Sine in terms of Tangent

Theorem
Let $\theta$ be an angle such that $\cos \theta \ne 0$.

Then:


 * $\sin \theta = \pm \dfrac {\tan \theta} { \sqrt{1 + \tan ^2 \theta} }$

where $\sin$ denotes the sine function and $\tan$ denotes the tangent function.

Also see

 * Trigonometric Functions in terms of each other