Area Enclosed by First Turn of Archimedean Spiral
Jump to navigation
Jump to search
Theorem
Let $S$ be the Archimedean spiral defined by the equation:
- $r = a \theta$
The area $\AA$ enclosed by the first turn of $S$ and the polar axis is given by:
- $\AA = \dfrac {4 \pi^3 a^2} 3$
Proof
\(\ds \AA\) | \(=\) | \(\ds \int_0^{2 \pi} \frac {\paren {a \theta}^2} 2 \rd \theta\) | Area between Radii and Curve in Polar Coordinates‎ | |||||||||||
\(\ds \) | \(=\) | \(\ds \intlimits {\frac {a^2 \theta^3} 6} 0 {2 \pi}\) | Primitive of Power | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac {\paren {2 \pi}^3 a^2} 6\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac {4 \pi^3 a^2} 3\) | after simplification |
$\blacksquare$
Historical Note
The Area Enclosed by First Turn of Archimedean Spiral was first determined by Archimedes in his book On Spirals.
His proof appears as Proposition $24$.
Sources
- 1992: George F. Simmons: Calculus Gems ... (previous) ... (next): Chapter $\text {A}.5$: Archimedes (ca. $\text {287}$ – $\text {212}$ B.C.)