Cover of Doubletons of Infinite Particular Point Space has no Locally Finite Refinement

Theorem
Let $T = \left({S, \tau_p}\right)$ be an infinite particular point space.

Let $\mathcal C$ be the open cover of $T$ defined as:
 * $\mathcal C = \left\{{\left\{{x, p}\right\}: x \in S, x \ne p}\right\}$

Then $\mathcal C$ has no open refinement which is locally finite.

Proof
Suppose $T$ is an infinite particular point space.

As $S$ is infinite, $\mathcal C$ is also infinite.

Let $x \in S, x \ne p$.

Then any neighborhood of $x$ must contain $p$, by the nature of the particular point topology.

But $p$ is contained in all elements of $\mathcal C$.

That is:
 * $\forall C \in \mathcal C: p \in C$

So any neighborhood of $x$ intersects with all elements of the open cover $\mathcal C$.

As $\mathcal C$ is infinite, it therefore has no open refinement which is locally finite.