Path Component is not necessarily Arc Component

Theorem
Let $T = \left({S, \tau}\right)$ be a topological space.

Let $P$ be a path component of $T$.

Then it is not necessarily the case that $P$ is also an arc component of $T$.

Proof
Let $T = \left({S, \tau_p}\right)$ be a finite particular point space.

From Particular Point Space is Path-Connected, $T$ is path-connected.

Therefore $S$ is a path component in $T$.

But from Particular Point Space is not Arc-Connected, $T$ is not arc-connected.

Therefore $S$ is not an arc component in $T$.

Hence the result.