Talk:Reciprocal Function is Strictly Decreasing

Okay, so maybe I didn't word this too well when I raised the issue ... but as it stands the statement is fallacious. It's s.d. on either $\R_{>0}$ or $\R_{<0}$ but not on $\R_{\ne 0} = \R \setminus \left\{{0}\right\}$ because e.g. $\dfrac 1 {-1} < \dfrac 1 1$. Sorry, I kinda assumed that would be taken care of. --prime mover 16:49, 3 August 2012 (UTC)


 * ... and yes I know, Ordering of Reciprocals is wrong too. Needs to be looked at. --prime mover 16:52, 3 August 2012 (UTC)