Talk:Riemann Integrable Dirac Function does not Exist

Does. $\sup_{x \mathop \in \closedint {- 1} 1 } \map \delta x $ exist?

If so, what is it? --Robkahn131 (talk) 16:45, 29 March 2021 (UTC)


 * $\delta$ is a placeholder for anything we would call a Riemann integrable Dirac function. However, Riemann integrable means that the function has to be finite. This is the point of the proof. Such a finite function does not exist.--Julius (talk) 17:43, 29 March 2021 (UTC)


 * This is also why we cannot use the definition of the Dirac function. Here $\delta$ is not the Dirac function. It's only an object which has some "Dirac" properties and is a function.--Julius (talk) 17:45, 29 March 2021 (UTC)

Doesn't quite read right to me. Wouldn't it be better to format it like, let $\phi$ be ..., let $a$ be ..., then there doesn't exist a Riemann integrable $\delta$ such that ...? Or am I being too nitpicky? Caliburn (talk) 17:28, 29 March 2021 (UTC)


 * Feel free to change according to your taste.--Julius (talk) 17:43, 29 March 2021 (UTC)