Anomalous Cancellation on 2-Digit Numbers/Example/49 over 98

Theorem

The fraction $\dfrac {49} {98}$ exhibits the phenomenon of anomalous cancellation:

$\dfrac {49} {98} = \dfrac 4 8$

as can be seen by deleting the $9$ from both numerator and denominator.

This is part of a longer pattern:

$\dfrac 4 8 = \dfrac {49} {98} = \dfrac {499} {998} = \dfrac {4999} {9998} = \cdots$