Cosets are Equivalent

Theorem
All left cosets of a group $G$ with respect to a subgroup $H$ are equivalent.

That is, any two left cosets are in one-to-one correspondence.

The same applies to right cosets.

As a special case of this:
 * $\forall x \in G: \left|{x H}\right| = \left|{H}\right| = \left|{H x}\right|$

where $H$ is a subgroup of $G$.

Proof
Let us set up mappings $\theta: H \to H x$ and $\phi: H x \to H$ as follows:
 * $\forall u \in H: \theta \left({u}\right) = u x$
 * $\forall v \in H x: \phi \left({v}\right) = v x^{-1}$

Note that $v \in H x \implies v x^{-1} \in H$ from Elements in Coset iff Product with Inverse in Coset.

Now:
 * $\forall v \in H x: \theta \circ \phi \left({v}\right) = v x^{-1} x = v$
 * $\forall u \in H: \phi \circ \theta \left({u}\right) = u x x^{-1} = u$

Thus $\theta \circ \phi = I_{Hx}$ and $\phi \circ \theta = I_H$.

So $\theta = \phi^{-1}$: both are bijections and one is the inverse of the other.

Hence the result.

Alternatively, it follows directly from Set Equivalence of Regular Representations.