Limit of (Cosine (X) - 1) over X at Zero/Proof 2

Proof
This proof assumes the truth of the Derivative of Cosine Function:

From Cosine of Zero is One:
 * $\cos 0 = 1$

From Derivative of Cosine Function:
 * $D_x \left({\cos x}\right) = - \sin x$

and by Derivative of Constant:
 * $D_x \left({-1}\right) = 0$

So by Sum Rule for Derivatives:
 * $D_x \left({\cos x - 1}\right) = - \sin x$

By Sine of Zero is Zero:
 * $\sin 0 = 0$

From Derivative of Identity Function:
 * $D_x \left({x}\right) = 1$

Thus L'Hôpital's Rule applies and so:
 * $\displaystyle \lim_{x \mathop \to 0} \frac {\cos x - 1} x = \lim_{x \mathop \to 0} \frac {-\sin x} 1 = \frac {-0} 1 = 0$