Biconditional is Transitive

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Theorem

The biconditional operator is transitive:


Formulation 1

$p \iff q, q \iff r \vdash p \iff r$


Formulation 2

$\vdash \left({\left({p \iff q}\right) \land \left({q \iff r}\right)}\right) \implies \left({p \iff r}\right)$