Second-Countable Space is First-Countable

Theorem
Let $T = \left({S, \tau}\right)$ be a topological space which is second-countable.

Then $T$ is also first-countable.

Proof
By definition $T$ is second-countable its topology has a countable basis.

Consider the entire set $S$ as an open set.

From Set is Open iff Neighborhood of all its Points, $S$ has that property.

As $T$ has a countable basis, then (trivially) every point in $T$ has a countable local basis.

So a second-countable space is trivially first-countable.