Definition:Limit Point/Topology

Topology
Let $$X$$ be a topological space.

Let $$A \subseteq X$$.

Definition from Closure
A point $$x \in X$$ is called a limit point of $$A$$ if every neighborhood $$U$$ of $$x$$ satisfies $$A \cap \left({U - \left\{{a}\right\}}\right) \ne \varnothing$$.

(Informally speaking, $$x$$ is a limit point of $$A$$ if there are points in $$A$$ that are different from $$x$$ but arbitrarily close to it.)

Equivalently, $$x$$ is a limit point of $$A$$ if $$x$$ belongs to the closure of $$A$$ but is not an isolated point of $$A$$.

Definition from Open Set
A point $$x \in X$$ is called a limit point of $$A$$ if every open set $$U$$ of $$X$$ such that $$x \in U$$ contains some point of $$A$$ other than $$x$$.

Note that this definition is the same as the previous one if the definition of neighborhood is the one which insists that the neighborhood must be open in $$X$$.

Definition from Limit of Sequence
Let $$\left \langle {x_n} \right \rangle$$ be a sequence in $$A - \left\{{\alpha}\right\}$$ whose limit is $$\alpha$$.

Then $$\alpha$$ is a limit point of $$X$$.

Definition of Limit Points of Filters
Let $$\mathcal{F}$$ be a filter on $$X$$. A point $$x \in X$$ is called a limit point of $$\mathcal{F}$$ if $$x \in \bigcap \{ \overline{V} | V \in \mathcal{F} \}$$.

Simple Examples

 * $$0$$ is the only limit point of the set $$\left\{{1/n: n \in \N}\right\}$$ in the usual topology of $$\R$$.
 * Every point of $$\R$$ is a limit point of $$\R$$ in the usual topology.
 * In $$\R$$ under the usual topology, $$a$$ is a limit point of the open interval $$\left({a \, . \, . \, b}\right)$$ and also of the closed interval $$\left[{a \, . \, . \, b}\right]$$. Thus it can be seen that a limit point of a set may or may not be part of that set.
 * Any point $$x \in \R$$ is a limit point of the set of rational numbers $$\Q$$, because for any $$\epsilon > 0$$, there exists $$y \in \Q: y \in \left({x \, . \, . \, x + \epsilon}\right)$$ from Between Every Two Reals Exists a Rational. This is an interesting case, because $$\Q$$ is countable but its set of limit points in $$\R$$ is $$\R$$ itself, which is uncountable.
 * The set $$\Z$$ has no limit points in the usual topology of $$\R$$.