Logarithm of Power

Theorem
Let $$x \in \R$$ be a strictly positive real number.

Let $$r \in \R$$ be any real number.

Let $$\log_a x$$ be the logarithm to the base $a$ of $$x$$.

Then $$\log_a \left({x^r}\right) = r \log_a x$$.

Natural Logarithms
When $$a = e$$, $$\log_a x = \ln x$$.

Consider the function $$f \left({x}\right) = \ln \left({x^r}\right) - r \ln x$$.

Then from:
 * The definition of the natural logarithm,
 * The Fundamental Theorem of Calculus;
 * The Power Rule for Derivatives, and
 * The Chain Rule:

$$\forall x > 0: f^{\prime} \left({x}\right) = \frac 1 {x^r} r x^{r-1} - \frac r x = 0$$.

Thus from Zero Derivative means Constant Function, $$f$$ is constant: $$\forall x > 0: \ln \left({x^r}\right) - r \ln x = c$$.

To determine the value of $$c$$, put $$x = 1$$.

From Basic Properties of Natural Logarithm, $$\ln 1 = 0$$.

Thus $$c = \ln 1 - r \ln 1 = 0$$.

General Logarithms
Let $$y = r \log_a x$$.

Then:

$$ $$ $$

The result follows by taking logs base $$a$$ of both sides.