Characterizing Property of Supremum of Subset of Real Numbers

Theorem
Let $S \subset \R$ be a non-empty subset of the real numbers.

Let $S$ be bounded above.

Let $\omega \in \R$.


 * $(1): \quad \omega$ is the supremum of $S$


 * $(2): \quad \omega$ is an upper bound for $S$
 * and:
 * $\forall \epsilon \in \R_{> 0}$ there exists $x \in S$ with $x > \omega - \epsilon$

$(1)$ implies $(2)$
Let $\omega$ be the supremum of $S$.

Then by definition, $\omega$ is an upper bound for $S$.

Let $\epsilon > 0$.

Because $\omega - \epsilon < \omega$, it is not an upper bound for $S$.

Thus there exists $x\in S$ with $x > \omega - \epsilon$.

$(2)$ implies $(1)$
Let $\omega$ be an upper bound of $S$ such that $\forall \epsilon > 0$ there exists $x \in S$ with $x > \omega - \epsilon$.

Let $d \in \R$ be an upper bound of $S$.

We have to prove that $d \ge \omega$.

$d < \omega$.

Let $\epsilon = \omega - d > 0$.

Then there exists $x \in S$ such that $x > \omega - \left({\omega - d}\right) = d$.

But this contradicts our assumption that $d$ is an upper bound of $S$.

Also see

 * Characterizing Property of Infimum of Subset of Real Numbers