Composition of Functors is Associative

Theorem
Let $\mathbf A$, $\mathbf B$, $\mathbf C$ and $\mathbf D$ be metacategories.

Let $F: \mathbf A \to \mathbf B$, $G: \mathbf B \to \mathbf C$ and $H: \mathbf C \to \mathbf D$ be functors.

Composition of functors is associative:


 * $H \left({GF}\right) = \left({HG}\right) F$

Proof
Let $A$ be an object of $\mathbf A$.

Then, solely by the definition of composite functor:

Mutatis mutandis, the same proof works for a morphism $f$ of $\mathbf A$ as well.

Hence the result.