Primitive of Reciprocal of x squared by square of a x squared plus b x plus c/Proof 2

Proof
First:

Next, with a view to obtaining an expression in the form:
 * $\displaystyle \int u \frac {\d v} {\d x} \rd x = u v - \int v \frac {\d u} {\d x} \rd x$

let:

and let:

Then:

Thus: