User talk:Aitzaz Imtiaz

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Cheers! prime mover (talk) 19:07, 15 October 2022 (UTC)

ax^-1 + bx + c = 0
Would you like to present your formula? --Usagiop (talk) 13:08, 26 October 2022 (UTC)
 * Ofcourse, my pleasures, if you have any equation in the form of $ax^{-1}+bx+c=0$ then $x=\frac{-c \pm \sqrt{c^2-4ab}}{2b}$ and for x to be a real value $c \geq b^2-4ac$ --Aitzaz Imtiaz (talk) 14:17, 26 October 2022 (UTC)
 * same as the Quadratic Formula then --prime mover (talk) 14:20, 26 October 2022 (UTC)
 * Somehow :) --Aitzaz Imtiaz (talk) 14:21, 26 October 2022 (UTC)
 * What is new then? --Usagiop (talk) 18:22, 26 October 2022 (UTC)
 * The difference is the condition $c \geq b^2-4ac$ but is this correct? The condition for x to be a real value is $c^2-4ab \ge 0$, isn't it? --Usagiop (talk) 21:04, 26 October 2022 (UTC)


 * Yea, sorry, thats a mistake, of course that is the correct way. --Aitzaz Imtiaz (talk) 00:41, 27 October 2022 (UTC)