Cyclic Group is Abelian/Proof 2
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Theorem
Let $G$ be a cyclic group.
Then $G$ is abelian.
Proof
We have that Integers under Addition form Abelian Group.
The result then follows from combining:
$\blacksquare$
Sources
- 1965: Seth Warner: Modern Algebra ... (previous) ... (next): Chapter $\text {IV}$: Rings and Fields: $25$. Cyclic Groups and Lagrange's Theorem: Theorem $25.3$