Double Negation Elimination implies Law of Excluded Middle

Theorem
Let the Law of Double Negation Elimination be supposed to hold:
 * $\neg \neg p \vdash p$

Then the Law of the Excluded Middle likewise holds:
 * $\vdash p \lor \neg p$

Proof

 * align="right" | 8 ||
 * align="right" |
 * $\neg \neg \left({p \lor \neg p}\right)$
 * $\neg \mathcal I$
 * 1, 7
 * align="right" | 9 ||
 * align="right" |
 * $p \lor \neg p$
 * $\neg \neg \mathcal E$
 * 8
 * $p \lor \neg p$
 * $\neg \neg \mathcal E$
 * 8

Comment
Thus the Law of Double Negation Elimination may be taken as an axiom instead of the Law of the Excluded Middle.