Complement of Bottom/Bounded Lattice

Theorem
Let $\left({S, \vee, \wedge, \preceq}\right)$ be a bounded lattice.

Then the bottom $\bot$ has a unique complement, namely $\top$, top.

Proof
We know that $\bot$ is the identity for $\vee$.

Therefore, from the condition that:


 * $\bot \vee a = \top$

for a complement $a$ of $\bot$, it follows that $a = \top$ is the only possibility.

Since also:


 * $\bot \wedge \top = \bot$

as $\top$ is the identity for $\wedge$, the result follows.

Also see

 * Complement of Top