Limit Point of Subset is Limit Point of Set

Theorem
Let $T = \left({S, \tau}\right)$ be a topological space.

Let $A, B$ be subset of $S$ such that
 * $A \subseteq B$

Let $x$ be a point of $S$.

Then:
 * if $x$ is limit point of $A$, then $x$ is limit point of $B$.

Proof
Assume $x$ is limit point of $A$.

By definition of limit point it suffices to prove
 * $\forall U \in \tau: x \in U \implies B \cap \left({U \setminus \left\{{x}\right\}}\right) \ne \varnothing$

Let $U \in \tau$ such that
 * $x \in U$

By definition of limit point:
 * $A \cap \left({U \setminus \left\{{x}\right\}}\right) \ne \varnothing$

By Set Intersection Preserves Subsets/Corollary:
 * $A \cap \left({U \setminus \left\{{x}\right\}}\right) \subseteq B \cap \left({U \setminus \left\{{x}\right\}}\right)$

Thus:
 * $B \cap \left({U \setminus \left\{{x}\right\}}\right) \ne \varnothing$