Rule of Exportation/Forward Implication/Formulation 1/Proof

Theorem

 * $\left ({p \land q}\right) \implies r \vdash p \implies \left ({q \implies r}\right)$

Proof

 * align="right" | 6 ||
 * align="right" | 1, 2
 * $q \implies r$
 * $\implies \mathcal I$
 * 3 - 5
 * align="right" | 7 ||
 * align="right" | 1
 * $p \implies \left ({q \implies r}\right)$
 * $\implies \mathcal I$
 * 2 - 6
 * $p \implies \left ({q \implies r}\right)$
 * $\implies \mathcal I$
 * 2 - 6