Quasigroup is not necessarily B-Algebra

Theorem
Let $\struct {S, \circ}$ be a quasigroup.

Then $\struct {S, \circ}$ is not necessarily a $B$-algebra.

Proof
As all groups are quasigroups we will use a small group as a counterexample.

Consider the Cayley table of the group of order $3$:


 * $\begin{array}{c|cccccc}

& 0 & 1 & 2 \\ \hline 0 & 0 & 1 & 2 \\ 1 & 1 & 2 & 0 \\ 2 & 2 & 0 & 1 \\ \end{array}$

By inspection we see that $B$-algebra axiom $(\text A 2)$ does not hold as $1 \circ 1 \ne 0$.

Also see

 * $B$-Algebra is Quasigroup