Laplace Transform of Derivative/Discontinuity at t = a

Theorem
Let $f: \R \to \R$ or $\R \to \C$ be a continuous function, differentiable on any interval of the form $0 < t \le A$.

Let $f$ be of exponential order $a$.

Let $f'$ be piecewise continuous with one-sided limits on said intervals.

Let $\laptrans f$ denote the Laplace transform of $f$.

Let $f$ have a jump discontinuity at $t = a$.

Then:
 * $\laptrans {\map {f'} t} = s \laptrans {\map f t} - \map f 0 - e^{-a s} \paren {\map f {a^+} - \map f {a^-} }$

Proof
See Laplace Transform of Derivatives with Finite Discontinuities and use $n=1$ and $a_1=a$.