Reverse Triangle Inequality/Normed Vector Space

Theorem
Let $\struct {X, \norm {\, \cdot \,} }$ be a normed vector space.

Then:
 * $\forall x, y \in X: \norm {x - y} \ge \size {\norm x - \norm y}$

Proof
Let $d$ denote the metric induced by $\norm {\, \cdot \,}$, that is:
 * $\map d {x, y} = \norm {x - y}$

From Metric Induced by Norm is Metric we have that $d$ is indeed a metric.

Then, from the Reverse Triangle Inequality as applied to metric spaces:
 * $\forall x, y, z \in X: \size {\norm {x - z} - \norm {y - z} } \le \norm {x - y}$

Then:
 * $\forall x, y \in X: \size {\norm x - \norm y} = \size {\norm {x - 0} - \norm {y - 0} } \le \norm {x - y}$.