Talk:Product Form of Sum on Completely Multiplicative Function

It occurs to me that this is only valid if the sum inside the product is absolutely convergent. Needs more work to make it rigorous. --Matt Westwood 05:31, 17 April 2009 (UTC)

... there, I think I've covered it. --Matt Westwood 07:14, 17 April 2009 (UTC)


 * Still some convergence issues I think...


 * Take it away, then, maestro ... --prime mover 13:49, 2 March 2011 (CST)


 * My mistake; forgot that $f$ is multiplicative, so $|f(p)| < 1 \implies$ abs. convergence --Linus44 19:33, 2 March 2011 (CST)