Propositiones ad Acuendos Juvenes/Problems/28 - De Civitate Triangula

by : Problem $28$

 * De Civitate Triangula: A Triangular Town
 * A triangular town measures $100$ feet along one side,
 * $100$ feet along another side
 * and $90$ feet along the front.


 * I want to build houses there,
 * each house being $20$ feet long
 * and $10$ feet wide.


 * How many houses can there be?

Solution
Adding the two sides makes $200$ feet.

The half of $200$ is $100$.

The front measures $90$ and the half of $90$ is $45$.

Because each house is $20$ feet long and $20$ feet wide:
 * take one $20$th of $100$ which is $5$
 * and take one $10$th of $40$ which is $4$.

Then $5$ times $4$ is $20$.

That is the number of houses the town should contain.