Characterization for Topological Evaluation Mapping to be Embedding/Necessary Condition
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Theorem
Let $X$ be a topological space.
Let $\family {Y_i}_{i \mathop \in I}$ be an indexed family of topological spaces for some indexing set $I$.
Let $\family {f_i : X \to Y_i}_{i \mathop \in I}$ be an indexed family of continuous mappings.
Let $\ds Y = \prod_{i \mathop \in I} Y_i$ be the product space of $\family {Y_i}_{i \mathop \in I}$.
Let $f : X \to Y$ be the evaluation mapping induced by $\family{f_i}_{i \mathop \in I}$.
Let $f$ be an embedding
Then:
- $(1)\quad$ the topology on $X$ is the initial topology with respect to $\family {f_i}_{i \mathop \in I}$
- $(2)\quad$ the family $\family {f_i}$ separates points
Proof
$(1)$ The Topology on $X$ is the Initial Topology
Let $f \sqbrk X$ denote the image of $f$.
Let $\tau_{f \sqbrk X}$ be the subspace topology on $f \sqbrk X$.
By definition of embedding:
- $f \restriction_{X \times f \sqbrk X}$ is a homeomorphism between $X$ and $f \sqbrk X$
From Subspace of Product Space has Initial Topology with respect to Restricted Projections:
- $\tau_{f \sqbrk X}$ is the initial topology on $f \sqbrk X$ with respect to the mappings $\family {\pr_i \restriction_{f \sqbrk X} : f \sqbrk X \to Y_i}_{i \mathop \in I}$
Let $\tau$ be the topology on $X$.
From Homeomorphic Topology of Initial Topology is Initial Topology:
- $\tau$ is the initial topology on $X$ with respect to $\family {\pr_i \restriction_{f \sqbrk X} \circ f \restriction_{X \times f \sqbrk X} : X \to Y_i}_{i \mathop \in I}$
We have:
\(\ds \pr_i \restriction_{f \sqbrk X} \circ f \restriction_{X \times f \sqbrk X}\) | \(=\) | \(\ds \pr_i \circ f\) | Composition of Mapping with Mapping Restricted to Image | |||||||||||
\(\ds \) | \(=\) | \(\ds f_i\) | Composite of Evaluation Mapping and Projection |
Hence:
- $\tau$ is the initial topology on $X$ with respect to $\family {f_i : X \to Y_i}_{i \mathop \in I}$
$\Box$
$(2)$ The Family $\family {f_i}$ Separates Points
By definition of embedding:
- $f$ is a homeomorphism between $X$ and $f \sqbrk X$
By definition of homeomorphism:
- $f$ is an injection
From Evaluation Mapping is Injective iff Mappings Separate Points:
- the family $\family {f_i}$ separates points.
$\blacksquare$