Definition talk:Equidistance

I used Givant's definition for $R^2$ and extrapolated it to $R^n$. Is it correct? --GFauxPas 19:54, 25 January 2012 (EST)


 * It certainly appears to be, and I'm quite sure it is. --Lord_Farin 02:28, 26 January 2012 (EST)