Fort Space is Scattered/Proof 1

Proof
Let $H \subseteq T$ such that $H \ne \varnothing$ and $H \ne \left\{{p}\right\}$.

Then $\exists x \in H: x \ne p$.

From Clopen Points in Fort Space, every point of $T$ apart from $p$ is open in $T$.

So $\left\{{x}\right\}$ is an open set of $T$.

So $H \cap \left\{{x}\right\} = \left\{{x}\right\}$ and so $x$ is isolated in $H$.

Thus $H$ contains at least one point which is isolated in $H$.

On the other hand, suppose $H = \left\{{p}\right\}$.

From Singleton Point is Isolated, $p$ is an isolated point in $\left\{{p}\right\} = H$.

So again $H$ contains at least one point which is isolated in $H$.

So for all $H \subseteq S$ we have that $H$ contains at least one point which is isolated in $H$.

Hence the result, by definition of scattered space.