Sum of Sequence of Products of Consecutive Reciprocals/Corollary

Corollary to Sum of Sequence of Products of Consecutive Reciprocals

 * $\displaystyle \lim_{n \to \infty} \sum_{j \mathop = 1}^n \frac 1 {j \left({j+1}\right)} = 1$

Proof
From Sum of Sequence of Products of Consecutive Reciprocals:
 * $\displaystyle \lim_{n \to \infty} \sum_{j \mathop = 1}^n \frac 1 {j \left({j+1}\right)} = \frac n {n+1} = 1 - \frac 1 {n+1}$

We have that:
 * $\dfrac 1 {n+1} < \dfrac 1 n$

and that $\left \langle \dfrac 1 n \right \rangle$ is a basic null sequence.

Thus by the Squeeze Theorem:
 * $\displaystyle \lim_{n \to \infty} \sum_{j \mathop = 1}^n \frac 1 {j \left({j+1}\right)} = 1$