Primitive of Reciprocal of a x + b squared/Proof 2

Proof
From Primitive of Power of $a x + b$:
 * $\ds \int \paren {a x + b}^n \rd x = \frac {\paren {a x + b}^{n + 1} } {\paren {n + 1} a} + C$

where $n \ne 1$.

The result follows by setting $n = -2$.