Sum of Infinite Geometric Sequence/Proof 1

Proof
From Sum of Geometric Sequence, we have:
 * $\ds s_N = \sum_{n \mathop = 0}^N z^n = \frac {1 - z^{N + 1} } {1 - z}$

We have that $\size z < 1$.

So by Sequence of Powers of Number less than One:
 * $z^{N + 1} \to 0$ as $N \to \infty$

Hence $s_N \to \dfrac 1 {1 - z}$ as $N \to \infty$.

The result follows.

It remains to demonstrate absolute convergence:

The absolute value of $\size z$ is just $\size z$.

By assumption:
 * $\size z < 1$

So $\size z$ fulfils the same condition for convergence as $z$.

Hence:
 * $\ds \sum_{n \mathop = 0}^\infty \size z^n = \frac 1 {1 - \size z}$