Algebra Defined by Ring Homomorphism on Commutative Ring is Commutative

Theorem
Let $R$ be a commutative ring.

Let $\left({S, +, *}\right)$ be a commutative ring.

Let $f: R \to S$ be a ring homomorphism.

Let $\left({S_R, *}\right)$ be the algebra defined by the ring homomorphism $f$.

Then $\left({S_R, *}\right)$ is an commutative algebra.

Proof
Note that by Center of Commutative Ring, the image of $f$ is indeed a subset of the center of $S$.

By definition, the multiplication of $(S_R, *)$ is the ring product of $S$.

Thus it follows immediately from the fact that $S$ is a ring, that $(S_R, *)$ is an commutative algebra.

Also see

 * Algebra Defined by Ring Homomorphism is Algebra
 * Algebra Defined by Ring Homomorphism is Associative
 * Algebra Defined by Ring Homomorphism on Ring with Unity is Unitary