65,536

Number
$65 \, 536$ (sixty-five thousand, five hundred and thirty-six) is:
 * $2^{16}$


 * The $256$th square number:
 * $65 \, 536 = 256 \times 256$


 * The $16$th fourth power after $1$, $16$, $81$, $256$, $625$, $1296$, $2401$, $4096$, $6561$, $10 \, 000$, $14 \, 641$, $20 \, 736$, $28 \, 561$, $38 \, 416$, $50 \, 625$:
 * $65 \, 536 = 16 \times 16 \times 16 \times 16$


 * The $4$th eighth power after $1$, $256$, $6561$:
 * $65 \, 536 = 4 \times 4 \times 4 \times 4 \times 4 \times 4 \times 4 \times 4$


 * The $16$th power of $2$ after $(1)$, $2$, $4$, $8$, $16$, $32$, $64$, $128$, $256$, $512$, $1024$, $2048$, $4096$, $8192$, $16 \, 384$, $32 \, 768$:
 * $65 \, 536 = 2^{16}$


 * The $8$th power of $4$ after $(1)$, $4$, $16$, $64$, $256$, $1024$, $4096$, $16 \, 384$:
 * $65 \, 536 = 4^8$


 * The $4$th power of $16$ after $(1)$, $16$, $256$, $4096$:
 * $65 \, 536 = 16^4$


 * The $17$th almost perfect number after $1$, $2$, $4$, $8$, $16$, $32$, $64$, $128$, $256$, $512$, $1024$, $2048$, $4096$, $8192$, $16 \, 384$, $32 \, 768$:
 * $\sigma \left({65 \, 536}\right) = 131 \, 071 = 2 \times 65 \, 536 - 1$


 * The only known power of $2$ whose digits do not contain $1$, $2$, $4$ or $8$.


 * The actual number of bytes in $64 \, \mathrm{KB}$ of computer memory.

Also see

 * Powers of 2 not containing Digit Power of 2