Power Set is Algebra of Sets

Theorem
Let $S$ be a set.

Let $\mathcal P \left({S}\right)$ be the power set of $S$.

Then $\mathcal P \left({S}\right)$ is an algebra of sets where $S$ is the unit.

Proof
From Power Set Closed under Intersection and Power Set Closed under Symmetric Difference, we have that:


 * $(1): \quad \forall A, B \in \mathcal P \left({S}\right): A \cap B \in \mathcal P \left({S}\right)$
 * $(2): \quad \forall A, B \in \mathcal P \left({S}\right): A * B \in \mathcal P \left({S}\right)$

From the definition of power set:
 * $\forall A \in \mathcal P \left({S}\right): A \subseteq S$

and so $S$ is the unit of $\mathcal P \left({S}\right)$.

Thus we see that $\mathcal P \left({S}\right)$ is a ring of sets with a unit.

Hence the result, from definition 2 of an algebra of sets.