Linear Second Order ODE/y'' - 5 y' + 6 y = 0

Theorem
The linear second order ODE:
 * $(1): \quad y'' - 5 y' + 6 y = 0$

has the general solution:
 * $y = C_1 e^{2 x} + C_2 e^{3 x}$

Proof
It can be seen that $(1)$ is a constant coefficient homogeneous linear second order ODE.

Its auxiliary equation is:
 * $(2): \quad: m^2 - 5 m + 6 = 0$

From Solution to Quadratic Equation: Real Coefficients, the roots of $(2)$ are:
 * $m_1 = 2$
 * $m_2 = 3$

These are real and unequal.

So from Solution of Constant Coefficient Homogeneous LSOODE, the general solution of $(1)$ is:
 * $y = C_1 e^{2 x} + C_2 e^{3 x}$