Ideals Containing Ideal Form Lattice

Theorem
Let $J$ be an ideal of a ring $R$.

Let $\mathbb L_J$ be the set of all ideal of $R$ which contain $J$.

Then the ordered set $\left({\mathbb L_J, \subseteq}\right)$ is a lattice.

Proof
Let $b_1, b_2 \in \mathbb L_J$.

Then from Set of Ideals forms Complete Lattice:


 * $(1): \quad b_1 + b_2 \in \mathbb L_J$ and is the supremum of $\left\{{b_1, b_2}\right\}$
 * $(2): \quad b_1 \cap b_2 \in \mathbb L_J$ and is the infimum of $\left\{{b_1, b_2}\right\}$

Thus $\left({\mathbb L_J, \subseteq}\right)$ is a lattice.