Inverse of Composition of Subsets of Topological Group

Theorem
Let $\struct {G, \odot, \tau}$ be a topological group.

Let $A, B \subseteq G$.

Then:


 * $\paren {A \odot B}^{-1} = B^{-1} \odot A^{-1}$

Proof
The proof is identical to Inverse of Product of Subsets of Group.