# Constant Function is Primitive Recursive

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## Theorem

The constant function $f_c: \N \to \N$, defined as:

- $\map {f_c} n = c$ where $c \in \N$

### General Case

The constant function of $k$ variables: $f_c^k: \N^k \to \N$, defined as:

- $\map {f_c^k} {n_1, n_2, \ldots, n_k} = c$ where $c \in \N$

## Proof

The proof proceeds by the Principle of Mathematical Induction.

### Base Case

First we note that $f_0: \N \to \N$ is the zero function, which is a basic primitive recursive function.

This is our base case.

### Induction Hypothesis

This is our induction hypothesis:

- $f_k: \N \to \N$ is primitive recursive for some given $k \in \N$.

Then we need to show:

- $f_{k + 1}: \N \to \N$ is primitive recursive.

### Induction Step

This is our induction step:

- $\map {f_{k + 1} } n = k + 1 = \map \Succ k = \map \Succ {\map {f_k} n}$

Now $\map {f_k} n$ is primitive recursive from our induction hypothesis.

Thus $\map {f_{k + 1} } n$ is obtained from the basic primitive recursive function $\Succ$ and $\map {f_k} n$ by substitution.

The result follows by the Principle of Mathematical Induction.

$\blacksquare$