3403

Previous  ... Next

Number

$3403$ (three thousand, four hundred and three) is:

$41 \times 83$

The $82$nd triangular number after $1$, $3$, $6$, $10$, $15$, $\ldots$, $2701$, $2775$, $2850$, $2926$, $3003$, $3081$, $3160$, $3240$, $3321$:

$3403 = \ds \sum_{k \mathop = 1}^{82} k = \dfrac {82 \times \paren {82 + 1} } 2$

Also see

• Previous  ... Next: Triangular Number