Talk:Limit at Infinity of Polynomial over Complex Exponential

I'm not sure what the problem is with $e^{iy}$ being constant ... --GFauxPas (talk) 13:12, 14 May 2014 (UTC)


 * If $y = 0$ then $e^{iy}$ = 1. If $y = \pi$ then $e^{iy} = -1$. $1 \ne -1$. $e^{iy}$ is not constant. --prime mover (talk) 13:18, 14 May 2014 (UTC)


 * But we're taking the limit as $x \to +\infty$, we're not concerned with $y$? --GFauxPas (talk) 13:37, 14 May 2014 (UTC)


 * That's not the issue. I can see what you're trying to do, and I know where you're going with it. But the fact is that $e^{iy}$ is not constant. Your result works, but your reasoning on how to get there seems flawed to me.


 * My recommendation is to consider applying the modulus. --prime mover (talk) 14:57, 14 May 2014 (UTC)