Period of Reciprocal of 53 is One Quarter of Maximal

Theorem
The decimal expansion of the reciprocal of $53$ has $\dfrac 1 4$ the maximum period, that is: $13$:
 * $\dfrac 1 {53} = 0 \cdotp \dot 01886 \, 79245 \, 28 \dot 3$

Proof
Performing the calculation using long division:

0.018867924528301... - 53)1.000000000000000000     53    212               --    ---     470    280     424    265     ---    ---      460    150      424    106      ---    ---       360    440       318    424       ---    ---        420    160        371    159        ---    ---         490     100         477      53         ---     ---          130    ...          106          ---           240           212           ---