Primitive of Reciprocal of x squared minus a squared/Logarithm Form 2

Theorem

 * $\displaystyle \int \frac {\d x} {x^2 - a^2} = \frac 1 {2 a} \ln \size {\frac {x - a} {x + a} } + C$

where $x^2 > a^2$.

Also see

 * Primitive of Reciprocal of $a^2 - x^2$: Logarithm Form