Fermat Problem

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $\triangle ABC$ be a triangle


Let the vertices of $\triangle ABC$ all have angles less than $120 \degrees$.

Let $\triangle ABG$, $\triangle BCE$ and $\triangle ACF$ be equilateral triangles constructed on the sides of $ABC$.

Let $AE$, $BF$ and $CG$ be constructed.

Let $P$ be the point at which $AE$, $BF$ and $CG$ meet.


FermatPointConstruction.png


Then $P$ is the Fermat-Torricelli point of $\triangle ABC$.


If one of vertices of $\triangle ABC$ be of $120 \degrees$ or more, then that vertex is itself the Fermat-Torricelli point of $\triangle ABC$.


Proof

The sum of the distances will be a minimum when the lines $PA$, $PB$ and $PC$ all meet at an angle of $120 \degrees$.

This is a consequence of the Fermat problem being a special case of the Steiner Tree Problem.

Consider the circles which circumscribe the $3$ equilateral triangles $\triangle ABG$, $\triangle BCE$ and $\triangle ACF$.

Consider quadrilaterals formed by $\triangle ABG$, $\triangle BCE$ and $\triangle ACF$ along with another point on each of those circumscribing circles.

Because these are cyclic quadrilaterals, the angle formed with these new points is $120 \degrees$.

It follows that $\Box APBG$, $\Box BPCE$ and $\Box APCF$ are those cyclic quadrilaterals.

Hence $\angle APC = \angle APB = \angle BPC = 120 \degrees$ and the result follows.

$\blacksquare$


Also known as

The Fermat Problem is also recognised as a special case of the Steiner Tree Problem for $3$ nodes.

Some refer to it as the Steiner Problem, or Steiner's Problem, for Jakob Steiner, but there are a number of such problems, and it is a good idea to be able to distinguish between them.


Some sources present this as Fermat's Problem.


Also see


Source of Name

This entry was named for Pierre de Fermat.


Historical Note

Pierre de Fermat sent the problem now known as the Fermat Problem to Evangelista Torricelli, who immediately solved it and returned the solution to Fermat straight away.

Hence the point in question bears the name of either or both mathematicians.


Sources