Talk:Derivative of Exponential Function

$$\frac{dy}{dx}=\frac{e^x(e^h-1)}{h}$$

Limit h → 0, (eh --1)→ h

$$\frac{dy}{dx}=\frac{e^xh}{h}$$

'Is the second line above correct? It seems to me that as h → 0, eh→ 1 and (eh --1)→ 0'