Projection from Product Topology is Continuous

Theorem
Let $T_1 = \left({A_1, \vartheta_1}\right)$ and $T_2 = \left({A_2, \vartheta_2}\right)$ be topological spaces.

Let $T = T_1 \times T_2$ be the topological product of $T_1$ and $T_2$.

Let $\operatorname{pr}_1: T \to T_1$ and $\operatorname{pr}_2: T \to T_2$ be the first and second projections from $T$ onto its factors.

Then both $\operatorname{pr}_1$ and $\operatorname{pr}_2$ are continuous.

Proof
If $U$ is open in $T_1$ then $\operatorname{pr}_1^{-1} \left({U}\right) = U \times T_2$ is one of the open sets in the basis in the definition of Product Topology.

Thus $\operatorname{pr}_1$ is continuous.

The same argument applies to $\operatorname{pr}_2$.