121

Number

$121$ (one hundred and twenty-one) is:

$11^2$

The $1$st of the two square numbers which is the sum of consecutive powers of a positive integer:

$121 = 3^0 + 3^1 + 3^2 + 3^3 + 3^4$

The $2$nd power of $11$ after $(1)$, $11$:

$121 = 11^2$

The $2$nd square number after $25$ of the form $n! + 1$:

$121 = 5! + 1 = 11^2$

where $!$ denotes the factorial function.

$3^{121} \equiv 3 \pmod {121}$

The $2$nd (with $4$) of the $2$ square numbers which are $4$ less than a cube:

$121 = 11^2 = 5^3 - 4$

$121 = \map {\sigma_1} {81}$

The $6$th integer after $0$, $1$, $2$, $4$, $8$ which is palindromic in both decimal and ternary:

$121_{10} = 11 \, 111_3$

The $7$th Smith number after $4$, $22$, $27$, $58$, $85$, $94$:

$1 + 2 + 1 = 1 + 1 + 1 + 1 = 4$

The $9$th positive integer which cannot be expressed as the sum of a square and a prime:

$1$, $10$, $25$, $34$, $58$, $64$, $85$, $91$, $121$, $\ldots$

The $9$th palindromic integer after $0$, $1$, $2$, $3$, $11$, $22$, $101$, $111$ whose square is also palindromic integer

$121^2 = 14 \, 641$

The $10$th square after $1$, $4$, $9$, $16$, $25$, $36$, $49$, $64$, $81$ which has no more than $2$ distinct digits and does not end in $0$:

$121 = 11^2$

The $11$th square number after $1$, $4$, $9$, $16$, $25$, $36$, $49$, $64$, $81$, $100$:

$121 = 11 \times 11$

The $16$th powerful number after $1$, $4$, $8$, $9$, $16$, $25$, $27$, $32$, $36$, $49$, $64$, $72$, $81$, $100$, $108$

The $39$th semiprime:

$121 = 11 \times 11$

No further terms of this sequence are documented on $\mathsf{Pr} \infty \mathsf{fWiki}$.