Path-Connected Space is Connected

Theorem
Let $T$ be a topological space which is path-connected.

Then $T$ is connected.

Proof
Let $D$ be the discrete space $\left\{{0, 1}\right\}$.

Let $T$ be path-connected.

Let $f: T \to D$ be a continuous surjection.

Let $x, y \in T: f \left({x}\right) = 0, f \left({y}\right) = 1$.

Let $I \subset \R$ be the closed real interval $\left[{0. . 1}\right]$.

Let $g: I \to T$ be a path from $x$ to $y$.

Then by Continuity of Composite Mapping it follows that $f \circ g: I \to D$ is a continuous surjection.

This contradicts the connectedness of $I$ as proved in Only Intervals are Connected.

Hence the result.

Note
The converse is not necessarily the case.

It is possible for a topological space to be connected but not path-connected.

For example, Graph of Sine of Reciprocal is connected but not path-connected.