Accumulation Point of Sequence of Distinct Terms is Omega-Accumulation Point of Range

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $T = \struct {S, \tau}$ be a topological space.

Let $\sequence {x_n}$ be a sequence of distinct terms of $S$.

Let $\alpha$ be an accumulation point of $\sequence {x_n}$.


Then $\alpha$ is also an $\omega$-accumulation point of $\set {x_n: n \in \N}$.


Proof

Let $U$ be an open set of $T$ containing $\alpha$.

By definition of accumulation point of $\sequence {x_n}$, $U$ contains infinitely many terms of $\sequence {x_n}$.

As $\sequence {x_n}$ is a sequence of distinct terms: $U$ contains infinitely many elements of $\set {x_n: n \in \N}$.

Thus by definition $\alpha$ is an $\omega$-accumulation point of $\set {x_n: n \in \N}$.

$\blacksquare$


Sources