Sum over k of n Choose k by p^k by (1-p)^n-k by Absolute Value of k-np/Historical Note

== Historical Note on Sum over $k$ of $\dbinom n k$ by $p^k$ by $\left({1 - p}\right)^{n-k}$ by $\left\lvert{k - n p}\right\rvert$ == This result was stated by in his $1730$ work  for the case where $n p$ is an integer.

The general case was proved by in his  of $1896$.