Equation of Straight Line Tangent to Circle

Theorem
Let $\tuple {a, b}$ be the center of a circle $\CC$.

Let $P_n = \tuple {x_n, y_n}$ be any point on $\CC$.

The equation of a non-vertical tangent line $\TT$ to $\CC$ is given by:


 * $y - y_n = \dfrac {a - x_n} {y_n - b} \paren {x - x_n}$

The equations of the vertical tangent lines to $\CC$ are:
 * $x = r - a$ for $P = \tuple {r - a, b}$
 * $x = a - r$ for $P = \tuple {a - r, b}$

Non-Vertical Tangent Lines
From Equation of Circle, $\CC$ can be described on the $x y$-plane in the form:


 * $\paren {x - a}^2 + \paren {y - b}^2 = r^2$

where $P = \tuple {a, b}$ is the center of the circle and $r$ is the radius.

We use the definition of the derivative as the gradient of the tangent line $\TT$.

Taking the derivative $x$ of both sides of the equation we get:

This is the slope at any point on $\CC$.

From the slope-intercept form of a line, the equation of such a line is:
 * $y - y_n = m \paren {x - x_n}$

given any point $\paren {x_n, y_n}$ and the gradient $m$.

For $\TT$:


 * $m = \valueat {\dfrac {\d y} {\d x} } {x \mathop = x_n, y \mathop = y_n}$

Thus the equation of $\TT$ is:


 * $y - y_n = \dfrac {a - x_n} {y_n - b} \paren {x - x_n}$