Lucas Number as Sum of Fibonacci Numbers

Theorem
Let $L_k$ be the $k$th Lucas number, defined as:


 * $L_n = \begin{cases}

2 & : n = 0 \\ 1 & : n = 1 \\ L_{n - 1} + L_{n - 2} & : \text{otherwise} \end{cases}$

Then:
 * $L_n = F_{n - 1} + F_{n + 1}$

where $F_k$ is the $k$th Fibonacci number.

Proof
Proof by induction:

For all $n \in \N_{>0}$, let $\map P n$ be the proposition:
 * $L_n = F_{n - 1} + F_{n + 1}$

Basis for the Induction
$\map P 1$ is true, as this just says:
 * $L_1 = 1 = F_0 + F_2$

which holds by definition of the Fibonacci numbers.

This is our basis for the induction.

Induction Hypothesis
Let us make the supposition that, for some $k \in \N: k \ge 1$, the proposition $\map P j$ holds for all $j \in \N: 1 \le j \le k$.

We shall show that it logically follows that $\map P {k + 1}$ is true.

So this is our induction hypothesis:
 * $L_j = F_{j - 1} + F_{j + 1}$

Then we need to show:
 * $L_{k + 1} = F_k + F_{k + 2}$

Induction Step
This is our induction step:

So $\map P {k + 1}$ and the result follows by the Second Principle of Mathematical Induction.

Therefore:
 * $\forall n \in \N, n \ge 1: L_n = F_{n - 1} + F_{n + 1}$