Coset Product is Well-Defined/Proof 1

Proof
Let $N \lhd G$ where $G$ is a group.

Let $a, a', b, b' \in G$ such that:
 * $a \circ N = a' \circ N$

and:
 * $b \circ N = b' \circ N$

To show that the coset product is well-defined, we need to demonstrate that:
 * $\paren {a \circ b} \circ N = \paren {a' \circ b'} \circ N$

So:

By Cosets are Equal iff Product with Inverse in Subgroup:
 * $\paren {a \circ b}^{-1} \circ \paren {a' \circ b'} \in N \implies \paren {a \circ b} \circ N = \paren {a' \circ b'} \circ N$

and the proof is complete.