Closure of Rational Numbers is Real Numbers

Theorem
Let $\struct {\R, \tau_d}$ be the real numbers under the usual (Euclidean) topology.

Let $\struct {\Q, \tau_d}$ be the rational number space under the same topology.

Then:
 * $\Q^- = \R$

where $\Q^-$ denotes the closure of $\Q$.

Proof
From Rationals are Everywhere Dense in Reals, $\Q$ is everywhere dense in $\R$.

It follows by definition of everywhere dense that $\Q^- = \R$.