Primitive of Reciprocal of Root of a minus x by Cube of Root of x minus b

Theorem

 * $\ds \int \dfrac {\d x} {\paren {a - x}^{1/2} \paren {x - b}^{3/2} } = \dfrac 2 {b - a} \sqrt {\dfrac {a - x} {x - b} } + C$