User:Furryoats

test
$X:\N\to \R$

Fun
If $\exists \theta \implies \exists \gamma$, then $\exists \gamma \implies \exists \alpha$

Then there must be some greater value that contains all other values. Let that value be $\beta$

Let $({\theta, \gamma, \alpha}) \in X$

Let $X \in \beta$, however, the lack of existence of beta does not imply the lack of existence of X, only that X may or may not be contained by beta.

Let $\exists \beta \implies \exists \delta$

Let Delta be the non-existence of beta

Then $X \in \beta \lor \delta$

Angles(The spell to awaken Cthulhu)
Let $V$ be a vector such that
 * $V=(r,{P'(x)})$

Let the function $f : o \to o+1$ represent the subset of the values of $(x_n,f(x)_n)$.

Let the function $f : n \to n-1$ represent the exponent set of an arbitrarily chosen $n$-degree polynomial function.

Let $m$ and $n$ converge at zero and $m$ be sequenced as the additive inverse of $f : n \to n-1$.

Let the constant of integration $\displaystyle C=\int_{a}^{b} P^m \mathrm{d}{x}$

Let $P(x)$ be a polynomial function such that

The order of a polynomial function is equal to the number of vectors such that