Separation Properties of Alexandroff Extension of Rational Number Space

Theorem
Let $\left({\Q, \tau_d}\right)$ be the rational number space under the Euclidean topology $\tau_d$.

Let $p$ be a new element not in $\Q$.

Let $\Q^* := \Q \cup \left\{{p}\right\}$.

Let $T^* = \left({\Q^*, \tau^*}\right)$ be the Alexandroff extension on $\left({\Q, \tau_d}\right)$.

Then $T^*$ satisfies no Tychonoff separation axioms higher than a $T_1$ (Fréchet) space.

Proof
From Alexandroff Extension of Rational Number Space is $T_1$ Space, $T^*$ is a $T_1$ space.

From Alexandroff Extension of Rational Number Space is not Hausdorff, $T^*$ is not a $T_2$ (Hausdorff) space.

From Completely Hausdorff Space is Hausdorff Space, $T^*$ is not a $T_{2 \frac 1 2}$ (completely Hausdorff) space.