Cartesian Product of Intersections/Corollary 1

Corollary to Cartesian Product of Intersections

 * $A \times \paren {B \cap C} = \paren {A \times B} \cap \paren {A \times C}$

Proof
Take the result Cartesian Product of Intersections:
 * $\paren {S_1 \cap S_2} \times \paren {T_1 \cap T_2} = \paren {S_1 \times T_1} \cap \paren {S_2 \times T_2}$

Put $S_1 = S_2 = A, T_1 = B, T_2 = C$: