Talk:Area of Square

Be careful, this can't be circular. --Cynic (talk) 01:21, 12 March 2009 (UTC)

If someone can check the irrational side length section (especially the limits), I would appreciate it. --Cynic (talk) 21:50, 12 March 2009 (UTC)

Looks impressive. I think it's okay, I need to look at it a bit harder (I'll do that later, not tonight) but I think it's fine. --Matt Westwood 21:53, 12 March 2009 (UTC)

I'm a touch concerned that the integral proof is circular. It seems to me that the definition of the definite integral as area is based on the area of a rectangle, which in turn is based on the area of a square. Also, I'm not sure if the fundamental theorem of calculus is really relevant for this proof. --Cynic (talk) 23:05, 18 April 2009 (UTC)
 * You're absolutely right. Even if we adopted a notion of double integral with arbitrary sets and Lebesgue measure, the notion of set measure in Euclidean space depends on the area of a rectangle being the product of the length of its sides.  Also, though it hardly matters in light of that, the fundamental theorem of calculus is over kill, one could use Integration of a Constant for the same use here. Zelmerszoetrop 23:09, 18 April 2009 (UTC)


 * I have to agree. I'll leave the decisions about geometry up to you guys (especially Cynic) - you seem to know our way round this area better than me. But I'd say: scrub this or label it "circular" or something. OTOH it is a proof (of sorts) and so is to all intents and purposes "valid". --Matt Westwood 23:13, 18 April 2009 (UTC)


 * Tidied and added a note regarding the circularity. --Cynic (talk) 23:32, 18 April 2009 (UTC)