Magic Constant of Order 5 Magic Square/Proof 1

Proof
Let $M_5$ denote an order $4$ magic square

By Sum of Terms of Magic Square, the total of all the entries in $M_5$ is given by:
 * $T_5 = \dfrac {5^2 \left({5^2 + 1}\right)} 2 = \dfrac {25 \times 26} 2 = 325$

As there are $5$ rows of $M_5$, the magic constant of $M_5$ is given by:
 * $S_5 = \dfrac {325} 5 = 65$