Convergent Sequence Minus Limit

Theorem
Let $X$ be one of the standard number fields $\Q, \R, \C$.

Let $\left \langle {x_n} \right \rangle$ be a sequence in $X$ which converges to $l$.

That is:
 * $\displaystyle \lim_{n \to \infty} x_n = l$

Then:
 * $\displaystyle \lim_{n \to \infty} \left|{x_n - l}\right| = 0$

Proof
Let $\epsilon > 0$.

We need to show that there exists $N$ such that:
 * $\forall n > N: \left|{\left({\left|{x_n - l}\right| - 0}\right)}\right| < \epsilon$

But:
 * $\left|{\left({\left|{x_n - l}\right| - 0}\right)}\right| = \left|{x_n - l}\right|$

So what needs to be proved is just $x_n \to l$ as $n \to \infty$, which is the definition of $\displaystyle \lim_{n \to \infty} x_n = l$.

Alternative Proof
We note that all of $\Q, \R, \C$ can be considered as metric spaces.

Then under the usual metric, $d \left({x_n, l}\right) = \left|{x_n - l}\right|$.

The result follows from the definition of metric: $d \left({x_n, l}\right) = 0 \iff x_n = l$.