Brahmagupta's Formula/Corollary

Corollary to Brahmagupta's Formula
The area of a cyclic quadrilateral with sides of lengths $a, b, c, d$ is:


 * $\dfrac {\sqrt {\paren {a^2 + b^2 + c^2 + d^2}^2 + 8 a b c d - 2 \paren {a^4 + b^4 + c^4 + d^4} } } 4$

Proof
Brahmagupta's Formula:


 * $\AA = \sqrt {\paren {s - a} \paren {s - b} \paren {s - c} \paren {s - d} }$

where $s$ is the semiperimeter:


 * $s = \dfrac {a + b + c + d} 2$

Making the substitutions:

results in:
 * $\AA = \dfrac {\sqrt {\paren {a^2 + b^2 + c^2 + d^2}^2 + 8 a b c d - 2 \paren {a^4 + b^4 + c^4 + d^4} } } 4$