Element of Integral Domain Divides Zero

Theorem
Let $\struct {D, +, \circ}$ be an integral domain whose zero is $0_D$.

Then every element of $D$ divides $0_D$:
 * $\forall x \in D: x \divides 0_D$

Proof
By definition, an integral domain is a ring.

So, from Ring Product with Zero:
 * $\forall x \in D: 0_D = x \circ 0_D$

The result follows from the definition of divisor.