Talk:Cantor Set is Uncountable

In fact, the $f$ in the informal proof isn't a bijection (for the representation of binary numbers isn't unique for a certain (countable) set of numbers, namely with finitely many nonzero $b_i$). --Lord_Farin 16:25, 16 November 2011 (CST)
 * Goodness, so it isn't. Good call. --prime mover 16:40, 16 November 2011 (CST)