Jump Discontinuity/Examples/Example 3

Example of Jump Discontinuity
Let $f: \R \to \R$ be the real function defined as:
 * $\forall x \in \R: \map f x = \begin {cases} -1 & : x < 0 \\ 1 & : x > 0 \\ \text {undefined} & : x = 0 \end {cases}$

Then $f$ has a jump discontinuity at $x = 1$.

In this case, $\map f 0$ is not defined.


 * Jump-discontinuity-at-0.png