Analytic Continuation of Dirichlet L-Function
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Theorem
Let $\chi : G := \paren {\Z / q \Z}^\times \to \C^\times$ be a Dirichlet character modulo $q$.
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Let $\map L {s, \chi}$ be the Dirichlet $L$-function for $\chi$.
Let $\chi$ be the trivial character.
Then $\map L {s, \chi}$ has an analytic continuation to $\C$ except for a simple pole at $s = 1$.
Let $\chi$ be non-trivial.
Then $\map L {s, \chi}$ is analytic on $\map \Re s > 0$.
Proof
Let $\chi$ be the trivial character.
Then by Dirichlet L-Function from Trivial Character:
- $\ds \map L {s, \chi} = \map \zeta s \cdot \prod_{p \mathop \divides q} \paren {1 - p^{-s} }$
where $\divides$ denotes divisibility.
Also, by Poles of Riemann Zeta Function, $\zeta$ is analytic on $\C$ except for a simple pole at $s = 1$.
Since $\map L {s, \chi}$ is just $\zeta$ times some constant, the same holds for this function.
If $\chi$ is non-trivial, then by the Orthogonality Relations for Characters:
- $\ds \sum_{x \mathop \in G} \map \chi x = 0$
By definition, $\chi$ is $q$-periodic, and zero on integers not coprime to $q$.
So for any $M \in \N$:
- $\ds \sum_{n \mathop = M + 1}^{M + Q} \map \chi n = 0$
Let $M, N \in \N$ be arbitrary.
Let $d$ be such that $M + q d \le N \le M + q \paren {d + 1}$.
Then:
\(\ds \sum_{n \mathop = M}^N \map \chi n\) | \(=\) | \(\ds \sum_{k \mathop = 0}^{d - 1} \sum_{n \mathop = 0}^{q - 1} \map \chi {M + k q + n} + \sum_{n \mathop = M + q d}^N \map \chi n\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \sum_{n \mathop = M \mathop + q d}^N \map \chi n\) | because $\chi$ is $q$-periodic, and zero on integers not coprime to $q$ | |||||||||||
\(\ds \) | \(\le\) | \(\ds q\) | because $\size {N - M + q d} \le q$ |
So the coefficients $\map \chi n$ of $\map L {s, \chi}$ have bounded partial sums.
Therefore, by Convergence of Dirichlet Series with Bounded Partial Sums, $\map L {s, \chi}$ converges locally uniformly to an analytic function on $\map \Re s > 0$.
$\blacksquare$
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