are two mistakes here:


 * $(1): \quad x x^5 x^{-1} = x$ makes no sense in this context. Here we have $x^5 = w$, which we are trying to show is the conjugate of $x$.
 * So it is apparent that what is meant is more likely something along the lines of:
 * $x w x^{-1} = x x^5 x^{-1} = x^5 = w$


 * $(2): \quad$ That last $N$ looks as though it ought to be $K$, as there is no $N$ defined in this section.