Area of Trapezoid

Theorem

 * TrapezoidArea.png

Let $ABCD$ be a trapezoid:
 * whose parallel sides are of lengths $a$ and $b$

and
 * whose height is $h$.

Then the area of $ABCD$ is given by:


 * $\Box ABCD = \dfrac {h \left({a + b}\right)} 2$

Proof

 * TrapezoidAreaProof.png

Extend line $AB$ to $E$ by length $a$.

Extend line $DC$ to $F$ by length $b$.

Then $BECF$ is another trapezoid whose parallel sides are of lengths $a$ and $b$ and whose height is $h$.

Also, $AEFD$ is a parallelogram which comprises the two trapezoids $ABCD$ and $BECF$.

$AEFD$ is of height $h$ with sides of length $a + b$.

Thus from Area of Parallelogram the area of $AEFD$ is given by:
 * $\Box AEFD = h \left({a + b}\right)$

So $\Box ABCD + \Box BECF = \Box AEFD$ and $\Box ABCD = \Box BECF$.

It follows that $\Box ABCD = \dfrac {h \left({a + b}\right)} 2$