Primitive of Root of a x + b over x

Theorem

 * $\displaystyle \int \frac {\sqrt{a x + b} } x \ \mathrm d x = 2 \sqrt{a x + b} + b \int \frac {\mathrm d x} {x \sqrt{a x + b} }$

Also see

 * Primitive of Reciprocal of $x \sqrt{a x + b}$ for $\displaystyle \int \frac {\mathrm d x} {x \sqrt{a x + b} }$