De Morgan's Laws (Logic)/Conjunction/Formulation 1/Reverse Implication

Theorem

 * $\neg \left({\neg p \lor \neg q}\right) \vdash p \land q$

Proof

 * align="right" | 5 ||
 * align="right" | 1
 * $p \land q$
 * Reductio Ad Absurdum
 * 2-4
 * }
 * }
 * }