Set Difference as Intersection with Complement

Theorem
Set difference can be expressed as the intersection with the set complement:


 * $A \setminus B = A \cap \complement \left({B}\right)$

Proof
This follows directly from Set Difference as Intersection with Relative Complement:
 * $A \setminus B = A \cap \complement_S \left({B}\right)$.

Let $S = \Bbb U$.

Since $A, B \in \Bbb U$ by the definition of the universe, the result follows.