# Complex Conjugate of Gamma Function

Jump to: navigation, search

## Theorem

Let $\Gamma$ denote the gamma function.

Then:

$\forall z \in \C \setminus \left\{{0, -1, -2, \ldots}\right\}: \Gamma \left({\overline z}\right) = \overline {\Gamma \left({z}\right)}$

## Proof

This is immediate from, say, the Euler form of $\Gamma$ and the fact that complex conjugation preserves products and sums.