Identity Morphism is Unique

Theorem
Let $\mathcal C$ be a category, and $X$ and object of $\mathcal C$.

Then the identity morphism $\operatorname{id}_X : X \to X$ is unique.

Proof
Let $\operatorname{id}_X^1$, $\operatorname{id}_X^2$ be two identity morphisms for $X$.

By definition, for any morphism $f : Y \to X$, we have $\operatorname{id}_X^1 \circ f = f$.

In particular, taking $Y = X$ and $f = \operatorname{id}_X^2$, we have $\operatorname{id}_X^1 \circ \operatorname{id}_X^2 = \operatorname{id}_X^2$.

Similarly for any morphism $g : X \to Y$ we have $g \circ \operatorname{id}_X^2 = g$.

So taking $Y = X$ and $g = \operatorname{id}_X^1$ we have $\operatorname{id}_X^1 \circ \operatorname{id}_X^2 = \operatorname{id}_X^1$.

Putting this together we have:


 * $\operatorname{id}_X^2 = \operatorname{id}_X^1 \circ \operatorname{id}_X^2 = \operatorname{id}_X^1$

as required.