Palindromes Formed by Multiplying by 55

Theorem
$55$ multiplied by any of the odd integers between $91$ and $109$ inclusive produces a palindromic number.

Proof
We have that:
 * $55 \times 91 = 5005$

Then we have that:
 * $55 \times 2 = 110$

Thus:
 * $\forall k: 1 \le k \le 9: 55 \times 2 k = 110k = 110, 220, 330, \ldots, 990$

Thus for $1 \le k \le 9$:
 * $55 \times \left({91 + 2 k}\right) = \left[{5kk5}\right]_{10}$

That is: