Sum of Sequence of Odd Squares/Formulation 1

Theorem

 * $\displaystyle \forall n \in \N: \sum_{i \mathop = 0}^n \left({2 i + 1}\right)^2 = \frac {\left({n + 1}\right) \left({2 n + 1}\right) \left({2 n + 3}\right)} 3$