Powers of Group Elements/Sum of Indices/Additive Notation

Theorem
Let $\struct {G, +}$ be a group whose identity is $e$.

Let $g \in G$.

Then:
 * $\forall m, n \in \Z: \paren {m \cdot g} + \paren {n \cdot g} = \paren {m + n} \cdot g$

Proof
All elements of a group are invertible, so we can directly use the result from Index Laws for Monoids: Sum of Indices:


 * $\forall m, n \in \Z: g^m \circ g^n = g^{m + n}$

where in this context the group operation is $+$ and $n$th power of $g$ is denoted $n g$.