Combination Theorem for Continuous Mappings/Topological Group/Multiple Rule

Theorem
Let $\struct{S, \tau_S}$ be a topological space.

Let $\struct{G, *, \tau_G}$ be a topological group.

Let $\lambda \in G$.

Let $f : \struct{S, \tau_S} \to \struct{G, \tau_G}$ be a continuous mapping.

Let $\lambda * f : S \to G$ be the mapping defined by:
 * $\forall x \in S: \map {\paren{\lambda * f}} x = \lambda * \map f x$

Let $f * \lambda : S \to G$ be the mapping defined by:
 * $\forall x \in S: \map {\paren{f * \lambda}} x = \map f x * \lambda$

Then:
 * $\lambda * f : \struct{S, \tau_S} \to \struct{G, \tau_G}$ is a continuous mapping
 * $f * \lambda : \struct{S, \tau_S} \to \struct{G, \tau_G}$ is a continuous mapping.

Proof
By definition, a topological group is a topological semigroup.

Hence $\struct{G, *, \tau_G}$ is a topological semigroup.

From Multiple Rule for Continuous Mappings to Topological Semigroup, $\lambda * f, f * \lambda : \struct{S, \tau_S} \to \struct{G, \tau_G}$ are a continuous mappings.