Sine of Full Angle

Theorem

 * $\sin 360^\circ = \sin 2 \pi = 0$

where $\sin$ denotes the sine function and $360^\circ = 2 \pi$ is the full angle.

Proof
A direct implementation of Sine of Multiple of Pi:
 * $\forall n \in \Z: \sin n \pi = 0$

In this case, $n = 2$ and so:
 * $\sin 2 \pi = 0$