Complex Vector Space with Dot Product is Hilbert Space

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $\C^d$ be a complex vector space with $d$ dimensions.

Let $\innerprod \cdot \cdot$ be the dot product on $\C^d$.



Then $\C^d$ endowed with $\innerprod \cdot \cdot$ is a Hilbert space.


Proof

Let us explore the inner product norm of $\innerprod \cdot \cdot$:

$\ds \norm z = \sqrt{ \sum_{i \mathop = 1}^d x_i^2 + y_i^2 }$

and subsequently the metric induced by $\norm \cdot$:

$\ds \map d {z, z'} = \norm {z - z'} = \sqrt{ \sum_{i \mathop = 1}^d \paren{ x_i - x'_i }^2 + \paren{ y_i - y'_i }^2 }$




Sources