Primitive of Reciprocal of x cubed by a x + b cubed

Theorem

 * $\displaystyle \int \frac {\mathrm d x} {x^3 \left({a x + b}\right)^3} = \frac {a^4 x^2} {2 b^5 \left({a x + b}\right)^2} - \frac {4 a^3 x} {b^5 \left({a x + b}\right)} - \frac {\left({a x + b}\right)^2} {2 b^5 x^2} + \frac {6 a^2} {b^5} \ln \left\vert{\frac x {a x + b} }\right\vert + C$