Multiply Perfect Number of Order 6/Historical Note

Historical Note on Multiply Perfect Number of Order 6
, in a letter of $1643$, challenged to find the ratio of:
 * $2^{36} \times 3^8 \times 5^5 \times 11 \times 13^2 \times 19 \times 31^2$
 * $\times \ 43 \times 61 \times 83 \times 223 \times 331 \times 379 \times 601 \times 757 \times 1201$
 * $\times \ 7019 \times 823 \, 543 \times 616 \, 318 \, 177 \times 100 \, 895 \, 598 \, 169$

to its aliquot sum.

replied that its ratio to the sum of all its divisors (including the number itself) was $6$.

He also pointed out that $100 \, 895 \, 598 \, 169 = 112 \, 303 \times 898 \, 423$, both of which divisors are prime.

Also note that $823 \, 543 = 7^7$, another point that glossed over, intentionally or inadvertently, in his initial challenge.

Both 's initial challenge and 's factorisation of $100 \, 895 \, 598 \, 169$ were remarkable, considering the lack of computing machines in those days. To this day, nobody knows how they did it.