Linear First Order ODE/y' - (y over x) = k x

Theorem
Let $k \in \R$ be a real number.

The linear first order ODE:
 * $(1): \quad \dfrac {\d y} {\d x} - \dfrac y x = k x$

has the general solution:
 * $\dfrac y x = k x + C$

or:
 * $y = k x^2 + C x$

Proof
$(1)$ is in the form:
 * $\dfrac {\d y}{\d x} + \map P x y = \map Q x$

where $\map P x = -\dfrac 1 x$.

Thus:

Thus from Solution by Integrating Factor, $(1)$ can be rewritten as:
 * $\dfrac {\d} {\d x} \paren {\dfrac y x} = \dfrac 1 x k x = k$

and the general solution is:
 * $\dfrac y x = k x + C$

or:
 * $y = k x^2 + C x$