Euler's Identity

Theorem

 * $$e^{i\pi}+1=0$$

Proo f
Falls directly from Euler's Formula $$e^{i\theta}=\cos\theta + i\sin\theta$$, by plugging in $$\theta=\pi$$.


 * $$e^{i\pi}+1 = \cos\pi + i\sin\pi + 1 = -1+i\times 0+1 =0$$