Polynomial Addition is Commutative

Theorem
Addition of polynomials is commutative.

Proof
Let $(R, +, \circ)$ be a commutative ring with unity with zero $0_R$.

Let $\left\{{X_j: j \in J}\right\}$  be a set of indeterminates.

Let $Z$ be the set of all multiindices indexed by $\left\{{X_j: j \in J}\right\}$.

Let


 * $\displaystyle f = \sum_{k\in Z} a_k \mathbf X^k$


 * $\displaystyle g = \sum_{k\in Z} b_k \mathbf X^k$

be a arbitrary polynomials in the   indeterminates $\left\{{X_j: j   \in J}\right\}$ over $R$.

Then

Therefore, $f + g = g + f$ for all polynomials $f$ and $g$.

Therefore, polynomial addition is commutative.