17,796,126,877,482,329,126,052

Number
$17 \, 796 \, 126 \, 877 \, 482 \, 329 \, 126 \, 052$ is:


 * $2^2 \times 3 \times 149 \times 991 \, 723 \times 10 \, 036 \, 160 \, 394 \, 373$


 * The $9$th and last in a sequence of $9$ consecutive integers all of which have the same number of divisors:
 * $\tau \left({17 \, 796 \, 126 \, 877 \, 482 \, 329 \, 126 \, 052}\right) = 48$