Rule of Distribution/Conjunction Distributes over Disjunction/Right Distributive/Formulation 2

Theorem
The conjunction operator is right distributive over the disjunction operator:
 * $\vdash \paren {\paren {q \lor r} \land p} \iff \paren {\paren {q \land p} \lor \paren {r \land p} }$

Proof
{{qed}