Non-Empty Set of Natural Numbers with no Greatest Element is Denumerable

Theorem
Let $A$ be a class of natural numbers.

Let $A$ have no greatest element.

Then $A$ is a denumerable class.

Proof
$A$ is finite.

From Subset of Naturals is Finite iff Bounded, it follows that $A$ is bounded.

Hence $A$ has a greatest element.

This contradicts the fact that $A$ has no greatest element.

Hence by Proof by Contradiction it follows that $A$ is not finite.

From Set of Natural Numbers is either Finite or Denumerable, $A$ is denumerable.