Identity Functor is Right Identity

Theorem
Let $\mathbf C$ and $\mathbf D$ be metacategories.

Let $F: \mathbf C \to \mathbf D$ be a functor, and let $1_{\mathbf C}$ be the identity functor on $\mathbf C$.

Then the composite functor $F 1_{\mathbf C}$ satisfies:


 * $F 1_{\mathbf C} = F$

Proof
We have, for all objects $C$ of $\mathbf C$:


 * $F 1_{\mathbf C} C = F \left({1_{\mathbf C} C}\right) = F C$

by definition of composition of functors and of identity functor.

Similarly, we have, for a morphism $f$ of $\mathbf C$:


 * $F 1_{\mathbf C} f = F \left({1_{\mathbf C} f}\right) = F f$

Hence the result.