Cosine of 144 Degrees

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Theorem

$\cos 144 \degrees = \cos \dfrac {4 \pi} 5 = -\dfrac \phi 2 = -\dfrac {1 + \sqrt 5} 4$

where $\cos$ denotes cosine.


Proof

\(\ds \cos 144 \degrees\) \(=\) \(\ds \map \cos {180 \degrees - 36 \degrees}\)
\(\ds \) \(=\) \(\ds -\cos 36 \degrees\) Cosine of Supplementary Angle
\(\ds \) \(=\) \(\ds -\dfrac {1 + \sqrt 5} 4\) Cosine of $36 \degrees$

$\blacksquare$