536,870,912

Number
$536 \, 870 \, 912$ (five hundred and thirty-six million, eight hundred and seventy thousand, nine hundred and twelve) is:
 * $2^{29}$


 * The $29$th power of $2$:
 * $536 \, 870 \, 912 = 2^{29}$


 * The $30$th almost perfect number:
 * $\map {\sigma_1} {536 \, 870 \, 912} = 1 \, 073 \, 741 \, 823 = 2 \times 536 \, 870 \, 912 - 1$


 * Of particular interest, as it is almost pandigital: only $4$ is missing.