Divisors of One More than Power of 10/Number of Zero Digits Congruent to 2 Modulo 3/Examples/101 Zero Digits

Proof
$101$ is of the form $3 \times k - 1$ where $k = 34$.

The result follows directly from Divisors of One More than Power of 10: Number of Zero Digits Congruent to 2 Modulo 3.

Also see

 * Henry Ernest Dudeney: Modern Puzzles: $62$ -- Factorizing