Absolute Value of Integer is not less than Divisors

Theorem
A (non-zero) integer is greater than or equal to its divisors in magnitude:


 * $\forall c \in \Z_{\ne 0}: a \mathrel \backslash c \implies a \le \left\vert{a}\right\vert \le \left\vert{c}\right\vert$

It follows that a non-zero integer can have only a finite number of divisors, since they must all be less than or equal to it.

Proof
Suppose $a \mathop \backslash c, c \ne 0$.

From Negative of Absolute Value:
 * $a \le \left\vert{a}\right\vert$

Then: