Talk:Gamma Function of One Half/Proof 2

Positive square root
This constraint follows from the definition of $ \Gamma $.


 * $ \forall z \in \R_{ \ge 0 }: \Gamma \left ( { z } \right ) > 0 $

because the integrand is positive, except, possibly, for $ t = 0 $.

Then, an integral of positive mapping is positive. --Julius (talk) 09:48, 12 June 2017 (EDT)


 * Good call. --prime mover (talk) 10:43, 12 June 2017 (EDT)