First Isomorphism Theorem/Rings

Theorem
Let $\phi: R \to S$ be a ring homomorphism.

Let $\map \ker \phi$ be the kernel of $\phi$.

Then:
 * $\Img \phi \cong R / \map \ker \phi$

where $\cong$ denotes ring isomorphism.

Proof
From Ring Homomorphism whose Kernel contains Ideal, let $J = \map \ker \phi$.

This gives the ring homomorphism $\mu: R / \map \ker \phi \to S$ as follows:


 * CommDiagFirstIsomTheorem.png

That is:
 * $\phi = \mu \circ \nu$

Then we have:
 * $\map \ker \mu = \map \ker \phi / \map \ker \phi$

This is the null subring of $R / \map \ker \phi$ by Quotient Ring Defined by Ring Itself is Null Ideal.

Then from Kernel is Trivial iff Monomorphism it follows that $\mu$ is a monomorphism.

From $\phi = \mu \circ \nu$, we have:
 * $\Img \mu = \Img \phi$

It follows that $\mu$ is an isomorphism.

Also known as
This result is also referred to as the First Fundamental Theorem on Ring Homomorphisms.

Also see

 * Isomorphism Theorems
 * Universal Property of Quotient Ring