Talk:Strictly Positive Real Numbers under Multiplication form Uncountable Abelian Group

Just asserting that $ab > 0$ feels non-rigorous. Isn't that essentially what we're trying to prove here? --Alec (talk) 02:15, 11 May 2011 (CDT)


 * I think Real Numbers form Totally Ordered Field and $(2)$ of Definition:Ordering Compatible with Ring would cover it --Linus44 03:33, 11 May 2011 (CDT)


 * We already know that $\R$ is a field, and therefore a ring, and so from one of the results in there we know that + times + equals +.


 * The point to this result is to demonstrate that the positive numbers form a group. The behaviour of real number arithmetic is taken for granted. The point is the closure of the + numbers under multiplication. --prime mover 14:23, 11 May 2011 (CDT)
 * ... but I've added a crucial couple of results that justify it. Good call. --prime mover 14:29, 11 May 2011 (CDT)