Central Field is Field of Functional
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Theorem
Let $\mathbf y$ be an $N$-dimensional vector.
Let $J$ be a functional, such that:
- $\ds J \sqbrk {\mathbf y} = \int_a^b \map F {x, \mathbf y, \mathbf y'} \rd x$
Let the following be a central field:
- $\map {\mathbf y'} x = \map {\boldsymbol \psi} {x, \mathbf y}$
Then this central field is a field of functional $J$.
Proof
Suppose:
- $\ds \map g {x, \mathbf y} = \int_c^{\paren {x, \mathbf y} } \map F {x, \hat {\mathbf y}, \hat {\mathbf y}'} \rd x$
where $\hat {\mathbf y}$ is an extremal of $J$ connecting points $c$ and $\tuple {x, \mathbf y}$.
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Define a field of directions in $R$ by the following:
- $\map {\mathbf p} {x, \mathbf y, \mathbf y'} = \map {g_{\mathbf y} } {x, \mathbf y}$
where $\mathbf p$ stands for momentum.
Note, that it does not depend on the path defined by $\hat {\mathbf y}$, only on its endpoint at $\tuple {x, \mathbf y}$.
By definition, $ \map g {x, \mathbf y}$ is a geodetic distance $S$.
Hence, $g_\mathbf y$ does not explicitly depend on $\mathbf y'$.
Then:
- $\map {g_{\mathbf y} } {x, \mathbf y} = \map {\mathbf p} {x, \mathbf y, \mathbf z}$
where $\mathbf z = \map {\mathbf z} {x, \mathbf y}$ denotes slope of the curve joining $c$ and $\tuple {x, \mathbf y}$ at the point $\tuple {x, \mathbf y}$.
Furthermore, since $g$ is a geodetic distance, it satisfies Hamilton-Jacobi equation:
- $\ds \frac {\partial \map g {x, \mathbf y} } {\partial x} + \map H {x, \mathbf y, \map {g_{\mathbf y} } {x, \mathbf y} } = 0$
which together with the previous relation results in a system of equations:
- $\begin {cases} \dfrac {\partial \map g {x, \mathbf y} } {\partial x} + \map H {x, \mathbf y, \map {\mathbf p} {x, \mathbf y, \mathbf z} } = 0 \\ \map {\mathbf z} {x, \mathbf y} = \map{\mathbf y'} x \end {cases}$
Differentiation with respect to $\mathbf y$ yields:
- $\begin {cases} \dfrac {\partial \mathbf p} {\partial x} = -\dfrac {\partial H} {\partial \mathbf y} \\ \map {\mathbf z} {x,\mathbf y} = \map{\mathbf y'} x \end {cases}$
These are Euler's equations in canonical coordinates with a constraint on derivative.
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Hence, the previously defined field of directions coincides with the field of functional.
$\blacksquare$
Sources
- 1963: I.M. Gelfand and S.V. Fomin: Calculus of Variations ... (previous) ... (next): $\S 6.32$: The Field of a Functional