Peirce's Law/Formulation 2/Proof 1

Theorem

 * $\vdash \left({\left({p \implies q}\right) \implies p}\right) \implies p$

Proof

 * align="right" | 2 ||
 * align="right" | 1
 * $p$
 * Sequent Introduction
 * 1
 * Formulation 1 of this law: $\left({p \implies q}\right) \implies p \vdash p$
 * Formulation 1 of this law: $\left({p \implies q}\right) \implies p \vdash p$