Kaprekar's Process on 3 Digit Number ends in 495/Mistake

Source Work

 * The Dictionary
 * $495$
 * $495$

Mistake

 * Take any $3$-digit number whose digits are not all the same and is not a palindrome. Arrange its digits into ascending and descending order and subtract. Repeat. This is called Kaprekar's process. All $3$-digit numbers eventually end up with $495$.

The $3$-digit number in question needs only to have its digits not all the same. A palindrome ends up at $495$ in the same way as any other number, for example: