1,048,576

Number
$1 \, 048 \, 576$ (one million, forty-eight thousand, five hundred and seventy-six) is:
 * $2^{20}$


 * The $1$st of a sequence of $7$ numbers which are square and anagrams of each other


 * The number of different binary operations with an identity element that can be applied to a set with $4$ elements


 * The number of different commutative binary operations that can be applied to a set with $4$ elements


 * The $5$th power of $16$ after $(1)$, $16$, $256$, $4096$, $65 \, 536$:
 * $1 \, 048 \, 576 = 16^5$


 * The $10$th power of $4$ after $(1)$, $4$, $16$, $64$, $256$, $1024$, $4096$, $16 \, 384$, $65 \, 536$, $262 \, 144$:
 * $1 \, 048 \, 576 = 4^{10}$


 * The $16$th fifth power after $1$, $32$, $243$, $1024$, $3125$, $7776$, $16 \, 807$, $32 \, 768$, $59 \, 049$, $100 \, 000$, $161 \, 051$, $248 \, 832$, $371 \, 293$, $537 \, 824$, $759 \, 375$:
 * $1 \, 048 \, 576 = 16 \times 16 \times 16 \times 16 \times 16$
 * Hence $100 \, 000$ in hexadecimal.


 * The $20$th power of $2$ after $(1)$, $2$, $4$, $8$, $16$, $\ldots$, $16 \, 384$, $32 \, 768$, $65 \, 536$, $131 \, 072$, $262 \, 144$, $524 \, 288$:
 * $1 \, 048 \, 576 = 2^{20}$


 * The $21$st almost perfect number after $1$, $2$, $4$, $8$, $16$, $\ldots$, $16 \, 384$, $32 \, 768$, $65 \, 536$, $131 \, 072$, $262 \, 144$, $524 \, 288$:
 * $\map {\sigma_1} {1 \, 048 \, 576} = 2 \, 097 \, 151 = 2 \times 524 \, 288 - 1$


 * The $32$nd fourth power:
 * $1 \, 048 \, 576 = 32 \times 32 \times 32 \times 32$


 * The $1024$th square number:
 * $1 \, 048 \, 576 = 1024 \times 1024$

Also see