Square of Golden Mean equals One plus Golden Mean/Decimal Expansion

Decimal Expansion of Square of Golden Mean
The decimal expansion of $\phi^2$ is given as:
 * $\phi^2 \approx 2 \cdotp 61803 \, 39887 \, 49894$

Thus the square of the golden mean is the unique number $n$ such that:
 * $\sqrt n = n - 1$