Primitive of Cube of Secant of a x

Theorem

 * $\displaystyle \int \sec^3 a x \rd x = \frac 1 {2 a} \paren {\sec a x \tan a x + \ln \size {\sec a x + \tan a x} } + C$

Also see

 * Primitive of $\sin^3 a x$
 * Primitive of $\cos^3 a x$
 * Primitive of $\tan^3 a x$
 * Primitive of $\cot^3 a x$
 * Primitive of $\csc^3 a x$