Quotient of Cauchy Sequences is Metric Completion/Lemma 2

Theorem
Let $\struct {R, \norm {\, \cdot \,} }$ be a normed division ring.

Let $d$ be the metric induced by $\struct {R, \norm {\, \cdot \,} }$.

Let $\CC$ be the ring of Cauchy sequences over $R$

Let $\NN$ be the set of null sequences.

Let $\CC \,\big / \NN$ be the quotient ring of Cauchy sequences of $\CC$ by the maximal ideal $\NN$.

Let $\norm {\, \cdot \,}: \CC \,\big / \NN \to \R_{\ge 0}$ be the norm on the quotient ring $\CC \,\big / \NN$ defined by:
 * $\ds \forall \sequence {x_n} + \NN: \norm {\sequence {x_n} + \NN} = \lim_{n \mathop \to \infty} \norm {x_n}$

Let $d'$ be the metric induced by $\struct {\CC \,\big / \NN, \norm {\, \cdot \,} }$

Let $\sim$ be the equivalence relation on $\CC$ defined by:


 * $\ds \sequence {x_n} \sim \sequence {y_n} \iff \lim_{n \mathop \to \infty} \map d {x_n, y_n} = 0$

Let $\tilde {\CC} = \CC / \sim$ denote the set of equivalence classes under $\sim$.

For $\sequence {x_n} \in \CC$, let $\eqclass {x_n} {}$ denote the equivalence class containing $\sequence {x_n}$.

Let $\tilde d: \tilde {\CC} \times \tilde {\CC} \to \R_{\ge 0}$ be the metric defined by:
 * $\map {\tilde d} {\eqclass {x_n} {}, \eqclass {y_n} {} } = \lim_{n \mathop \to \infty} \map d {x_n, y_n}$

Then:
 * $\quad d' = \tilde d$

Proof
By Lemma 1 of Quotient of Cauchy Sequences is Metric Completion we have that:
 * $\CC \,\big / \NN = \tilde {\CC}$

Let $\eqclass {x_n} {}$ and $\eqclass {x_n} {}$ be equivalence classes in $\CC \,\big / \NN = \tilde {\CC}$.

Then:

The result follows.