Intersecting Circles have Different Centers

Proof

 * Euclid-III-5.png

Let $ABC$ and $BDCG$ be circles which cut one another at $B$ and $C$.

Suppose they had the same center $E$.

Join $EC$ and let $EG$ be drawn at random through $F$.

As $E$ is the center of $ABC$, by, we have that $EC = EF$.

Similarly, as $E$ is also the center of $BDCG$, we have that $EC = EG$.

But they are clearly unequal by the method of construction.

So from this contradiction, the two circles can not have the same center.