Definite Integral to Infinity of Power of x over Power of x plus Power of a
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Theorem
- $\ds \int_0^\infty \dfrac {x^m \rd x} {x^n + a^n} = \frac {\pi a^{m + 1 - n} } {n \map \sin {\paren {m + 1} \frac \pi n} }$
for $0 < m + 1 < n$.
Proof
\(\ds \int_0^\infty \dfrac {x^m \rd x} {x^n + a^n}\) | \(=\) | \(\ds \int_0^\infty \dfrac {x^m \rd x} {\paren {x^{m + 1} }^{\frac n {m + 1} } + \paren {a^{m + 1} }^{\frac n {m + 1} } }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 {m + 1} \int_0^\infty \dfrac 1 {u^{\frac n {m + 1} } + \paren {a^{m + 1} }^{\frac n {m + 1} } } \rd u\) | substituting $u = x^{m + 1}$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 {\paren {m + 1} \paren {\frac n {m + 1} \paren {a^{m + 1} }^{\frac n {m + 1} - 1} } } \map \csc {\frac {\paren {m + 1} \pi} n}\) | Definite Integral to Infinity of $\dfrac 1 {1 + x^n}$: Corollary | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac {a^{m + 1} } {n a^{\paren {m + 1} \frac n {m + 1} } } \map \csc {\frac {\paren {m + 1} \pi} n}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac {\pi a^{m + 1 - n} } {n \map \sin {\paren {m + 1} \frac \pi n} }\) |
$\blacksquare$
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 15$: Definite Integrals involving Rational or Irrational expressions: $15.20$