Two-Person Zero-Sum Game/Example/Abstract 5

Example of Two-Person Zero-Sum Game
The two players are $A$ and $B$.

Player $A$ has $m$ strategies: $A_1, A_2, \ldots, A_m$.

Player $B$ has $n$ strategies: $B_1, B_2, \ldots, B_n$.

The game is zero-sum in that a payoff of $p$ to $A$ corresponds to a payoff of $-p$ to $B$.

The following table partially specifies the payoff to $A$ for each strategy of $A$ and $B$.

This has an equilibrium point at $\left({A_3, B_3}\right)$ with a payoff to $A$ of $5$.

Proof
Given $B_3$, every other strategy adopted by $A$ will result in a smaller payoff to $A$ than $5$.

Given $A_3$, every other strategy adopted by $B$ will result in a larger payoff to $A$ than $5$.

Hence, by definition, $\left({A_3, B_3}\right)$ is an equilibrium point.