Sum of Infinite Geometric Sequence/Proof 2

Proof
By the Chain Rule for Derivatives and the corollary to $n$th Derivative of Reciprocal of $m$th Power:
 * $\dfrac {\d^n} {\d z^n} \dfrac 1 {1 - z} = \dfrac {n!} {\paren {1 - z}^{n + 1} }$

Thus the Maclaurin series expansion of $\dfrac 1 {1 - z}$ is:
 * $\ds \sum_{n \mathop = 0}^\infty \frac {z^n} {n!} \dfrac {n!} {\paren {1 - 0}^{n + 1} }$

whence the result.