Definition:Inverse Secant/Real/Arcsecant

Definition
From Shape of Secant Function, we have that $\sec x$ is continuous and strictly increasing on the intervals $\hointr 0 {\dfrac \pi 2}$ and $\hointl {\dfrac \pi 2} \pi$.

From the same source, we also have that:
 * $\sec x \to + \infty$ as $x \to \dfrac \pi 2^-$
 * $\sec x \to - \infty$ as $x \to \dfrac \pi 2^+$

Let $g: \hointr 0 {\dfrac \pi 2} \to \hointr 1 \to$ be the restriction of $\sec x$ to $\hointr 0 {\dfrac \pi 2}$.

Let $h: \hointl {\dfrac \pi 2} \pi \to \hointl \gets {-1}$ be the restriction of $\sec x$ to $\hointl {\dfrac \pi 2} \pi$.

Let $f: \closedint 0 \pi \setminus \dfrac \pi 2 \to \R \setminus \openint {-1} 1$:


 * $\map f x = \begin{cases}

\map g x & : 0 \le x < \dfrac \pi 2 \\ \map h x & : \dfrac \pi 2 < x \le \pi \end{cases}$

From Inverse of Strictly Monotone Function, $\map g x$ admits an inverse function, which will be continuous and strictly increasing on $\hointr 1 \to$.

From Inverse of Strictly Monotone Function, $\map h x$ admits an inverse function, which will be continuous and strictly increasing on $\hointl \gets {-1}$.

As both the domain and range of $g$ and $h$ are disjoint, it follows that:


 * $\map {f^{-1} } x = \begin{cases}

\map {g^{-1} } x & : x \ge 1 \\ \map {h^{-1} } x & : x \le -1 \end{cases}$

This function $\map {f^{-1} } x$ is called arcsecant of $x$.

Thus:
 * The domain of arcsecant is $\R \setminus \openint {-1} 1$
 * The image of arcsecant is $\closedint 0 \pi \setminus \dfrac \pi 2$.

Also see

 * Definition:Secant Function

Other inverse trigonometrical ratios

 * Definition:Arcsine
 * Definition:Arccosine
 * Definition:Arctangent
 * Definition:Arccotangent
 * Definition:Arccosecant