Even Convergents of Simple Continued Fraction are Strictly Increasing

Theorem
Let $n \in \N \cup \set \infty$ be an extended natural number.

Let $\sqbrk {a_0, a_1, \ldots}$ be a simple continued fraction in $\R$ of length $n$.

Let $p_0, p_1, p_2, \ldots$ and $q_0, q_1, q_2, \ldots$ be its numerators and denominators.

Let $\sequence {C_0, C_1, \ldots}$ be its sequence of convergents.

The even convergents satisfy $C_0 < C_2 < C_4 \cdots$.

Proof
Let $k \ge 2$ be an even integer.

From Difference between Adjacent Convergents But One of Simple Continued Fraction:
 * $C_k - C_{k - 2} = \dfrac {\paren {-1}^k a_k} {q_k q_{k - 2} } = \dfrac {a_k} {q_k q_{k - 2} }$

By definition of simple continued fraction, $a_k > 0$.

By Convergents of Simple Continued Fraction are Rationals in Canonical Form, $q_k > 0$ and $q_{k - 2} > 0$.

Thus $C_k > C_{k - 2}$.

Also see

 * Odd Convergents of Simple Continued Fraction are Strictly Decreasing
 * Properties of Convergents of Continued Fractions