Coarseness Relation on Topologies is Partial Ordering

Theorem
Let $X$ be a set.

Let $\mathbb T$ be the set of all topologies on $X$

Let $\le$ be the relation on $\mathbb T$:
 * $\forall \tau_1, \tau_2 \in \mathbb T: \tau_1 \le \tau_2 := \tau_1$ is coarser than $\tau_2$.

Then $\le$ is a partial ordering on $\mathbb T$.

Proof
Follows directly from the definition that:
 * $\tau_1 \le \tau_2 \iff \tau_1 \subseteq \tau_2$

We have that the Subset Relation is Ordering and so $\le$ is also an ordering.

From Topologies Not Always Comparable by Coarseness, it follows that such an ordering is not always total.