Y'-independent Euler's Equation

Theorem
Let $y$ be a mapping.

Let $J$ a functional be such that


 * $\ds J \sqbrk y = \int_a^b \map F {x,y} \rd x$

Then the corresponding Euler's Equation can be reduced to:


 * $F_y = 0$

Furthermore, this is an algebraic equation.

Proof
Assume that:


 * $\ds J \sqbrk y = \int_a^b \map F {x,y} \rd x$

Then Euler's Equation for $J$ is:


 * $F_y = 0$

Since $F$ is independent of $y'$, the equation is algebraic.