Talk:Polynomial over Field is Reducible iff Scalar Multiple is Reducible

As it stands it doesn't: If $P \in \Z[X]$ is any irreducible polynomial and $\lambda \in \Z$ is a prime, then $\lambda P$ is a product of two irreducible elements. In an arbitrary ring we need the additional hypothesis that $\lambda$ is a unit. --Linus44 (talk) 10:29, 22 March 2013 (UTC)