Talk:Fermat's Two Squares Theorem/Uniqueness Lemma

Fri, 15 Sep 2023 19:55:13 User:Usagiop added a 3rd proof derived from the 1st one. Must choose one of both!


 * Yes, as I asked there, I cannot see how you derive:
 * $\dfrac{d^2}{b^2}=\dfrac{c^2+d^2}{a^2+b^2}$
 * Can you please explain this, first?
 * Sure, we can discuss about deleting Proof 3, after you improved your Proof 1. --Usagiop (talk) 20:09, 15 September 2023 (UTC)


 * I don't see why we need both Proof 1 and Proof 3 considering they are the same. --prime mover (talk) 20:21, 15 September 2023 (UTC)


 * Yes, if they are the same, then delete Proof 3. It was not clear how User:Fabo34 wanted to finish his last argument, which I am still looking forward to know. By the way, I changed my last argument, because User:Fabo34 said that was the same as his idea. Now, it should be different. --Usagiop (talk) 20:38, 15 September 2023 (UTC)


 * i done the tidying an justification linx, left an explain template --prime mover (talk) 20:50, 15 September 2023 (UTC)
 * Thanks, I also changed the first part of my proof. --Usagiop (talk) 21:18, 15 September 2023 (UTC)
 * it is a basic numerical fact when writting if $\dfrac{u}{v}=\dfrac{r}{s}$ then $\dfrac{u}{v}=\dfrac{r}{s}=\dfrac{u+r}{v+s}$. It is always true. I am not sure it's worth detailing this. But If you think it is, then feel free to add that. I am new on this site and I don't know the required level of precision. fabo34 16 Sep 2023 06:41:25 (UTC)


 * Indeed? Your mission, Jim, should you choose to accept it, is to prove it. This tape will self-destruct in 5 seconds. Good luck, Jim. --prime mover (talk) 08:07, 16 September 2023 (UTC)