Complex Addition is Closed

Theorem
$$\forall z, w \in \C: z + w \in \C$$.

Proof from Informal Definition
From the informal definition of complex numbers, we define the following:


 * $$z = x_1 + i y_1$$
 * $$w = x_2 + i y_2$$

where $$i = \sqrt {-1}$$ and $$x_1, x_2, y_1, y_2 \in \R$$.

Then from the definition of complex addition, $$z + w = \left({x_1 + x_2}\right) + i \left({y_1 + y_2}\right)$$.

Real Addition is closed, from Additive Group of Real Numbers so $$\left({x_1 + x_2}\right) \in \R$$ and $$\left({y_1 + y_2}\right) \in \R$$.

Hence the result.

Proof from Formal Definition
From the formal definition of complex numbers, we have:


 * $$z = \left({x_1, y_1}\right)$$
 * $$w = \left({x_2, y_2}\right)$$

where $$x_1, x_2, y_1, y_2 \in \R$$.

Then from the definition of complex addition, $$z + w = \left({x_1 + x_2, y_1 + y_2}\right)$$.

Real Addition is closed, from Additive Group of Real Numbers so $$\left({x_1 + x_2}\right) \in \R$$ and $$\left({y_1 + y_2}\right) \in \R$$.

Hence the result.