Integer Divisor is Equivalent to Subset of Ideal

Theorem
Let $\Z$ be the set of all integers.

Let $\Z_{>0}$ be the set of strictly positive integers.

Let $m \in \Z_{>0}$ and let $n \in \Z$.

Let $\ideal m$ be the principal ideal of $\Z$ generated by $m$.

Then:
 * $m \divides n \iff \ideal n \subseteq \ideal m$

Proof
The ring of integers is a principal ideal domain.

The result follows directly from Principal Ideals in Integral Domain.