Rule of Exportation/Reverse Implication/Formulation 1/Proof

Theorem

 * $p \implies \left ({q \implies r}\right) \vdash \left ({p \land q}\right) \implies r$

Proof

 * align="right" | 7 ||
 * align="right" | 1
 * $\left ({p \land q}\right) \implies r$
 * $\implies \mathcal I$
 * 2 - 6
 * 2 - 6