Circle of Apollonius in Complex Plane/Examples/mod z-3 over z+3 = 2/Proof 2

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Example of Circle of Apollonius in Complex Plane

The equation:

$\cmod {\dfrac {z - 3} {z + 3} } = 2$

describes a circle embedded in the complex plane whose radius is $4$ and whose center is $\paren {-5, 0}$.


Proof

\(\ds \cmod {\dfrac {z - 3} {z + 3} }\) \(=\) \(\ds 2\)
\(\ds \leadstoandfrom \ \ \) \(\ds \paren {\dfrac {z - 3} {z + 3} } \paren {\dfrac {\overline z - 3} {\overline z + 3} }\) \(=\) \(\ds 4\)
\(\ds \leadstoandfrom \ \ \) \(\ds z \overline z + 5 \overline z + 5 z + 9\) \(=\) \(\ds 0\)
\(\ds \leadstoandfrom \ \ \) \(\ds \paren {z + 5} \paren {\overline z + 5}\) \(=\) \(\ds 16\)
\(\ds \leadstoandfrom \ \ \) \(\ds \cmod {z + 5}\) \(=\) \(\ds 4\)

Hence the result by Equation of Circle in Complex Plane.

$\blacksquare$


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