Divisor Count of 108/Mistake

Source Work

 * The Dictionary
 * $108$
 * $108$

Mistake

 * The number of its factors is also a cube: $8$.

Notwithstanding the fact that the also is redundant, as $108$ is not actually a cube itself for $8$ to be also to, the count of the factors of $108$ is in fact $12$, not $8$.

This is shown at.

It is probable that this is a typesetting error, as in the following paragraph it is pointed out that $\map \sigma {110}$ is a cube.

We also have from that $\map {\sigma_0} {110}$ is indeed equal to $8$.