Talk:Product of Summations is Summation Over Cartesian Product of Products

Happy for it to be merged with Product of Summations. It is similar.

Peter Driscoll (talk) 03:46, 10 September 2017 (EDT)


 * I need to analyse it to see whether this approach can genuinely be considered a different proof from the existing one. If they are essentially the same, we may regrettably have to ditch this, as the effort to bring it to house style may be considerable. --prime mover (talk) 04:00, 10 September 2017 (EDT)


 * Note that the statements of the two are not identical. In Product of Summations, $B = \{1\cdots m\}$ does not depend on $a \in A$. So it is a proper generalisation and ought to be treated as such. &mdash; Lord_Farin (talk) 05:12, 10 September 2017 (EDT)

Product of Summations talks about standard summation re-ordering. The cartesian product version, although related has a single sum and a cartesian product to iterate over. This is useful in one particular derivation of the Eulers Product formula for the zeta function. It allows the construction of the set of positive natural numbers from the cartesian product of powers of primes.

The result is not rocket science. Just a simple proof to get started with. Learn the rules of the game here.

Peter Driscoll (talk) 10:19, 10 September 2017 (EDT)


 * I had a look at house style. It is going to take a while to get used to. As I understand your structure, the proof should have its own page but be referenced by Product of Summations, with the result listed there. Can you rename this page to, Product of Summations is Summation Over Cartesian Product of Products. If renaming is not supported, then I will create the new page and you can delete this one.


 * Your house style doesn't seem to give examples. Examples are incredibly usefull.


 * Peter Driscoll (talk) 21:02, 10 September 2017 (EDT)