Algebra from Cayley-Dickson Construction Never Real

Theorem
Let $A$ be a $*$-algebra.

Let $A'$ be constructed from $A$ using the Cayley-Dickson construction.

Then $A'$ is not a real algebra.

Proof
Let the conjugation operator on $A$ be $*$.

$A'$ is a real algebra whose conjugation operator is $*'$.

Then by definition:
 * $\forall a \in A': {a^*}' = a$

Let $a = \tuple {x, y} \in A'$.

Then by definition of the Cayley-Dickson construction:
 * $x, y \in A$

By definition of the conjugation operator:
 * ${\tuple {x, y}^*}' = \tuple {x^*, -y}$

So for ${a^*}' = a$ it must be that $x = x^*$ and $y = -y$ from definition of Equality of Ordered Pairs.

That is, $y = 0$.

But $A'$ is a $*$-algebra, which is by definition a unitary division algebra.

So $\exists y \in A: y = 1 \ne 0$.

From that contradiction, it follows that $A'$ can not be a real algebra.