Inversion Mapping Reverses Ordering in Ordered Group

Theorem
Let $(G,\circ, \le)$ be an ordered group.

Let $x, y \in G$.

Let $<$ be the reflexive reduction of $\le$.

Then the following equivalences hold:


 * $x \le y \iff y^{-1} \le x^{-1}$
 * $x < y \iff y^{-1} < x^{-1}$.

Proof
By the definition of an ordered group, $\le$ is a relation compatible with $\circ$.

Thus by User:Dfeuer/CRG3, we obtain the first result:


 * $x \le y \iff y^{-1} \le x^{-1}$

By Reflexive Reduction of Relation Compatible with Group Operation is Compatible, $<$ is compatible with $\circ$.

Thus by User:Dfeuer/CRG3, we obtain the second result:
 * $x < y \iff y^{-1} < x^{-1}$.