# Class is Proper iff Bijection from Class to Proper Class

## Theorem

Let $A$ be a class.

Let $\mathrm P$ be a proper class.

Then $A$ is proper if and only if there exists a bijection from $A$ to $\mathrm P$.

### Corollary

$A$ is proper if and only if there exists a bijection from $\mathrm P$ to $A$.

## Proof

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### Necessary Condition

Suppose that $A$ is a proper class.

Then by the Axiom of Limitation of Size there exists a bijection $f: A \to \mathrm U$, where $\mathrm U$ is the universal class.

There also exists a bijection $g: \mathrm P \to \mathrm U$.

By Inverse of Bijection is Bijection, there exists a bijection $g^{-1}: \mathrm U \to \mathrm P$

From Composite of Bijections is Bijection, it follows that $f \circ g^{-1}: A \to \mathrm P$ is a bijection.

$\Box$

### Sufficient Condition

Suppose that there exists a bijection $f: A \to \mathrm P$.

Because $\mathrm P$ is a proper class, it follows from the Axiom of Limitation of Size that there exists a bijection $g: \mathrm P \to \mathrm U$.

Then by Composite of Bijections is Bijection, $f \circ g: A \to \mathrm U$ is a bijection from $A$ to the universe.

And so by the Axiom of Limitation of Size, $A$ is proper.

Hence the result.

$\blacksquare$