Reflexive Reduction is Antireflexive

Theorem
Let $\mathcal R$ be a relation on a set $S$.

Let $\mathcal R^\ne$, be the reflexive reduction of $\mathcal R$.

Then $\mathcal R^\ne$ is antireflexive.

Proof
By the definition of reflexive reduction:


 * $\mathcal R^\ne = \mathcal R \setminus \Delta_S$

where $\Delta_S$ denotes the diagonal relation on $S$.

By Set Difference Intersection with Second Set is Empty Set:


 * $\left({\mathcal R \setminus \Delta_S}\right) \cap \Delta_S = \varnothing$

Hence by Relation is Antireflexive iff Disjoint from Diagonal Relation, $\mathcal R^\ne$ is antireflexive.