Denial of Existence/Examples/x less than or equal to 3/Examples/0 to 3

Example of Denial of Universality: $\forall x \in S: x \le 3$
Let $P$ be the statement:
 * $\exists x \in S: x \le 3$

and $\lnot P$ its negation:
 * $\forall x \in S: x > 3$

Let $S = \closedint 0 3$ where $\closedint \cdot \cdot$ denotes a closed real interval.

Then we have that:
 * $P$ is true

and consequently:
 * $\lnot P$ is false

Proof
The truth of $P$ can be demonstrated by citing $x \in S: x = 2$.

Thus $2$ is an instance of an $x \in S$ such that $x > 3$ that has been shown to exist.

Hence its negation is false.