G-Tower is Well-Ordered under Subset Relation/Corollary

Corollary to $g$-Tower is Well-Ordered under Subset Relation
Let $M$ be a class.

Let $g: M \to M$ be a progressing mapping on $M$.

Let $M$ be a $g$-tower.

Let $y \in M$ other than $\O$.

Then the strict lower closure $y^\subset$ of $y$ is non-empty and exactly one of the following conditions holds:


 * $(1): \quad y^\subset$ has a greatest element $x$ and $\map g x = y$


 * $(2): \quad y^\subset$ has no greatest element $x$ and $\ds \bigcup y^\subset = y$

Proof
We have $y \ne \O$.

Then $y$ is not the smallest element of $M$.

Hence $\O \in y^\subset$ and $y^\subset$ is non-empty.

The result follows from $g$-Tower is Well-Ordered under Subset Relation, taking $A = \set y$.

The smallest element of $\set y$ is of course $y$ itself.