Sequential Continuity is Equivalent to Continuity in the Reals/Necessary Condition

Theorem
Let $A \subseteq \R$ be a subset of the real numbers.

Let $c \in A$.

Let $f : A \to \R$ be a real function.

Then if $f$ is continuous at $c$:


 * for each sequence $\sequence {x_n}$ in $A$ that converges to $c$, the sequence $\sequence {\map f {x_n} }$ converges to $\map f c$.

Proof
Let $c \in \R$.

Let $\sequence {x_n}$ be a sequence in $A$ that converges to $c$.

Let $\varepsilon \in \R_{> 0}$.

Since $f$ is continuous at $c$, there exists $\delta > 0$ such that:


 * for all $x \in A$ with $\size {x - c} < \delta$, we have $\size {\map f x - \map f c} < \varepsilon$.

Additionally, since $\sequence {x_n}$ converges to $c$, there exists $N \in \N$ such that:


 * for all $n > N$ we have $\size {x_n - c} < \delta$.

Therefore, since $x_n \in A$ for all $n \in \N$:


 * for all $n > N$, we have $\size {\map f {x_n} - \map f c} < \varepsilon$.

Since $\varepsilon$ was arbitrary, we have:


 * $\sequence {\map f {x_n} }$ converges to $\map f c$.