Cardinals form Equivalence Classes

Theorem
Let $\operatorname{Card} \left({S}\right)$ denote the cardinal of the set $S$.

Then $\operatorname{Card} \left({S}\right)$ forms an equivalence class which contains all sets which have the same cardinality as $S$.

Proof
Follows directly from:
 * The definition of a cardinal as $S \sim T \iff \operatorname{Card} \left({S}\right) = \operatorname{Card} \left({T}\right)$
 * Set Equivalence an Equivalence Relation
 * Relation Partitions a Set iff Equivalence.