Rutherford's Experiment that led to Nuclear Model of Atom/Strength of Force

Rutherford's Experiment that led to Nuclear Model of Atom: Strength of Force
Consider 's experiment that led him to propose the nuclear model of the atom: that most of its mass is concentrated in one place. The $\alpha$ particles that were deflected through $180 \degrees$ were coming within $10^{-14} \ \mathrm m$ of the nucleus.

The electric charge on the $\alpha$ particle is $2 \E$, where $\E$ is the elementary charge.

The electric charge on the nucleus of gold is $79 \E$.

Hence by Coulomb's Law of Electrostatics, the force $F$ on the $\alpha$ particle at this range is given by:

given the values:
 * $\E = 1.60217 \, 6634 \times 10^{−19} \ \mathrm C$
 * $\varepsilon_0 = 8 \cdotp 85418 \, 78128 (13) \times 10^{-12} \, \mathrm F \, \mathrm m^{-1}$

Hence we have a force acting within a single atom of the weight of nearly $10 \mathrm {kg}$.