Talk:Absolutely Continuous Real Function is Uniformly Continuous

I don't quite know what I was doing either. Give me a second to re-work it... Caliburn (talk) 20:01, 8 June 2022 (UTC)
 * All good now? It's just a matter of symbols in the end. I think the problem is that I didn't specify $y < x$? Caliburn (talk) 20:08, 8 June 2022 (UTC)
 * Yes, no longer wrong. A minor remark: Probably you wanted to say:
 * $0 \le y - x < \delta \implies \size {\map f y - \map f x} < \epsilon$ ($b_1=y, a_1=x$)
 * $0 < x - y < \delta \implies \size {\map f x - \map f y} < \epsilon$ ($b_1=x, a_1=y$)
 * It is opposite in your exposition.--Usagiop (talk) 20:24, 8 June 2022 (UTC)
 * Good catch. Caliburn (talk) 20:26, 8 June 2022 (UTC)