Trivial Module is Module

Theorem
Let $\struct {G, +_G}$ be an abelian group whose identity is $e_G$.

Let $\struct {R, +_R, \circ_R}$ be a ring.

Let $\struct {G, +_G, \circ}_R$ be the trivial $R$-module, such that:


 * $\forall \lambda \in R: \forall x \in G: \lambda \circ x = e_G$

Then $\struct {G, +_G, \circ}_R$ is a module.

Proof
Checking the module axioms in turn:


 * $(\text M 1): \quad \lambda \circ \paren {x +_G y} = e_G = e_G +_G e_G = \paren {\lambda \circ x} +_G \paren {\lambda \circ y}$


 * $(\text M 2): \quad \paren {\lambda +_R \mu} \circ x = e_G = e_G +_G e_G = \paren {\lambda \circ x} +_G \paren {\mu \circ x}$


 * $(\text M 3): \quad \paren {\lambda \times_R \mu} \circ x = e_G = \lambda \circ e_G = \lambda \circ \paren {\mu \circ x}$

Thus the trivial module is indeed a module.