Linear Second Order ODE/y'' - 7 y' - 5 y = 0

Theorem
The second order ODE:
 * $(1): \quad y'' - 7 y' - 5 y = 0$

has the general solution:
 * $y = C_1 \, \map \exp {\paren {\dfrac 7 2 + \dfrac {\sqrt {69} } 2} x} + C_2 \, \map \exp {\paren {\dfrac 7 2 - \dfrac {\sqrt {69} } 2} x}$

Proof
It can be seen that $(1)$ is a constant coefficient homogeneous linear second order ODE.

Its auxiliary equation is:
 * $(2): \quad: m^2 - 7 m - 5 = 0$

From Solution to Quadratic Equation: Real Coefficients, the roots of $(2)$ are:

{{eqn | r = \dfrac 7 2 \pm \dfrac {\sqrt {69} 2 | c = }}

These are real and unequal.

So from Solution of Constant Coefficient Homogeneous LSOODE, the general solution of $(1)$ is:
 * $y = C_1 \, \map \exp {\paren {\dfrac 7 2 + \dfrac {\sqrt {69} } 2} x} + C_2 \, \map \exp {\paren {\dfrac 7 2 - \dfrac {\sqrt {69} } 2} x}$