Row in Pascal's Triangle forms Palindromic Sequence

Theorem
Each of the rows of Pascal's triangle forms a palindromic sequence.

Proof
The $n$th row of Pascal's triangle consists of the finite sequence:
 * $\dbinom n 0, \dbinom n 1, \dbinom n 2, \ldots, \dbinom n {n - 2}, \dbinom n {n - 1}, \dbinom n n$

By the Symmetry Rule for Binomial Coefficients:


 * $\dbinom n m = \dbinom n {n - m}$

Hence we can write the $n$th row in reverse order:

and the sequences are seen to be the same.