Capelli's Sum
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Theorem
- $\ds \paren {x + y}^{\overline n} = \sum_k \binom n k x^{\overline k} y^{\overline {n - k} }$
where:
- $\dbinom n k$ denotes a binomial coefficient
- $x^{\overline k}$ denotes $x$ to the $k$ rising.
Proof
The proof proceeds by induction on $n$.
For all $n \in \Z_{> 0}$, let $\map P n$ be the proposition:
- $\ds \paren {x + y}^{\overline n} = \sum_k \binom n k x^{\overline k} y^{\overline {n - k} }$
Basis for the Induction
$\map P 1$ is the case:
\(\ds \paren {x + y}^{\overline 1}\) | \(=\) | \(\ds x^{\overline 1} + y^{\overline 1}\) | Number to Power of One Rising is Itself | |||||||||||
\(\ds \) | \(=\) | \(\ds x^{\overline 0} y^{\overline 1} + x^{\overline 1} y^{\overline 0}\) | Number to Power of Zero Rising is One | |||||||||||
\(\ds \) | \(=\) | \(\ds \binom 1 0 x^{\overline 0} y^{\overline 1} + \binom 1 1 x^{\overline 1} y^{\overline 0}\) | One Choose n | |||||||||||
\(\ds \) | \(=\) | \(\ds \sum_k \binom 1 k x^{\overline k} y^{\overline {1 - k} }\) |
Thus $\map P 1$ is seen to hold.
This is the basis for the induction.
Induction Hypothesis
Now it needs to be shown that, if $\map P m$ is true, where $m \ge 1$, then it logically follows that $\map P {m + 1}$ is true.
So this is the induction hypothesis:
- $\ds \paren {x + y}^{\overline m} = \sum_k \binom m k x^{\overline k} y^{\overline {m - k} }$
from which it is to be shown that:
- $\ds \paren {x + y}^{\overline {m + 1} } = \sum_k \binom {m + 1} k x^{\overline k} y^{\overline {m + 1 - k} }$
Induction Step
This is the induction step:
\(\ds \paren {x + y}^{\overline {m + 1} }\) | \(=\) | \(\ds \paren {x + y}^{\overline m} \paren {x + y + m}\) | Definition of Rising Factorial | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {\sum_k \binom m k x^{\overline k} y^{\overline {m - k} } } \paren {x + y + m}\) | Induction Hypothesis | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {\sum_k \binom m k x^{\overline k} y^{\overline {m - k} } } \paren {x + k + y + m - k}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \sum_k \binom m k x^{\overline k} \paren {x + k} y^{\overline {m - k} } + \sum_k \binom m k x^{\overline k} y^{\overline {m - k} } \paren {y + m - k}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \sum_k \binom m k x^{\overline {k + 1} } y^{\overline {m - k} } + \sum_k \binom m k x^{\overline k} y^{\overline {m - k + 1} }\) | Definition of Rising Factorial | |||||||||||
\(\ds \) | \(=\) | \(\ds \sum_k \binom m k x^{\overline {k + 1} } y^{\overline {m - k} } + \sum_k \binom m {k + 1} x^{\overline {k + 1} } y^{\overline {m - k} }\) | Translation of Index Variable of Summation | |||||||||||
\(\ds \) | \(=\) | \(\ds \sum_k \binom {m + 1} k x^{\overline {k + 1} } y^{\overline {m - k} }\) | Pascal's Rule |
So $\map P m \implies \map P {m + 1}$ and the result follows by the Principle of Mathematical Induction.
Therefore:
- $\ds \forall n \in \Z_{> 0}: \paren {x + y}^{\overline n} = \sum_k \binom n k x^{\overline k} y^{\overline {n - k} }$
$\blacksquare$
Source of Name
This entry was named for Alfredo Capelli.
Sources
- 1893: Alfredo Capelli: L'analisi algebrica e l'interpretazione fattoriale delle potenze (Giornale di Matematiche di Battaglini Vol. 31: pp. 291 – 313)
- 1997: Donald E. Knuth: The Art of Computer Programming: Volume 1: Fundamental Algorithms (3rd ed.) ... (previous) ... (next): $\S 1.2.6$: Binomial Coefficients: Exercise $33$