Power Structure of Group is Semigroup

Theorem
Let $\left({G, \circ}\right)$ be a group.

Then its power set $\mathcal P \left({G}\right)$ is a semigroup $\left({\mathcal P \left({G}\right), \circ_\mathcal P}\right)$ with respect to the subset product.

Proof
We need to prove closure and associativity.


 * Closure:

Let $\left({G, \circ}\right)$ be a group, and let $A, B \subseteq G$.


 * Associativity: This follows from Subset Product of Associative is Associative.

Thus $\left({\mathcal P \left({G}\right), \circ_\mathcal P}\right)$ is a semigroup.