Chiu Chang Suann Jing/Examples/Example 6
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Example of Problem from Chiu Chang Suann Jing
- There is a pool $10$ feet square, with a reed growing vertically in the centre,
- its roots at the bottom of the pool, which rises $1$ foot above the surface;
- when drawn towards the shore it reaches exactly to the brink of the pool;
- what is the depth of the water?
Solution
The water is $12$ feet deep.
Proof
Let the depth of the water be $d$.
The length of the reed is $d + 1$.
When drawn to the edge of the pool, the reed forms the hypotenuse of a right triangle.
One of the legs of that right triangle is the depth of the pool, which is $d$.
The other leg is the distance from the centre of the pool, which is $5$ feet.
Hence:
\(\ds \paren {d + 1}^2\) | \(=\) | \(\ds d^2 + 5^2\) | Pythagoras's Theorem | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds 2 d + 1\) | \(=\) | \(\ds 25\) | simplification | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds d\) | \(=\) | \(\ds 12\) | simplification |
The right triangle in question here is the $\text{5-12-13}$ triangle.
$\blacksquare$
Sources
- c. 100: Anonymous: Chiu Chang Suann Jing
- 1965: Henrietta Midonick: The Treasury of Mathematics: Volume $\text { 1 }$
- 1992: David Wells: Curious and Interesting Puzzles ... (previous) ... (next): The Nine Chapters: $64$