Abel's Test
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Theorem
Let $\ds \sum a_n$ be a convergent real series.
Let $\sequence {b_n}$ be a decreasing sequence of positive real numbers.
Then the series $\ds \sum a_n b_n$ is also convergent.
Abel's Test for Uniform Convergence
Let $\sequence {\map {a_n} z}$ and $\sequence {\map {b_n} z}$ be sequences of complex functions on a compact set $K$.
Let $\sequence {\map {a_n} z}$ be such that:
- $\sequence {\map {a_n} z}$ is bounded in $K$
- $\ds \sum \size {\map {a_n} z - \map {a_{n + 1} } z}$ is convergent with a sum which is bounded in $K$
- $\ds \sum \map {b_n} z$ is uniformly convergent in $K$.
Then $\ds \sum \map {a_n} z \map {b_n} z$ is uniformly convergent on $K$.
Proof
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Source of Name
This entry was named for Niels Henrik Abel.
Sources
- 1989: Ephraim J. Borowski and Jonathan M. Borwein: Dictionary of Mathematics ... (previous) ... (next): Abel's test: 1.
- 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): Abel's test
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): Abel's test
- 2014: Christopher Clapham and James Nicholson: The Concise Oxford Dictionary of Mathematics (5th ed.) ... (previous) ... (next): Abel's test