Talk:Null Ring is Ring

There's actually no need for all this. All you need to do is show that $(R,+)$ is a group (the trivial group) and then exhibit the fact that $\forall a \in R: a \circ a = 0_R$ which shows that $R$ is a trivial ring. Trivial rings are shown to be rings.

This is why I originally had this page as a redirect to Null Ring is Trivial Ring.

But never mind, you seem keen - I'll leave you to finish this all off, as we're having edit conflicts. --prime mover 15:50, 19 April 2012 (EDT)