Equivalence of Axiom Schemata for Groups/Warning

Theorem
Suppose we build an algebraic structure with the following axioms:

Then this does not (necessarily) define a group (although clearly a group fulfils those axioms).

Proof
Let $\struct {S, \circ}$ be the algebraic structure defined as:
 * $\forall x, y \in S: x \circ y = x$

That is, $\circ$ is the left operation.

From Element under Left Operation is Right Identity, every element serves as a right identity.

Then given any $a \in S$, we have that $x \circ a = x$ and as $x$ is an identity, axiom $(3)$ is fulfilled as well.

But from More than one Right Identity then no Left Identity, there is no left identity and therefore no identity element.

Hence $\struct {S, \circ}$ is not a group.