Natural Number Multiplication is Commutative/Proof 1

Theorem
The operation of multiplication on the set of natural numbers $\N$ is commutative:
 * $\forall x, y \in \N: x \times y = y \times x$

Proof
We have that the Natural Numbers form Naturally Ordered Semigroup whose operation is addition.

The result follows from Multiplication in Naturally Ordered Semigroup is Commutative.