Group/Examples/x+y over 1+xy

Theorem
The set of real numbers $\left\{{x \in \R: -1 < x < 1}\right\}$, under the operation:
 * $x \circ y = \dfrac {x + y} {1 + x y}$

is a group.

Proof
Let $-1 < x, y, z < 1$.

We check the group axioms in turn:

G2: Identity
Similarly, putting $y = 0$ we find $x \circ y = x$.

So $0$ is the identity.

G3: Inverses
Similarly, putting $x = -y$ gives us $\left({-y}\right) \circ y = 0$.

So each $x$ has an inverse $-x$.

G0: Closure
First note that: $-1 < x, y < 1 \implies x y > -1 \implies 1 + x y > 0$.

Next:

Finally:

Thus $-1 < x, y < 1 \implies -1 < x \circ y < 1$, and we see that in this range, $\circ$ is closed.

Thus the given set and operation form a group.