Period of Reciprocal of 53 is One Quarter of Maximal

Theorem
The decimal expansion of the reciprocal of $53$ has $\dfrac 1 4$ the maximum period, that is: $13$:
 * $\dfrac 1 {53} = 0 \cdotp \dot 01886 \, 79245 \, 28 \dot 3$

Proof
Performing the calculation using long division:

0.018867924528301.... -- 53)1.0000000000000000000     53     --     470     424     ---      460      424      ---       360       318       ---        420        371        ---         490         477         ---          130          106          ---           240           212           ---            280            265            ---             150             106             ---              440              424              ---               160               159               ---                 100                  53                 ---                 ....