Equivalence of Definitions of Locally Connected Space/Definition 1 implies Definition 3

Theorem
Let $T = \struct{S, \tau}$ be a topological space. Let each point $x$ of $T$ have a local basis $\DD_x$ consisting entirely of connected sets in $T$.

Then
 * $T$ has a basis consisting of connected sets in $T$.

Proof
By definition of local basis, each of these connected sets in $\DD_x$ is open in $T$.

Consider the set $\ds \DD = \bigcup_{x \mathop \in S} \DD_x$.

From Union of Local Bases is Basis, $\DD$ is a basis for the topology $\tau$.

Since each $\DD_x$ consists entirely of connected sets, $\DD$ also consists entirely of connected sets.