Rational Points on Graph of Exponential Function

Theorem
Consider the graph $f$ of the exponential function in the real Cartesian plane $\R^2$:
 * $f := \set {\tuple {x, y} \in \R^2: y = e^x}$

The only rational point of $f$ is $\tuple {0, 1}$.

Proof
From Exponential of Rational Number is Irrational:
 * $r \in \Q_{\ne 0} \implies e^r \in \R - \Q$

Thus, apart from the point $\tuple {0, 1}$, when $x$ is rational, $e^x$ is not.

Hence the result.