Cartesian Product of Intersections/Corollary 1
Jump to navigation
Jump to search
Corollary to Cartesian Product of Intersections
- $A \times \paren {B \cap C} = \paren {A \times B} \cap \paren {A \times C}$
Proof
Take the result Cartesian Product of Intersections:
- $\paren {S_1 \cap S_2} \times \paren {T_1 \cap T_2} = \paren {S_1 \times T_1} \cap \paren {S_2 \times T_2}$
Put $S_1 = S_2 = A, T_1 = B, T_2 = C$:
\(\ds A \times \paren {B \cap C}\) | \(=\) | \(\ds \paren {A \cap A} \times \paren {B \cap C}\) | Set Intersection is Idempotent | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {A \times B} \cap \paren {A \times C}\) | Cartesian Product of Intersections |
$\blacksquare$
Sources
- 1965: J.A. Green: Sets and Groups ... (previous) ... (next): Chapter $1$. Sets: Exercise $8 \ \text{(i)}$
- 1971: Robert H. Kasriel: Undergraduate Topology ... (previous) ... (next): $\S 1.9$: Cartesian Product: Theorem $9.2$
- 1975: T.S. Blyth: Set Theory and Abstract Algebra ... (previous) ... (next): $\S 3$. Ordered pairs; cartesian product sets: Exercise $3 \ (1)$