ProofWiki:Sandbox

User:JamesMazur2 (User_talk:JamesMazur2) 19:56, 10 March 2011 (CST)

$ \newcommand{\Re}{\mathrm{Re}\,}  \newcommand{\pFq}[5]{{}_{#1}\mathrm{F}_{#2} \left( \genfrac{}{}{0pt}{}{#3}{#4} \bigg| {#5} \right)}$We consider, for various values of $s$, the $n$-dimensional integral\begin{align}  \label{def:Wns}  W_n (s)  &:=   \int_{[0, 1]^n}     \left| \sum_{k = 1}^n \mathrm{e}^{2 \pi \mathrm{i} \, x_k} \right|^s \mathrm{d}\boldsymbol{x}\end{align}which occurs in the theory of uniform random walk integrals in the plane, where at each step a unit-step is taken in a random direction. As such, the integral \eqref{def:Wns} expresses the $s$-th moment of the distance to the origin after $n$ steps.By experimentation and some sketchy arguments we quickly conjectured and strongly believed that, for $k$ a nonnegative integer\begin{align} \label{eq:W3k}  W_3(k) &= \Re \, \pFq32{\frac12, -\frac k2, -\frac k2}{1, 1}{4}.\end{align}Appropriately defined, \eqref{eq:W3k} also holds for negative odd integers. The reason for \eqref{eq:W3k} was long a mystery, but it will be explained at the end of the paper.

How long do the "newcommands" survive?

Definition
Let $C\subseteq\mathbb C$ be some domain in the complex plane such that $z\!+\!1\in C \forall z \in C$

Let $D\subseteq\mathbb C$ be some domain in the complex plane.

Let $F: D\mapsto D$ be holomorphic function.

Let $H: C\mapsto D$ be holomorphic function.

Let $H(F(z))=F(z+1)$ for all $z\in C$.

Then $F$ is called superfunction of function $H$, and function $H$ is called transfer function of $F$.

Project of Definition:Tetration by Kouznetsov 07:33, 20 May 2011 (CDT)
Let $b\in \mathbb R$, $b \ge \exp(1/e)$

Let $L\in \mathbb C$ be fixed point of $\log_b$ such that $\Im(L) \ge 0$

Let $C = \mathbb C \backslash \{x \in \mathbb R : x\le -2 \}$

Let $\mathrm{tet}_b: C\mapsto \mathbb C$ be superfunction of $z\mapsto b^z$ such that
 * $\mathrm{tet}_b(0)=1$
 * $\mathrm{tet}_b(z^*)= \mathrm{tet}_b(z)^* \forall z \in C$
 * $\displaystyle \lim_{y\rightarrow +\infty} \mathrm{tet}_b(x+\mathrm i y)=L \forall x\in \mathbb R$

Then function $\mathrm {tet}_b$ is called tetration to base $b$.

Allowed??
P.S. I look at the update of Definition:Superfunction; as I understand, the only one source is allowed... Ok, let it be so.