Commutativity of Powers in Group
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Theorem
Let $\left ({G, \circ}\right)$ be a group.
Let $a, b \in G$ such that $a$ and $b$ commute.
Then:
- $\forall m, n \in \Z: a^m \circ b^n = b^n \circ a^m$
This can be expressed in additive notation in the group $\left ({G, +}\right)$ as:
- $\forall m, n \in \Z: m a + n b = n b + m a$
Proof
By definition, all elements of a group are invertible.
Therefore Commutativity of Powers in Monoid‎ can be applied directly.
$\blacksquare$