Propositiones ad Acuendos Juvenes/Problems/24 - De Campo Triangulo

by : Problem $24$

 * De Campo Triangulo: A Triangular Field
 * A triangular field is $30$ perches along $2$ sides
 * and $18$ perches along the bottom.


 * How many acres must be enclosed?

Solution
Join the $2$ long sides and make $60$.

Half of $60$ is $30$.

Because the bottom is $18$, take half of this which is $9$.

$9$ times $30$ is $270$.

Divide $270$ by $12$ which makes $22 \tfrac 1 2$.

Again divide by $12$, giving $1$ acre and $12$ perches.