Set of Strictly Positive Real Numbers has no Smallest Element

Theorem
Let $\R_{>0}$ denote the set of strictly positive real numbers.

Then $\R_{>0}$ has no smallest element.

Proof
$\R_{>0}$ has a smallest element.

Let $m$ be that smallest element.

Then we have that:
 * $0 < \dfrac m 2 < m$

But as $0 \dfrac m 2$ it follows that $\dfrac m 1 \in \R_{>0}$.

This contradicts our assertion that $x$ is the smallest element of $\R_{>0}$.

Hence the result by Proof by Contradiction.