Combination Theorem for Sequences/Complex/Multiple Rule

Theorem
Let $\sequence {z_n}$ be a sequence in $\C$.

Let $\sequence {z_n}$ be convergent to the following limit:


 * $\displaystyle \lim_{n \mathop \to \infty} z_n = c$

Let $\lambda \in \C$.

Then:
 * $\displaystyle \lim_{n \mathop \to \infty} \paren {\lambda z_n} = \lambda c$

Proof
Let $\epsilon > 0$.

We need to find $N$ such that:
 * $\forall n > N: \cmod {\lambda z_n - \lambda c} < \epsilon$

If $\lambda = 0$ the result is trivial.

So, assume $\lambda \ne 0$.

Then $\cmod \lambda > 0$ from the definition of the modulus of $\lambda$.

Hence $\dfrac \epsilon {\cmod \lambda} > 0$.

We have that $z_n \to c$ as $n \to \infty$.

Thus it follows that:
 * $\exists N: \forall n > N: \cmod {z_n - c} < \dfrac \epsilon {\cmod \lambda}$

That is:
 * $\forall n > N: \cmod \lambda \cmod {z_n - c} < \epsilon$

But we have:

Hence:
 * $\displaystyle \lim_{n \mathop \to \infty} \paren {\lambda x_n} = \lambda c$