User talk:J D Bowen/Math735 HW1


 * "The number of permutations of m elements from n possible elements is $n!/m! = n(n-1)...(n-m+1)$. "

Think you might mean $\frac {n!} {\left({n-m}\right)!}$.

Easy to get confused, I've just stared at it for 10 minutes with a puzzled look on my face!

See Number of k-Cycles in Symmetric Group‎ for the page I did. --prime mover 09:13, 11 September 2010 (UTC)
 * You're right. Good call.  eh, it's already been handed in =/ . J D Bowen 17:18, 11 September 2010 (UTC)