2016

Number

 * $2016 = 2^5 \times 3^2 \times 7$


 * $2016 = 3^3 + 4^3 + 5^3 + 6^3 + 7^3 + 8^3 + 9^3$

From Ratio of 2016 to Sum of Aliquot Parts:
 * $\dfrac {\sigma \left({2016}\right) - 2016} {2016} = \dfrac 9 4$

where $\sigma$ denotes the $\sigma$ (sigma) function.