Primitive of x cubed over Root of x squared minus a squared cubed

Theorem

 * $\displaystyle \int \frac {x^3 \rd x} {\paren {\sqrt {x^2 - a^2} }^3} = \sqrt {x^2 - a^2} - \frac {a^2} {\sqrt {x^2 - a^2} } + C$

for $\size x > a$.

Also see

 * Primitive of $\dfrac {x^3} {\paren {\sqrt {x^2 + a^2} }^3}$
 * Primitive of $\dfrac {x^3} {\paren {\sqrt {a^2 - x^2} }^3}$