Order Isomorphism is Transitive

Theorem
Let $\struct {S_1, \preccurlyeq_1}$, $\struct {S_2, \preccurlyeq_2}$ and $\struct {S_3, \preccurlyeq_3}$ be ordered sets.

Let $\struct {S_1, \preccurlyeq_1}$ be isomorphic to $\struct {S_2, \preccurlyeq_2}$.

Let $\struct {S_2, \preccurlyeq_2}$ be isomorphic to $\struct {S_3, \preccurlyeq_3}$.

Then $\struct {S_1, \preccurlyeq_1}$ is isomorphic to $\struct {S_3, \preccurlyeq_3}$.

Proof
Let $\phi: S_1 \to S_2$ be an order isomorphism from $\struct {S_1, \preccurlyeq_1}$ to $\struct {S_2, \preccurlyeq_2}$.

Let $\psi: S_2 \to S_3$ be an order isomorphism from $\struct {S_2, \preccurlyeq_2}$ to $\struct {S_3, \preccurlyeq_3}$.

From Composite of Order Isomorphisms is Order Isomorphism, $\psi \circ \phi: S_1 \to S_3$ is an order isomorphism from $\struct {S_1, \preccurlyeq_1}$ to $\struct {S_3, \preccurlyeq_3}$.

The result follows.