Ceiling of x+m over n/Corollary

Corollary to Ceiling of $\frac {x + m} n$
Let $n \in \Z$ such that $n > 0$.

Let $x \in \R$.

Then:
 * $\left \lceil{\dfrac x n}\right \rceil = \left \lceil{\dfrac {\left \lceil{x}\right \rceil} n}\right \rceil$

where $\left\lceil{x}\right\rceil$ denotes the ceiling of $x$.

Proof
This is a special case of Ceiling of $\dfrac {x + m} n$:
 * $\left \lceil{\dfrac {x + m} n}\right \rceil = \left \lceil{\dfrac {\left \lceil{x}\right \rceil + m} n}\right \rceil$

where $m = 0$.