Contradiction is Negation of Tautology

Theorem
A contradiction implies and is implied by the negation of a tautology:


 * $\bot \dashv \vdash \neg \top$

That is, a falsehood can not be true, and a non-truth is a falsehood.

Comment
Note that the proof of:
 * $\neg \top \vdash \bot$

relies directly upon Law of Excluded Middle, and it can be seen that this is just another way of stating that truth.

The proposition:
 * If it's not true, it must be false

is indeed valid only in the context where there are only two truth values.

From the intuitionistic perspective, this result does not hold.

Proof by Truth Table
We apply the Method of Truth Tables to the proposition.

As can be seen by inspection, the truth values in the appropriate columns match.

$\begin{array}{|c||cc|} \hline \top & \neg & \bot \\ \hline T & T & F \\ \hline \end{array}$

Proof by Boolean Interpretation
Let $p$ be a propositional formula.

Let $v$ be any arbitrary boolean interpretation of $p$.

Then $v \left({p}\right) = F \iff v \left({\neg p}\right) = T$ by the definition of the logical not.

Since $v$ is arbitrary, $p$ is false in all interpretations iff $\neg p$ is true in all interpretations.

Hence $\bot \dashv \vdash \neg \top$.