Talk:Rational Power is of Exponential Order Epsilon

What's the best way to phrase this idea?:

$t^r$ at $t = 0$ can be defined any way you'd like, or left undefined; the theorem will hold in any case because $t^r$ has a right hand limit at $0$. --GFauxPas (talk) 18:45, 10 December 2016 (EST)