Group Element Commutes with Inverse

Theorem
Let $\left({G, \circ}\right)$ be a group whose identity is $e$.

Let $x \in G$.

Then:
 * $x \circ x^{-1} = x^{-1} \circ x$

That is, $x$ commutes with its inverse $x^{-1}$.

Proof
By definition of inverse element:


 * $x \circ x^{-1} = e = x^{-1} \circ x$

Hence the result by definition.