User:1is0?

Proof: $1 = 0$
Let $x = 0$. Then,


 * $\displaystyle \frac{x}{x} = \frac{0}{x}$


 * $\displaystyle 1 = 0 \left({?}\right)$

Proof: $f \left({-x}\right) = f \left({x}\right) \implies f' \left({-x}\right) = -f' \left({x}\right)$ (valid this time)

 * $\displaystyle \dfrac{\ \mathrm d {f \left({-x})\right)}}{\ \mathrm d x} = \dfrac{\ \mathrm d {f \left({x}\right)}}{\ \mathrm d x}$
 * $\displaystyle f' \left({-x}\right) = -f' \left({x}\right)$

I think you might want to explain that a little better. The notation is confusing at best. It may help to introduce an auxiliary function $g(x) = f(-x)$. --Dfeuer (talk) 18:19, 4 May 2013 (UTC)