Floor of x+m over n/Corollary

Corollary to Floor of $\frac {x + m} n$
Let $n \in \Z$ such that $n > 0$.

Let $x \in \R$.

Then:
 * $\floor {\dfrac x n} = \floor {\dfrac {\floor x} n}$

where $\floor x$ denotes the floor of $x$.

Proof
This is a special case of Floor of $\dfrac {x + m} n$:
 * $\floor {\dfrac {x + m} n} = \floor {\dfrac {\floor x + m} n}$

where $m = 0$.