Talk:Cubes which are Sum of Five Cubes

The page in Wells says just:
 * Since $6^3 = 3^3 + 4^3 + 5^3$, $9^3$ is also the sum of $5$ cubes.

The fact that this is not a particularly profound result, as in that all numbers greater than $8$ can be expressed as the sum of $5$ cubes (I hadn't noticed that fact myself when I wrote it), I'm not sure where to go with this page.

Any ideas? --prime mover (talk) 08:24, 8 August 2020 (UTC)