G-Delta Sets Closed under Intersection

Theorem
Let $T = \left({S, \vartheta}\right)$ be a topological space.

Let $G, G'$ be $G_\delta$ sets of $T$.

Then their intersection $G \cap G'$ is also a $G_\delta$ set of $T$.

Proof
By definition of $G_\delta$ set, there exist sequences $\left({U_n}\right)_{n \in \N}$ and $\left({U'_n}\right)_{n \in \N}$ of open sets of $T$ such that:


 * $G = \displaystyle \bigcap_{n \mathop \in \N} U_n$
 * $G' = \displaystyle \bigcap_{n \mathop \in \N} U'_n$

By General Distributivity of Intersection, we have:


 * $G \cap G' = \displaystyle \bigcap_{n \mathop \in \N} \left({U_n \cap U'_n}\right)$

By Intersection of Closed Sets is Closed, $U_n \cap U'_m$ is closed, for all $n, m \in \N$.

Thus $G \cap G'$ is seen to be a $G_\delta$ set.

Also see

 * $G_\delta$ Sets Closed under Union
 * $F_\sigma$ Sets Closed under Intersection