Covariance of Linear Combination of Random Variables with Another

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Theorem

Let $X, Y, Z$ be random variables.

Let $a, b$ be real numbers.


Then:

$\cov {a X + b Y, Z} = a \cov {X, Z} + b \cov {Y, Z}$


Proof

\(\ds \cov {a X + b Y, Z}\) \(=\) \(\ds \expect {\paren {a X + b Y} Z} - \expect {a X + b Y} \expect Z\) Covariance as Expectation of Product minus Product of Expectations
\(\ds \) \(=\) \(\ds a \expect {X Z} + b \expect {Y Z} - \paren {a \expect X + b \expect Y} \expect Z\) Expectation is Linear
\(\ds \) \(=\) \(\ds a \paren {\expect {X Z} - \expect X \expect Z} + b \paren {\expect {Y Z} - \expect Y \expect Z}\)
\(\ds \) \(=\) \(\ds a \cov {X, Z} + b \cov {Y, Z}\) Covariance as Expectation of Product minus Product of Expectations

$\blacksquare$