Rational Multiplication is Commutative

Theorem
The operation of multiplication on the set of rational numbers $$\Q$$ is commutative:


 * $$\forall x, y \in \Q: x \times y = y \times x$$

Proof
Follows directly from the definition of rational numbers as the quotient field of the integral domain $$\left({\Z, +, \times}\right)$$ of integers.

So $$\left({\Q, +, \times}\right)$$ is a field, and therefore a priori $$\times$$ is commutative on $$\Q$$.