False Statement implies Every Statement/Formulation 1/Proof by Truth Table

Proof
We apply the Method of Truth Tables.

As can be seen by inspection, where the truth value in the relevant column on the is $\T$, that under the one on the  is also $\T$:

$\begin{array}{|cc||ccc|} \hline \neg & p & p & \implies & q \\ \hline \T & \F & \F & \T & \F \\ \T & \F & \F & \T & \T \\ \F & \F & \T & \F & \F \\ \F & \F & \T & \T & \T \\ \hline \end{array}$