Category:Power Series Expansion for Reciprocal of Cube of 1 + x

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This category contains pages concerning Power Series Expansion for $\dfrac 1 {\paren {1 + x}^3}$:


Let $x \in \R$ such that $-1 < x < 1$.

Then:

\(\ds \dfrac 1 {\paren {1 + x}^3}\) \(=\) \(\ds \sum_{k \mathop = 0}^\infty \paren {-1}^k \frac {\paren {k + 2} \paren {k + 1} } 2 x^k\)
\(\ds \) \(=\) \(\ds 1 - 3 x + 6 x^2 - 10 x^3 + 15 x^4 - \cdots\)

Pages in category "Power Series Expansion for Reciprocal of Cube of 1 + x"

The following 3 pages are in this category, out of 3 total.