User:Guy vandegrift/sandbox

$\map {\log_a} {b^y}$

Alternative proof
Let:
 * $b^y=a^z$

Solve for one of the bases:
 * $b=a^{z/y}$

Take the logarithm of both sides. You can use either base:
 * Base $a$ yields:
 * $\log_a(b)=\log_a\left(a^{z/y}\right)$


 * Base $b$ yields:
 * $\log_b(b)=\log_b\left(a^{z/y}\right)$

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 * Special:Permalink/551517 What is physics joke (failed to parse)
 * Special:Permalink/551563 Talk:Change of Base of Logarithm