Derivative Operator on Continuously Differentiable Function Space with C^1 Norm is Continuous

Theorem
Let $I = \closedint 0 1$ be a closed real interval.

Let $\map C I$ be the real-valued, continuous on $I$ function space.

Let $\map {C^1} I$ be the continuously differentiable function space.

Let $x \in \map {C^1} I$ be a continuoulsly differentiable real-valued function.

Let $D : \map {C^1} I \to \map \CC I$ be the derivative operator such that:


 * $\forall t \in \closedint 0 1 : \map {D x} t := \map {x'} t$

Suppose $\map C I$ and $\map {C^1} I$ are equipped with $C^0$ and $C^1$ norms respectively

Then $D$ is continuous.

Proof
We have that the Derivative Operator is Linear Mapping.

By definition and Continuity of Linear Transformation between Normed Vector Spaces, $D$ is continuous.