Connectedness of Points is Equivalence Relation

Theorem
Let $T = \left({X, \vartheta}\right)$ be a topological space.

Let $a \sim b $ denote the relation:
 * $a \sim b \iff a$ is connected to $b$

where $a, b \in X$.

Then $\sim$ is an equivalence relation.

Proof
Checking in turn each of the criteria for equivalence:

Reflexivity
We have that $\left\{{a}\right\} \subseteq X$ is a (degenerate) connected subset of $X$.

So $a$ is in the same connected set as itself and so $a \sim a$.

So $\sim$ has been shown to be reflexive.

Symmetry
If $x \sim y$ then $x$ is in the same connected set as $y$ by definition.

Trivially it follows that $y$ is in the same connected set as $x$ and so $y \sim x$.

So $\sim$ has been shown to be symmetric.

Transitivity
Let $x \sim y$ and $y \sim z$.

Then by definition:
 * $x$ is in the same connected set as $y$


 * $y$ is in the same connected set as $z$

and so it follows that $x$ is in the same connected set as $z$ and so $x \sim z$.

So $\sim$ has been shown to be transitive.

$\sim$ has been shown to be reflexive, symmetric and transitive.

Hence by definition it is an equivalence relation.

Alternative Proof
Follows directly from Spaces with Connected Intersection have Connected Union.