Primitive of Inverse Hyperbolic Cotangent Function/Also presented as

Primitive of Inverse Hyperbolic Tangent Function: Also presented as
This result can also be presented as:
 * $\ds \int \arcoth x \rd x = x \arcoth x + \ln \sqrt {x^2 - 1} + C$

Proof
From Primitive of $\artanh x$:
 * $\ds \int \arcoth x \rd x = x \arcoth x + \frac {\map \ln {x^2 - 1} } 2 + C$

The result follows by observing:
 * $\dfrac 1 2 \log x = \log \sqrt x$

from Logarithm of Power.