Talk:Absolute Value Equals Square Root of Square

My thoughts
In my opinion the best way, and most conventional/useful, to approach this would be to define $|x| := \sqrt{x^2}$ over the reals, rather than having this as a theorem. (even given a "good definition", this theorem would probably be trivial) Caliburn (talk) 13:05, 17 November 2017 (EST)
 * Until recently it was a definition. But the square root is too deep a notion to use it to define absolute value. See Definition talk:Absolute Value/Real Number --barto (talk) (contribs) 13:53, 17 November 2017 (EST)