3,719,048,256

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Number

$3 \, 719 \, 048 \, 256$ is:

$2^6 \times 3^4 \times 7^2 \times 11^4$

The $60 \, 984$th square number:

$3 \, 719 \, 048 \, 256 = 60 \, 984 \times 60 \, 984$

The square of the larger of both the $1$st and the $2$nd pandigital pairs, with $35 \, 172$ and $57 \, 321$, of integers each have squares which are themselves pandigital:

$35 \, 172^2 = 1 \, 237 \, 069 \, 584$, $60 \, 984^2 = 3 \, 719 \, 048 \, 256$

$57 \, 321^2 = 3 \, 285 \, 697 \, 041$, $60 \, 984^2 = 3 \, 719 \, 048 \, 256$

Also see

• Pandigital Pairs whose Squares are Pandigital

Sources

• 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $57,321$