Invertible Integers under Multiplication

Theorem
The only invertible elements of $\Z$ for multiplication are $1$ and $-1$.

Proof
Let $x > 0$ and $x y > 0$.

Suppose $y \le 0$.

Then from Multiplicative Ordering on Integers and Ring Product with Zero:
 * $x y \le x \, 0 = 0$

From this contradiction we deduce that $y > 0$.

Now, if we have $x > 0$ and $x y = 1$, then $y > 0$ and hence $y \in \N$ by Natural Numbers are Non-Negative Integers.

Hence by Ordering on Naturally Ordered Semigroup Product it follows that $x = 1$.

Thus $1$ is the only element of $\N$ that is invertible for multiplication.

Therefore by Natural Numbers are Non-Negative Integers and Negative Product, the result follows.