Quadratic Equation/Examples/z^2 + (i-2)z + (3-i) = 0

The quadratic equation in $\C$:
 * $z^2 + \paren {i - 2} z + \paren {3 - i} = 0$

has the solutions:


 * $z = \begin{cases} 1 + i \\ 1 - 2 i \end{cases}$

Proof
From the Quadratic Formula: