Primitive of Reciprocal of q plus p by Secant of a x

Theorem

 * $\displaystyle \int \frac {\mathrm d x} {q + p \sec a x} = \frac x q - \frac p q \int \frac {\mathrm d x} {p + q \cos a x}$

Also see

 * Primitive of $\dfrac 1 {q + p \csc a x}$