Talk:Linear Operator on General Logarithm

I'm not sure how to look at linear operators, that's why I'm confused LF. Is the domain a subset of the reals, or is the domain a set of real functions? That's why I didn't say $\phi: \R \to \R$, because I wanted $\phi$ to have the connotation of a function on functions. As to $y$, that was a mistake, you're correct it should be $y>0$ not $\phi(y) > 0$ In any event, it needs to be clear that we're dealing with a function of $y$ here and $\ln a$ is a constant multiple. --GFauxPas 17:27, 16 January 2012 (EST)