Nontrivial Zeroes of Riemann Zeta Function are Symmetrical with respect to Critical Line

Theorem
The nontrivial zeroes of the Riemann $\zeta$ function are distributed symmetrically the  critical line.

That is, suppose $s_1 = \sigma_1 + i t$ is a nontrivial zero of $\map \zeta s$.

Then there exists another nontrivial zero $s_2$ of $\map \zeta s$ such that:


 * $s_2 = 1 - s_1$

Proof
From Functional Equation for Riemann Zeta Function, we have:


 * $\ds \pi^{-s/2 } \map \Gamma {\dfrac s 2} \map \zeta s = \pi^{\paren {s/2 - 1/2 } } \map \Gamma {\dfrac {1 - s} 2} \map \zeta {1 - s}$

We suppose $s_1 = \sigma_1 + i t$ is a nontrivial zero of $\map \zeta s$. Then we have:

It remains to be shown that of the three terms on the, $\map \zeta {1 - s_1}$ MUST equal zero.

We can rewrite the first term in terms of the exponential function
 * $\ds \pi^{\paren { {s_1}/2 - 1/2 } } = \map \exp {\map \ln {\pi^{\paren { {s_1}/2 - 1/2 } } }}$

From the definition of the exponential function, we know $\map \exp {\map \ln {\pi^{\paren { {s_1}/2 - 1/2 } } }}$ never equals zero.

From Zeroes of Gamma Function, we know $\map \Gamma {\dfrac {1 - s_1} 2}$ never equals zero.

Therefore:
 * $\map \zeta {1 - s_1} = 0$

Also see

 * Riemann Hypothesis: If this is true, all nontrivial zeroes are already on the critical line.