Pointwise Addition on Continuous Real Functions forms Group

Theorem
Let $C$ be the set of all continuous real functions on the set of real numbers $\R$.

Let $f, g \in C$.

Let $f + g$ be the pointwise sum of $f$ and $g$:
 * $\forall x \in R: \map {\paren {f + g} } x = \map f x + \map g x$

Then $\struct {C, +}$, the algebraic structure on $C$ induced by $+$, forms a group.

Proof
Taking the group axioms in turn:

$\text G 0$: Closure
From the Sum Rule for Continuous Functions, if $f$ and $g$ are continuous real functions then so is $f + g$.

Thus closure is demonstrated.

$\text G 1$: Associativity
Pointwise Addition is Associative.

$\text G 2$: Identity
The constant function $f_0$ defined as:
 * $\forall x \in \R: \map {f_0} x = 0$

fulfils the role of the Identity:


 * $\forall x \in \R: \map {f_0} x + \map f x = 0 + \map f x = \map f x = \map f x + 0 = \map f x = \map {f_0} x$

Note that $f_0 \in C$ as the Constant Function is Uniformly Continuous, and hence continuous.

$\text G 3$: Inverses
From the Multiple Rule for Continuous Functions, if $\map f x$ is continuous then so is $\map g x$ where:
 * $\forall x \in \R: \map g x = -\map f x$.

Then we note that:
 * $\forall x \in \R: \map f x + \paren {-\map f x} = 0 = \paren {-\map f x} + \map f x$

So every element has an inverse.

All the group axioms are satisfied, hence the result.