239

Number
$239$ (two hundred and thirty-nine) is:


 * The $52$nd prime number.


 * The $1$st of the $17$th pair of twin primes, with $241$


 * The $17$th Sophie Germain prime after $2, 3, 5, 11, 23, 29, 41, 53, 83, 89, 113, 131, 173, 179, 191, 233$:
 * $2 \times 239 + 1 = 479$, which is prime.


 * The $39$th happy number after $1, 7, 10, 13, 19, 23, \ldots, 188, 190, 192, 193, 203, 208, 219, 226, 230, 236$:
 * $239 \to 2^2 + 3^2 + 9^2 = 4 + 9 + 81 = 94 \to 9^2 + 4^2 = 81 + 16 = 97 \to 9^2 + 7^2 = 81 + 49 = 130 \to 1^2 + 3^2 + 0^2 = 1 + 9 + 0 = 10 \to 1^2 + 0^2 = 1$


 * The $2$nd of the only two positive integers needing as many as $9$ positive cubes to express it:
 * $239 = 4^3 + 4^3 + 3^3 + 3^3 + 3^3 + 3^3 + 1^3 + 1^3 + 1^3$
 * The other is $23$.


 * The $3$rd positive integer after $79$, $159$ which cannot be expressed as the sum of fewer than $19$ fourth powers:
 * $239 = 13 \times 1^4 + 4 \times 2^4 + 2 \times 3^4$


 * The largest integer such that the largest prime factor of $n^2 + 1$ is less than $17$:
 * $239^2 + 1 = 57122 = 2 \times 13^4$


 * With $y = 13$, the only $x$ which is the solution of the indeterminate Diophantine equation $x^2 + 1 = 2 y^4$:
 * $239^2 + 1 = 2 \times 13^4$

Also see

 * Numbers not Expressible as Sum of Less than 9 Positive Cubes
 * Largest Prime Factor of n squared plus 1
 * Solution of Diophantine Equation $x^2 + 1 = 2 y^4$