Closure of Infinite Union may not equal Union of Closures

Theorem
Let $T$ be a topological space.

Let $I$ be an infinite indexing set.

Let $\family {H_i}_{i \mathop \in I}$ be an indexed family of subsets of a set $S$.

Let $\displaystyle H = \bigcup_{i \mathop \in I} H_i$ be the union of $\family {H_i}_{i \mathop \in I}$.

Then it is not always the case that:
 * $\displaystyle \bigcup_{i \mathop \in I} \map \cl {H_i} = \map \cl {\bigcup_{i \mathop \in I} H_i}$

where $\map \cl {H_i}$ denotes the closure of $H_i$.

Proof
Let $\displaystyle H_n \subseteq \R: H_n = \closedint {\frac 1 n} 1$ for $n \ge 2$.

Then:
 * $\map \cl {H_n} = H_n$

Also:
 * $\displaystyle \bigcup_{n \mathop \ge 2} \map \cl {H_n} = \bigcup_{n \mathop \ge 2} H_n = \hointl 0 1$

However:
 * $\displaystyle \map \cl {\bigcup_{n \mathop \ge 2} H_n} = \closedint 0 1$

So:
 * $\displaystyle \bigcup_{n \mathop \ge 2} \map \cl {H_n} \ne \map \cl {\bigcup_{n \mathop \ge 2} H_n}$