Talk:Product of Permuting Idempotent Elements is Idempotent

Do you really want the marginally more general result that is currently up or would it be fine to presume that all $f_i$ commute instead? Never encountered "permuting mappings". &mdash; Lord_Farin (talk) 07:36, 6 March 2013 (UTC)


 * As soon as you assume they all commute it gets quite thoroughly pointless. I don't know if this result is useful, mind you, but it arose as a natural generalization of the stronger result for mappings that commute. --Dfeuer (talk) 07:42, 6 March 2013 (UTC)