Primitive of Reciprocal of a x + b cubed/Mistake

Source Work

 * Chapter $14$: Indefinite Integrals:
 * Integrals involving $a x + b$: $14.73$

This mistake can be seen in the edition as published by Schaum: ISBN 0-07-060224-7 (unknown printing).

Mistake

 * $\displaystyle \int \frac {\rd x} {\left({a x + b}\right)^3} = -\frac 1 {2 \left({a x + b}\right)^2} + C$

As demonstrated in Primitive of Reciprocal of $\left({a x + b}\right)^3$ the correct expression is in fact:


 * $\displaystyle \int \frac {\rd x} {\left({a x + b}\right)^3} = -\frac 1 {2 a \left({a x + b}\right)^2} + C$