Restriction of Commutative Operation is Commutative

Theorem
Let $\left({S, \circ}\right)$ be an algebraic structure.

Let $T \subseteq S$.

Let the operation $\circ$ be commutative on $\left({S, \circ}\right)$.

Then it is also commutative on the restriction $\left({T, \circ \! \restriction_T}\right)$.