Carmichael Number with 4 Prime Factors
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Theorem
$41 \, 041$ is the smallest Carmichael number with $4$ prime factors:
- $41 \, 041 = 7 \times 11 \times 13 \times 41$
Proof
From Sequence of Carmichael Numbers:
The sequence of Carmichael numbers begins:
- $561, 1105, 1729, 2465, 2821, 6601, 8911, 10585, 15841, \ldots$
The sequence continues:
- $\ldots, 29 \, 341, 41 \, 041$
We now investigate their prime factors:
\(\ds 561\) | \(=\) | \(\ds 3 \times 11 \times 17\) | ||||||||||||
\(\ds 1105\) | \(=\) | \(\ds 5 \times 13 \times 17\) | ||||||||||||
\(\ds 1729\) | \(=\) | \(\ds 7 \times 13 \times 19\) | ||||||||||||
\(\ds 2465\) | \(=\) | \(\ds 5 \times 17 \times 29\) | ||||||||||||
\(\ds 2821\) | \(=\) | \(\ds 7 \times 13 \times 31\) | ||||||||||||
\(\ds 6601\) | \(=\) | \(\ds 7 \times 23 \times 41\) | ||||||||||||
\(\ds 8911\) | \(=\) | \(\ds 7 \times 19 \times 67\) | ||||||||||||
\(\ds 10 \, 585\) | \(=\) | \(\ds 5 \times 29 \times 73\) | ||||||||||||
\(\ds 15 \, 841\) | \(=\) | \(\ds 7 \times 31 \times 73\) | ||||||||||||
\(\ds 29 \, 341\) | \(=\) | \(\ds 13 \times 37 \times 61\) | ||||||||||||
\(\ds 41 \, 041\) | \(=\) | \(\ds 7 \times 11 \times 13 \times 41\) |
$\blacksquare$
Sources
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $41,041$