Ceiling of x+m over n/Corollary

Corollary to Ceiling of $\frac {x + m} n$
Let $n \in \Z$ such that $n > 0$.

Let $x \in \R$.

Then:
 * $\ceiling {\dfrac x n} = \ceiling {\dfrac {\ceiling x} n}$

where $\ceiling x$ denotes the ceiling of $x$.

Proof
This is a special case of Ceiling of $\dfrac {x + m} n$:
 * $\ceiling {\dfrac {x + m} n} = \ceiling {\dfrac {\ceiling x + m} n}$

where $m = 0$.