Peirce's Law/Formulation 1

Theorem

 * $\left({p \implies q}\right) \implies p \vdash p$

Proof

 * align="right" | 4 ||
 * align="right" | 3
 * $p \implies q$
 * Sequent Introduction
 * 3
 * False Statement Implies Every Statement
 * False Statement Implies Every Statement