100 using Digits from 1 to 9
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Classic Problem
Using just the digits $1$ to $9$ in order (ascending and descending), using the usual operations ($+$, $-$, $\times$, $\div$) and brackets, how can you make $100$?
Solution
There are many answers:
- $1 + 2 + 3 + 4 + 5 + 6 + 7 + \paren {8 \times 9} = 100$
- $123 - 45 - 67 + 89 = 100$
Using the digits in reverse order:
- $98 - 76 + 54 + 3 + 21 = 100$
... and of course the initial answer:
- $\paren {9 \times 8} + 7 + 6 + 5 + 4 + 3 + 2 + 1$
$\blacksquare$
Historical Note
This puzzle was posed, and solutions provided, by Henry Ernest Dudeney.
Sources
- 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $100$
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $100$