365

Number
$365$ (three hundred and sixty-five) is:


 * $5 \times 73$


 * The $1$st positive integer which is the sum of both $2$ and $3$ consecutive non-zero square numbers:
 * $365 = 10^2 + 11^2 + 12^2 = 13^3 + 14^2$


 * The $18$th positive integer $n$ after $0$, $1$, $5$, $25$, $29$, $41$, $49$, $61$, $65$, $85$, $89$, $101$, $125$, $145$, $149$, $245$, $265$ such that the Fibonacci number $F_n$ ends in $n$