Sum of Sequence of Harmonic Numbers/Proof 2

Proof
From Sum over k to n of k Choose m by kth Harmonic Number:
 * $\displaystyle \sum_{k \mathop = 1}^n \binom k m H_k = \binom {n + 1} {m + 1} \left({H_{n + 1} - \frac 1 {m + 1} }\right)$

Setting $m = 0$: