P-adic Numbers form Completion of Rational Numbers with P-adic Norm

Theorem
Let $p$ be a prime number.

Let $\norm {\,\cdot\,}^\Q_p$ be the p-adic norm on the rationals $\Q$.

Let $\struct {\Q_p, \norm {\,\cdot\,}_p}$ be the $p$-adic numbers.

Then $\struct {\Q_p, \norm {\,\cdot\,}_p}$ is a completion of $\struct {\Q, \norm {\,\cdot\,}^\Q_p}$

Proof
Let $\norm {\,\cdot\,}^\Q_p$ be the p-adic norm on the rationals $\Q$.

From P-adic Norm is Non-Archimedean Norm:
 * $\struct{Q, \norm {\,\cdot\,}^\Q_p}$ is a valued field with non-Archimedean norm $\norm {\,\cdot\,}_p$

By definition of the $p$-adic numbers:
 * $\Q_p$ is the quotient ring $\CC \, \big / \NN$

where:
 * $\CC$ is the commutative ring of Cauchy sequences over $\struct {\Q, \norm {\,\cdot\,}^\Q_p}$.

and
 * $\NN$ is the set of null sequences in $\struct {\Q, \norm {\,\cdot\,}^\Q_p}$.

From Completion of Normed Division Ring:
 * $\struct {\Q_p, \norm {\,\cdot\,}_p}$ is the completion of $\struct {\Q, \norm {\,\cdot\,}^\Q_p}$.