3403

Number
$3403$ (three thousand, four hundred and three) is:


 * $41 \times 83$


 * The $82$nd triangular number after $1$, $3$, $6$, $10$, $15$, $\ldots$, $2701$, $2775$, $2850$, $2926$, $3003$, $3081$, $3160$, $3240$, $3321$:
 * $3403 = \displaystyle \sum_{k \mathop = 1}^{82} k = \dfrac {82 \times \paren {82 + 1} } 2$