Boolean Prime Ideal Theorem/Proof 2

From ProofWiki
Jump to navigation Jump to search


Let $\struct {S, \le}$ be a Boolean algebra.

Let $I$ be an ideal in $S$.

Let $F$ be a filter on $S$.

Let $I \cap F = \O$.

Then there exists a prime ideal $P$ in $S$ such that:

$I \subseteq P$


$P \cap F = \O$


We prove that the Boolean Prime Ideal Theorem is equivalent to the Ultrafilter Lemma in ZF.