Book:Tablet/YBC 4652/Examples

Example from Tablet YBC 4652

 * I found a stone, but did not weigh it. After I weighed out six times its weight, added $2$ gin and added one third of one seventh [of this new weight] multiplied by $24$, I weighed it. The result was $1$ ma-na. What was the original weight of the stone?

A weight of $1$ ma-na equals $60$ gin.

Solution
Let $x$ gin be the weight of the stone.

Then the word problem can be expressed in symbols as:
 * $\left({6 x + 2}\right) + \dfrac 1 3 \times \dfrac 1 7 \times 24 \left({6 x + 2}\right) = 60$

Algebraic manipulation reveals that $x = 4 \dfrac 1 3$.