Circle is Bisected by Diameter/Proof 1

Proof
Let $AB$ be a diameter of a circle $ADBE$ whose center is at $C$.

By definition of diameter, $AB$ passes through $C$.

that $AB$ does not bisect $ADBE$, but that $ADBC$ is larger than $AEBC$.


 * CircleBisectedByDiameter.png

Thus it will be possible to find a diameter $DE$ passing through $C$ such that $DC \ne CE$.

Both $DC$ and $CE$ are radii of $ADBE$.

By Euclid's definition of the circle:

That is, all radii of $ADBE$ are equal.

But $DC \ne CE$.

From this contradiction it follows that $AB$ bisects the circle.