Talk:Squeeze Theorem for Absolutely Convergent Series

Huh?!? The only way $-\sum \left|{a_n}\right| = \sum \left|{a_n}\right|$ is for $\sum \left|{a_n}\right| = 0$ and the result is then pointlessly trivial. --prime mover 17:23, 10 February 2012 (EST)


 * This is not what I intended. I meant something like:


 * $\displaystyle\lim_{n\to\infty} a_n = 0 \land \forall n: -|a_n|\le b_n \le |a_n| \implies \lim_{n\to\infty} b_n = 0$


 * which is slightly less trivial. --Lord_Farin 18:10, 10 February 2012 (EST)