Fourier Series/4 minus x squared over Range of 2

Theorem
Let $\map f x$ be the real function defined on $\openint 0 2$ as:


 * Sneddon-1-3-Example2.png


 * $\map f x = 4 - x^2$

Then its Fourier series can be expressed as:


 * $\map f x \sim \ds \frac 8 3 - \frac 4 {\pi^2} \sum_{n \mathop = 1}^\infty \frac {\cos n \pi x} {n^2} + \frac 4 \pi \sum_{n \mathop = 1}^\infty \frac {\sin n \pi x} n$

Proof
By definition of Fourier series:


 * $\ds \map f x \sim \frac {a_0} 2 + \sum_{n \mathop = 1}^\infty \paren {a_n \cos n \pi x + b_n \sin n \pi x}$

where:

for all $n \in \Z_{>0}$.

Thus:

For $n > 0$:

Splitting this up into bits:

Reassembling $a_n$ from the remaining non-vanishing terms:

Now for the $\sin n \pi x$ terms:

Splitting this up into bits:

Reassembling $b_n$ from the remaining non-vanishing terms:

Finally: