Lower Section with no Greatest Element is Open in GO-Space

Theorem
Let $\struct {S, \preceq, \tau}$ be a generalized ordered space.

Let $L$ be a lower set in $S$ with no greatest element.

Then $L$ is open in $\struct {S, \preceq, \tau}$.

Proof
By Maximal Element in Toset is Unique and Greatest, $L$ has no maximal element.

By Lower Set with no Maximal Element:
 * $\ds L = \bigcup \set {l^\prec: l \in L}$

where $l^\prec$ is the strict lower closure of $l$.

By Open Ray is Open in GO-Space and the fact that a union of open sets is open, $L$ is open.

Also see

 * Upper Set with no Smallest Element is Open in GO-Space