Perimeter of Parallelogram

Theorem
Let $ABCD$ be a parallelogram whose side lengths are $a$ and $b$.

The perimeter of $ABCD$ is $2 a + 2 b$.

Proof

 * PerimeterOfParallelogram.png

By Opposite Sides and Angles of Parallelogram are Equal it follows that:
 * $AB = CD$
 * $BC = AD$

The perimeter of $ABCD$ is $AB + BC + CD + AD$.

But $AB = CD = a$ and $BC = AD = b$.

Hence the result.