Length of Circumradius of Triangle

Theorem
Let $\triangle ABC$ be a triangle whose sides are of lengths $a, b, c$.

Then the length of the circumradius $R$ of $\triangle ABC$ is given by:
 * $R = \dfrac {abc} {4 \sqrt {s \paren {s - a} \paren {s - b} \paren {s - c} } }$

where $s = \dfrac {a + b + c} 2$ is the semiperimeter of $\triangle ABC$.

Proof

 * Circumcircle.png

Let $\mathcal A$ be the area of $\triangle ABC$.

From Area of Triangle in Terms of Circumradius:
 * $\mathcal A = \dfrac {a b c} {4 R}$

From Heron's Formula:
 * $\mathcal A = \sqrt {s \paren {s - a} \paren {s - b} \paren {s - c} }$

where $s = \dfrac {a + b + c} 2$ is the semiperimeter of $\triangle ABC$.

Hence the result:
 * $R = \dfrac {abc} {4 \sqrt {s \paren {s - a} \paren {s - b} \paren {s - c} } }$