Derivative of Inverse Hyperbolic Sine Function

Theorem
Let $u$ be a differentiable real function of $x$.

Then:
 * $\map {\dfrac \d {\d x} } {\arsinh u} = \dfrac 1 {\sqrt {1 + u^2} } \dfrac {\d u} {\d x}$

where $\sinh^{-1}$ is the inverse hyperbolic sine.

Also see

 * Derivative of Real Area Hyperbolic Cosine of Function


 * Derivative of Inverse Hyperbolic Tangent Function
 * Derivative of Inverse Hyperbolic Cotangent Function


 * Derivative of Inverse Hyperbolic Secant Function
 * Derivative of Inverse Hyperbolic Cosecant Function