Either-Or Topology is Lindelöf/Proof 2

Proof
Any open cover $\CC$ of $T$ must contain an open set of $T$ which contains $0$.

So $\openint {-1} 1$ will always be covered by one set in $\CC$, leaving just $-1$ and $1$ possibly needing to be included in at most two other sets.

So $\CC$ has a subcover containing at most three sets.

Hence $T$ is a Lindelöf space by definition.