Horizontal Section of Simple Function is Simple Function

Theorem
Let $\struct {X, \Sigma_X}$ and $\struct {Y, \Sigma_Y}$ be measurable spaces.

Let $\struct {X \times Y, \Sigma_X \otimes \Sigma_Y}$ be the product measurable space of $\struct {X, \Sigma_X}$ and $\struct {Y, \Sigma_Y}$.

Let $f : X \times Y \to \R$ be a simple function.

Let $y \in Y$.

Then $f^y : X \to \R$ is a simple function, where $f^y$ is the $y$-horizontal section of $f$.

Proof
Write the standard representation of $f$ as:


 * $\ds f = \sum_{k \mathop = 1}^n a_k \chi_{E_k}$

with:


 * $E_1, E_2, \ldots, E_n$ pairwise disjoint $\Sigma_X \otimes \Sigma_Y$-measurable sets
 * $a_1, a_2, \ldots, a_n$ real numbers.

We have:

From Intersection of Horizontal Sections is Horizontal Section of Intersection, we have that:


 * $\paren {E_1}^y, \paren {E_2}^y, \ldots, \paren {E_n}^y$ are pairwise disjoint.

From Horizontal Section of Measurable Set is Measurable, we have that:


 * $\paren {E_1}^y, \paren {E_2}^y, \ldots, \paren {E_n}^y$ are $\Sigma_X$-measurable.

So, we have:


 * $\ds f^y = \sum_{k \mathop = 1}^n a_k \chi_{\paren {E_k}^y}$

with:


 * $\paren {E_1}^y, \paren {E_2}^y, \ldots, \paren {E_n}^y$ pairwise disjoint $\Sigma_X$-measurable sets
 * $a_1, a_2, \ldots, a_n$ real numbers.

So $f^y$ is a simple function.