Set of Integers is not Well-Ordered by Usual Ordering

Theorem
The set of integers $\Z$ is not well-ordered under the usual ordering $\le$.

Proof
$\Z$ is a well-ordered set.

Then by definition, all subsets of $\Z$ has a smallest element.

But take $\Z$ itself.

Suppose $x \in \Z$ is a smallest element.

Then $x - 1 \in \Z$.

But $x - 1 < x$, which contradicts the supposition that $x \in \Z$ is a smallest element.

Hence there can be no such smallest element.

So by Proof by Contradiction, $\Z$ is not well-ordered by $\le$.