Cauchy-Goursat Theorem/Examples/z squared over e to the it
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Example of Use of Cauchy-Goursat Theorem
Let $\map \gamma t = e^{i t}$.
Let the domain of $\gamma$ be $\hointr 0 {2 \pi}$.
Let $\map f z = z^2$.
Then:
- $\ds \oint_\gamma \map f z \rd z = 0$
Proof
\(\ds \oint_\gamma \map f z \rd z\) | \(=\) | \(\ds \int_0^{2 \pi} i e^{i t} e^{2 i t} \rd t\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds i \int_0^{2 \pi} e^{3 i t} \rd t\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac i {3 i} \paren {e^{6 i \pi} - e^{i 0} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 3 \paren {\cos 6 \pi + i \sin 6 \pi - \cos 0 - i \sin 0}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 3 \paren {1 - 1}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 0\) |
$\blacksquare$