Only Number which is Sum of 3 Factors is 6/Corollary

Corollary to Only Number which is Sum of 3 Factors is 6
$1$ can be expressed uniquely as the sum of $3$ distinct unit fractions:
 * $1 = \dfrac 1 2 + \dfrac 1 3 + \dfrac 1 6$

Proof
Suppose we have $1 = \dfrac 1 a + \dfrac 1 b + \dfrac 1 c$, where $a, b, c$ are distinct positive integers in ascending order.

Multiplying both sides by $m = \lcm \set {a, b, c}$:
 * $m = \dfrac m a + \dfrac m b + \dfrac m c$

Each fraction on the right is a factor of $m$.

Moreover, they must be comprime:

Suppose not. Then:
 * $\exists d > 1: d \divides \dfrac m a, \dfrac m b, \dfrac m c$

Then:
 * $\dfrac {m / d} a, \dfrac {m / d} b, \dfrac {m / d} c \in \Z$

Which shows that $\dfrac m d$ is a common multiple of $a, b, c$ less than $m$, a contradiction.

From Only Number which is Sum of 3 Factors is 6 we have:
 * $\dfrac m a = 3, \dfrac m b = 2, \dfrac m c = 1$

Their sum is:
 * $m = 3 + 2 + 1 = 6$

Thus:
 * $m = 3 a = 2 b = c = 6$

with the unique solution:
 * $\tuple {a, b, c} = {2, 3, 6}$