Ax-Grothendieck Theorem

Theorem
Let $f: \C^n \to \C^n$ be a polynomial map.

If $f$ is injective, then $f$ is surjective.

Proof
The proof proceeds as follows:


 * $(1): \quad$ showing that the theorem can be captured using a first-order sentences in the language of rings
 * $(2): \quad$ showing that the theorem is true for at least one field of every characteristic $p > 0$
 * $(3): \quad$ applying the Lefschetz Principle (First-Order).

First-Order Sentences in Language of Rings
Since $n$ is fixed, we can quantify over polynomials where each variable occurs with degree at most $d$ since there are only finitely many coefficients to quantify over.

Thus, for each $n$ and $d$, we can build an $\mathcal L_r$ sentence which holds in a field $F$ if and only if every injective polynomial map $F^n \to F^n$ where each variable occurs with at most degree $d$ is surjective.

First, we write a formula:
 * $\phi_{\left({i_1, \dots, i_n}\right)}$

which says that the $n$-variable polynomial map with coefficients $a_{\left({i_1, \dots, i_n}\right)}$ where $(\left({i_1, \dots, i_n}\right) \le \left({d, \dots, d}\right)$ is injective.

Note that the polynomial map takes on $n$-tuple images, so is of the form:
 * $f = \left({f_1, \dots, f_n}\right)$

where each $f_k$ is a polynomial in $n$ variables.

The variables $a_{k, \left({i_1, \dots, i_n}\right)}$ in the sentence below are intended to be interpreted as the coefficients of $f_k$:


 * $\displaystyle \forall x_1 \cdots \forall x_n \forall y_1 \cdots \forall y_n \left({\left({\bigwedge_{k \le n}\ \sum_{ \left({i_1, \dots, i_n}\right)} a_{k, \left({i_1, \dots, i_n}\right)} x_{1}^{i_1}\cdots x_{n}^{i_n} = \sum_{ \left({i_1, \dots, i_n}\right)} a_{k, \left({i_1, \dots, i_n}\right)}  y_{1}^{i_1} \cdots y_n^{i_n} }\right) \rightarrow \bigwedge_{i \mathop = 1, \dots, n} x_i = y_i}\right)$

We also write a formula $\psi_{(i_1,\dots,i_n)}$ which says that such a polynomial is surjective:
 * $\displaystyle \forall z_1 \cdots \forall z_n \exists x_1 \cdots \exists x_n \left(\bigwedge_{k \le n}\ \sum_{(i_1,\dots,i_n)} a_{k,(i_1,\dots,i_n)}  x_{1}^{i_1}\cdots x_{n}^{i_n} = z_k \right) $

Finally, we combine these into the required implication, quantifying over all coefficients:
 * $\displaystyle \underset{k,(i_1,\dots,i_n)}{\huge{\forall}} a_{k,(i_1,\dots,i_n)} \left[ \phi_{(i_1,\dots,i_n)} \rightarrow \psi_{(i_1,\dots,i_n)} \right]$

Note that we have one of these sentences for every maximum degree $d$ of the variables in a polynomial map.

Thus it has been demonstrated that the theorem can be captured using a first-order sentences in the language of rings.

Field of Characteristic $p > 0$
Since injections on finite sets are necessarily surjective, every injective polynomial map $k^n \to k^n$ is surjective when $k$ is a finite field.

We extend this to the algebraic closure of $k$.

This will demonstrate that the sentence above is satisfied by at least one model of the theory of algebraically closed fields of characteristic $p$ for every $p > 0$.

Let $\mathbb F^{\operatorname{alg} }_p$ be the algebraic closure of the finite field with $p$ elements.

Suppose there is an injective polynomial map $f:(\mathbb F^{\operatorname{alg}}_p )^n \to (\mathbb F^{\operatorname{alg}}_p )^n$ which is not surjective.

Let $A$ be the set of coefficients appearing in $f$.

Let $(z_1,\dots,z_n)\in (\mathbb F^{\operatorname{alg}}_p )^n$ be an element not in the range of $f$.

Consider the subfield $k$ of $\mathbb F^{\operatorname{alg}}_p$ generated by the elements of $A$ and the elements $z_1,\dots,z_n$.

Since $\mathbb F^{\operatorname{alg}}_p = \displaystyle{\bigcup_{n=1,2,\dots} \mathbb F_{p^n}}$, any finitely generated subfield is contained in some finite sub-union $\displaystyle{\bigcup_{n=1,2,\dots,N} \mathbb F_{p^n}}$.

Hence $k$ is finite.

Therefore, $f\restriction_{k^n}$ is an injective polynomial map on a finite field which is not surjective.

This is a contradiction.

So, we must have that every injective polynomial map on $(\mathbb F^{\operatorname{alg}}_p )^n$ is surjective.

That is, $(\mathbb F^{\operatorname{alg}}_p )^n$ satisfies the sentences above for each characteristic $p>0$.

Thus it has been demonstrated that the theorem is true for at least one field of every characteristic $p > 0$.

Application of Lefschetz Principle
It has been shown that the sentences above are true in some algebraically closed field of characteristic $p$ for all $p > 0$.

By the Lefschetz Principle, it follows that they are true in $\C$.