Primitive of Power of x over x cubed plus a cubed

Theorem

 * $\displaystyle \int \frac {x^m \rd x} {x^3 + a^3} = \frac {x^{m - 2} } {m - 2} - a^3 \int \frac {x^{m - 3} \rd x} {x^3 + a^3}$