Self-Distributive Law for Conditional/Reverse Implication/Formulation 1/Proof

Theorem

 * $\left({p \implies q}\right) \implies \left({p \implies r}\right) \vdash p \implies \left({q \implies r}\right)$

Proof

 * align="right" | 4 ||
 * align="right" | 3
 * $p \implies q$
 * Sequent Introduction
 * 3
 * True Statement is Implied by Every Statement
 * True Statement is Implied by Every Statement