Biconditional Equivalent to Biconditional of Negations/Formulation 1

Theorem

 * $p \iff q \dashv \vdash \neg p \iff \neg q$

This can be expressed as two separate theorems:

Proof
We apply the Method of Truth Tables.

As can be seen by inspection, in all cases the truth values under the main connectives match for all models.

$\begin{array}{|ccc||ccccc|} \hline p & \iff & q & \neg & p & \iff & \neg & q \\ \hline F & T & F & T & F & T & T & F \\ F & F & T & T & F & F & F & T \\ T & F & F & F & T & F & T & F \\ T & T & T & F & T & T & F & T \\ \hline \end{array}$