Talk:Ordering of Reciprocals

WRONG! $-1 < 1$ and $\dfrac 1 {-1} < \dfrac 1 1$. --prime mover 16:53, 3 August 2012 (UTC)


 * Fixed. --prime mover 16:54, 3 August 2012 (UTC)


 * It holds for $x<0,y<0$ also, doesn't it? --GFauxPas 10:55, 5 August 2012 (UTC)


 * Yes; I think a corollary would be just fine. --Lord_Farin 11:02, 5 August 2012 (UTC)

Refactoring request
Let me remind you that the old version also used abstruse algebraic ideas, but it was much less specific about what it was doing and it was also incomplete. I've added (back?) a second proof that I wrote that uses less abstract nonsense. I'd really like to make the underlying theorems of the abstract nonsense version easier to understand. They are not inherently complicated, but the (my) explanations, and the terminology, are terrible. --Dfeuer (talk) 21:19, 22 February 2013 (UTC)


 * Many of the issues on tend to concern mainly the trivial, since it's glossed over so often that we don't realise presentation isn't rigorous until we try and cover it. Such is life. &mdash; Lord_Farin (talk) 22:21, 22 February 2013 (UTC)