Primitive of x cubed over a squared minus x squared squared

Theorem

 * $\displaystyle \int \frac {x^3 \rd x} {\paren {a^2 - x^2}^2} = \frac {a^2} {2 \paren {a^2 - x^2} } + \frac 1 2 \map \ln {a^2 - x^2} + C$

for $x^2 < a^2$.

Also see

 * Primitive of $\dfrac {x^3} {\paren {x^2 - a^2}^2}$