Coherent Sequence is Partial Sum of P-adic Expansion/Lemma

Theorem
Let $p$ be a prime number.

Let $\sequence {\alpha_n}$ be a coherent sequence.

For all $n \in \N$, let $\sequence {b_{j, n} }_{0 \le j \le n}$ be a sequence such that:
 * $(1) \quad \displaystyle \alpha_n = \sum_{j \mathop = 0}^n b_{j,n} p^j$
 * $(2) \quad \forall j: 0 \le j \le n: 0 \le b_{j, n} < p$

Then:
 * $\forall n \in \N: \alpha_n = \displaystyle \sum_{i \mathop = 0}^n b_{i, i} p^i$

Proof
The theorem is proved by induction:

Basis for the Induction
$n = 0$

By definition: $\alpha_0 = b_{0, 0}$

This is the basis for the induction.

Induction Hypothesis
This is our induction hypothesis:
 * $\alpha_k = \displaystyle \sum_{i \mathop = 0}^k b_{i, i} p^i$

Now we need to show true for $n = k + 1$:
 * $\alpha_{k + 1} = \displaystyle \sum_{i \mathop = 0}^{k + 1} b_{i, i} p^i$

Induction Step
This is our induction step.

From Difference of Consecutive terms of Coherent Sequence there exists $c_{k + 1} \in \Z$:
 * $(a) \quad 0 \le c_{k + 1} < p$
 * $(b) \quad \alpha_{k + 1} = c_{k + 1} p^{k + 1} + \alpha_k$

From the induction hypothesis:
 * $\alpha_{k + 1} = c_{k + 1} p^{k + 1} + \sum_{j \mathop = 0}^k b_{j, j} p^j$

From the Zero Padded Basis Representation it follows that the two sequences:
 * $\sequence {b_{j, k + 1} }_{0 \le j \le k + 1}$

and
 * $\sequence {b_{0, 0}, b_{1, 1}, \dots, b_{k - 1, k - 1}, b_{k, k}, c_{k + 1}}$

are equal.

Then:
 * $\forall j \in \closedint 0 {k + 1} : b_{j, k + 1} = b_{j, j}$

It follows that:
 * $\alpha_{k + 1} = \displaystyle \sum_{i \mathop = 0}^{k + 1} b_{i, i} p^i$

By induction:
 * $\forall n \in \N: \alpha_n = \displaystyle \sum_{i \mathop = 0}^n b_{i, i} p^i$