Modus Tollendo Ponens/Variant/Formulation 1/Reverse Implication

Theorem

 * $\neg p \implies q \vdash p \lor q$

Proof

 * align="right" | 2 ||
 * align="right" |
 * $p \lor \neg p$
 * LEM
 * (None)
 * (None)


 * align="right" | 6 ||
 * align="right" | 1, 5
 * $q$
 * $\implies \mathcal E$
 * 1, 5
 * 1, 5