Existence of Rational Powers of Irrational Numbers/Proof 3

Theorem
There exist irrational numbers $a$ and $b$ such that $a^b$ is rational.

Proof
Consider the equation:
 * $\left({\sqrt 2}\right)^{\log_{\sqrt 2} 3} = 3$

We have that $\sqrt 2$ is irrational and $3$ is (trivially) rational.

It remains to be proved $\log_{\sqrt 2} 3$ is irrational.

We have:

From Irrationality of Logarithm, $\log_2 3$ is irrational.

Therefore $2 \, \log_2 3$ is irrational.

Thus there exist two irrational numbers $a = \sqrt 2$ and $b = \log_{\sqrt 2} 3$ such that $a^b$ is rational.

Also see

 * Positive Rational Number as Power of Number with Power of Itself for an interesting related result.