Composition of Right Regular Representations
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Theorem
Let $\struct {S, *}$ be a semigroup.
Let $\rho_x$ be the right regular representation of $\struct {S, *}$ with respect to $x$.
Let $\rho_x \circ \rho_y$ be defined as the composition of the mappings $\rho_x$ and $\rho_y$.
Then $\forall x, y \in S$:
- $\rho_x \circ \rho_y = \rho_{y * x}$
Proof
Let $z \in S$.
\(\ds \map {\paren {\rho_x \circ \rho_y} } z\) | \(=\) | \(\ds \map {\rho_x} {\map {\rho_y} z}\) | Definition of Composition of Mappings | |||||||||||
\(\ds \) | \(=\) | \(\ds \map {\rho_x} {z * y}\) | Definition of Right Regular Representation | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {z * y} * x\) | Definition of Right Regular Representation | |||||||||||
\(\ds \) | \(=\) | \(\ds z * \paren {y * x}\) | Semigroup Axiom $\text S 1$: Associativity | |||||||||||
\(\ds \) | \(=\) | \(\ds \map {\rho_{y * x} } z\) | Definition of Right Regular Representation |
$\blacksquare$
Sources
- 1978: Thomas A. Whitelaw: An Introduction to Abstract Algebra ... (previous) ... (next): Chapter $6$: An Introduction to Groups: Exercise $2$