Exponential Function is Continuous/Real Numbers/Proof 1

Proof
This proof depends on the limit definition of the exponential function.

Let:
 * $\ds \map \exp x = \lim_{n \mathop \to \infty} \paren {1 + \dfrac x n}^n$

Fix $x_0 \in \R$.

Consider $I := \closedint {x_0 - 1} {x_0 + 1}$.

From Closed Bounded Subset of Real Numbers is Compact, $I$ is compact.

From Exponential Sequence is Uniformly Convergent on Compact Sets:
 * $\paren {1 + \dfrac x n}^n$ is uniformly convergent on $I$.

By the Uniform Limit Theorem:
 * $\ds \lim_{n \mathop \to \infty} \paren {1 + \dfrac x n}^n = \exp$

is continuous on $I$.

In particular, $\map \exp x$ is continuous at $x_0$.