External Angle of Triangle equals Sum of other Internal Angles/Proof 2

Proof
Let $\triangle ABC$ be a triangle.

From Sum of Angles of Triangle equals Two Right Angles: Proof 2:
 * $\paren 1: \angle ABC + \angle BCA + \angle CAB = 180^\circ$

Extend $AB$ to $D$.

By Two Angles on Straight Line make Two Right Angles:
 * $\paren 1: \angle ABC + \angle CBD = 180^\circ$

Combining $\paren 1$ and $\paren 2$ and using Equality is Transitive:
 * $\angle ABC + \angle BCA + \angle CAB = \angle ABC + \angle CBD$

By using commom notion 3:
 * $\angle BCA + \angle CAB = \angle CBD$

By using Equality is Symmetric:
 * $\angle CBD = \angle BCA + \angle CAB$