Talk:Zero and One are the only Consecutive Perfect Squares

But 0 and 1 are both perfect squares. --Matt Westwood 19:25, 4 February 2009 (UTC)

Also, just because two numbers are distinct doesn't mean that their product is not a perfect square. $$4\cdot 16=64=8^2$$. And Matt, might we move the page to Zero and One are the only Consecutive Perfect Squares? --Cynic (talk) 22:10, 4 February 2009 (UTC)

By all means. Unless you want to include Gaussian integers, in which case $$-1$$ and $$0$$ are also consecutive perfect squares. Hm. Haven't thought as to whether it applies in the complex plane. Might need to be thought about.

Whatever, I'd like to leave Zero and One are the only Consecutive Perfect Squares to the originator of this page. Fair play, by the way. --Matt Westwood 22:48, 4 February 2009 (UTC)