Regular Space with Sigma-Locally Finite Basis is Perfectly Normal Space

Theorem
Let $T = \struct {S, \tau}$ be a regular topological space.

Let $\BB$ be a $\sigma$-locally finite basis.

Then:
 * $T$ is a perfectly normal space

Proof
By definition of regular topological space:
 * $T$ is a $T_3$ space
 * $T$ is a $T_0$ (Kolmogorov) space

From User:Leigh.Samphier/Topology/T3 Space with Sigma-Locally Finite Basis is Perfectly T4 Space:
 * $T$ is a perfectly $T_4$ space

From Regular Space is $T_2$ Space:
 * $T$ is a $T_2$ space

From $T_2$ Space is $T_1$ Space:
 * $T$ is a $T_1$ space

By definition, $T$ is a perfectly normal space.