Between two Rational Numbers exists Irrational Number/Lemma 2
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Lemma for Between two Rational Numbers exists Irrational Number
Let $\alpha \in \Q$ and $\beta \in \R \setminus \Q$.
Then:
- $\alpha + \beta \in \R \setminus \Q$
Proof
Aiming for a contradiction, suppose $\alpha + \beta \in \Q$.
By the definition of rational numbers:
- $\exists p, q \in \Z: \alpha + \beta = \dfrac p q$
Thus:
- $\beta = \dfrac p q - \alpha$
By Rational Subtraction is Closed, we have $\beta \in \Q$, which contradicts the statement that $\beta \in \R \setminus \Q$.
Therefore:
- $\alpha + \beta \in \R \setminus \Q$
$\blacksquare$