Linear Second Order ODE/y'' + 4 y' + 4 y = 0

Theorem
The second order ODE:
 * $(1): \quad y'' + 4 y' + 4 y = 0$

has the general solution:
 * $y = \paren {C_1 + C_2 x} e^{-2 x}$

Proof
It can be seen that $(1)$ is a constant coefficient homogeneous linear second order ODE.

Its auxiliary equation is:
 * $(2): \quad: m^2 + 4 m + 4 = 0$

From Solution to Quadratic Equation: Real Coefficients, the roots of $(2)$ are:
 * $m_1 = m_2 = -2$

These are real and equal.

So from Solution of Constant Coefficient Homogeneous LSOODE, the general solution of $(1)$ is:
 * $y = C_1 e^{-2 x} + C_2 x e^{-2 x}$