Axiom:Axiom of Continuity

From ProofWiki
Jump to: navigation, search


Axiom Schema

This is more properly an collection of axioms rather than a single axiom.

Let $a,b,x,y,$ be points.

Let $\mathsf{B}$ be the relation of betweenness.


Let $\alpha, \beta$ be first-order formulas.

Let $\alpha$ contain no free occurrences of $a,b,y$.

Let $\beta$ contain no free occurrences of $a,b,x$.


This axiom asserts:

\(\displaystyle \) \(\) \(\displaystyle \exists a: \forall x,y: \left({ \alpha \land \beta \implies \mathsf{B}axy }\right)\) $\quad$ $\quad$
\(\displaystyle \) \(\implies\) \(\displaystyle \exists b: \forall x,y: \left({ \alpha \land \beta \implies \mathsf{B}xby }\right)\) $\quad$ $\quad$


Alternative form

Let $\mathsf{B}$ be the relation of betweenness.


This axiom asserts:

$\left({\exists a : \forall x,y : \left({x \in X \land y \in Y}\right)\implies \mathsf{B}axy}\right) \implies \left({\exists b : \forall x,y : \left({x \in X \land y \in Y}\right)\implies \mathsf{B}xby}\right)$

where $a,b,x,y$ are points and $X, Y$ are point sets.


Note that this alternate form of the Axiom of Continuity assumes the existence of sets.

As such, it cannot be expressed in the framework of first-order logic.


Intuition

Consider an infinite line.

Consider it as consisting of a left side and a right side, where the transition is any place you care to choose.

No matter what place you choose, that place of transition is a point.


Also see


Sources