Derivative of Hyperbolic Tangent Function

Theorem
Let $u$ be a differentiable real function of $x$.

Then:
 * $\map {\dfrac \d {\d x} } {\tanh u} = \sech^2 u \dfrac {\d u} {\d x}$

where $\tanh$ is the hyperbolic tangent and $\sech$ is the hyperbolic secant.

Also see

 * Derivative of Hyperbolic Sine Function
 * Derivative of Hyperbolic Cosine Function


 * Derivative of Hyperbolic Cotangent Function


 * Derivative of Hyperbolic Secant Function
 * Derivative of Hyperbolic Cosecant Function