Talk:Ordering on Natural Numbers is Compatible with Multiplication

@PM: I'm sorry, but you can't seriously think that $\N_{\ne0}$ is aesthetically preferable over $\N_{>0}$. However, so as to avoid an editing battle, I have refrained from changing it (since last time I did so, you made the notation evolve even further (not a bad thing there)). --Lord_Farin 13:45, 17 January 2012 (EST)
 * It makes little difference. The only reason $\N_{\ne0}$ might be preferable is that when you consider $\N$ as the good old minimal infinite successor set, the $>$ symbol may have to be defined. However, in this case we have already defined $>$ so no worries. I think I was just being over fussily careful. --prime mover 15:57, 17 January 2012 (EST)
 * Still, in that case I would prefer $\N\setminus\{0\}$ despite it being longer to put in. Thanks for response. --Lord_Farin 16:21, 17 January 2012 (EST)
 * Makes sense - then there's no danger of circularism. --prime mover 16:40, 17 January 2012 (EST)