Chinese Remainder Theorem/Examples/n = 7 mod 12 so n = 3 mod 4
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Example of use of Chinese Remainder Theorem
Let $n \equiv 7 \pmod {12}$.
Then:
- $n \equiv 3 \pmod 4$
Proof
By the Chinese Remainder Theorem:
- $n \equiv 7 \pmod {12} \iff n \equiv 7 \pmod 3 \text { and } n \equiv 7 \pmod 4$
as $3$ and $4$ are coprime.
Thus given the hypothesis:
\(\ds n\) | \(\equiv\) | \(\ds 7\) | \(\ds \pmod {12}\) | |||||||||||
\(\ds \) | \(\equiv\) | \(\ds 7\) | \(\ds \pmod 4\) | Chinese Remainder Theorem | ||||||||||
\(\ds \) | \(\equiv\) | \(\ds 3\) | \(\ds \pmod 4\) |
$\blacksquare$
Sources
- 1978: Thomas A. Whitelaw: An Introduction to Abstract Algebra ... (previous) ... (next): Chapter $2$: Some Properties of $\Z$: Exercise $2.7$