Product of Two Distinct Primes has 4 Positive Divisors

Theorem
Let $n \in \Z_{>0}$ be a positive integer which is the product of $2$ distinct primes.

Then $n$ has exactly $4$ positive divisors.

Proof
Let $n = p \times q$ where $p$ and $q$ are primes.

We have by definition of divisor:

where $\backslash$ denotes divisibility.

Suppose $a \mathrel \backslash n$ such that $1 \le a < n$.

Suppose $a \ne p$.

By definition of prime number:
 * $a \perp p$

where $\perp$ denotes coprimality.

From Euclid's Lemma:
 * $a \mathrel \backslash q$

and so by definition of prime number:
 * $a = q$

or:
 * $a = 1$

Similarly, suppose $a \ne q$.

By the same reasoning:
 * $a = p$

or:
 * $a = 1$

Thus the only positive divisors are as above.