Subspace of Either-Or Space less Zero is not Lindelöf

Theorem
Let $T = \left({S, \tau}\right)$ be the either-or space.

Let $H = S \setminus \left\{{0}\right\}$ be the set $S$ without zero.

Then the topological subspace $T_H = \left({H, \tau_H}\right)$ is not a Lindelöf space.

Proof
By definition of topological subspace, $U \subseteq H$ is open in $T_H$ iff:
 * $(1): \quad \left\{{0}\right\} \nsubseteq U$

or:
 * $(2): \quad \left({-1 \,.\,.\, 1}\right) \subseteq U$

But for all $U \subseteq H$, condition $(1)$ holds as $0 \notin H$.

So $T_H$ is by definition a discrete space.

As $T_H$ is uncountable, we have that Uncountable Discrete Space is not Lindelöf holds.

Hence the result.