Talk:Quaternion Group not Dihedral Group

Proofs of a concrete group
In any proof, it is best to use the representation of the group which is easier to manipulate in that proof.

In this case is easier to see that $-1$ is the only element of $Q$ that has order $2$; using the representation $Q=\{1,-1,i,-i,j,-j,k,-k\}$ and the usual multiplication from $\mathbb{H}$.


 * Maybe. But in this case the particular concretisation is not defined on the proof page. In order for the proof to make sense, the fact that this particular representation is to be used needs to be specified. --prime mover 03:28, 16 December 2011 (CST)