Linear Second Order ODE/y'' + 2 y' + 2 y = 0

Theorem
The second order ODE:
 * $(1): \quad y'' + 2 y' + 2 y = 0$

has the general solution:
 * $y = e^{-x} \paren {A \cos x + B \sin x}$

Proof
It can be seen that $(1)$ is a constant coefficient homogeneous linear second order ODE.

Its auxiliary equation is:
 * $(2): \quad: m^2 + 2 m + 2 = 0$

From Solution to Quadratic Equation: Real Coefficients, the roots of $(2)$ are:
 * $m_1 = -1 + i$
 * $m_2 = -1 - i$

These are complex conjugates.

So from Solution of Constant Coefficient Homogeneous LSOODE, the general solution of $(1)$ is:
 * $y = e^{-x} \paren {A \cos x + B \sin x}$