Greek Anthology Book XIV: 51. - Problem

Problem

 * $A$. I have what the second has and the third of what the third has.


 * $B$. I have what the third has and the third of what the first has.


 * $C$. And I have ten and the third of what the second has.

Solution
Let $a$, $b$ and $c$ (respectively) be what $A$, $B$ and $C$ have in.

We have:

So:
 * $A$ has $45$


 * $B$ has $37 \frac 1 2$


 * $C$ has $22 \frac 1 2$.