Primitive of Root of x squared minus a squared cubed over x cubed

Theorem

 * $\displaystyle \int \frac {\paren {\sqrt {x^2 - a^2} }^3} {x^3} \rd x = \frac {-\paren {\sqrt {x^2 - a^2} }^3} {2 x^2} + \frac {3 \sqrt {x^2 - a^2} } 2 - \frac {3 a} 2 \arcsec \size {\frac x a} + C$

for $\size x \ge a$.

Proof
Let:

Also see

 * Primitive of $\dfrac {\paren {\sqrt {x^2 + a^2} }^3} {x^3}$
 * Primitive of $\dfrac {\paren {\sqrt {a^2 - x^2} }^3} {x^3}$