Definition:Isomorphism (Abstract Algebra)

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This page is about isomorphisms in abstract algebra. For other uses, see Definition:Isomorphism.

Definition

An isomorphism is a homomorphism which is a bijection.

That is, it is a mapping which is both a monomorphism and an epimorphism.


An algebraic structure $\left({S, \circ}\right)$ is isomorphic to another algebraic structure $\left({T, *}\right)$ iff there exists an isomorphism from $\left({S, \circ}\right)$ to $\left({T, *}\right)$, and we can write $S \cong T$ (although notation may vary).


Semigroup Isomorphism

Let $\left({S, \circ}\right)$ and $\left({T, *}\right)$ be semigroups.

Let $\phi: S \to T$ be a (semigroup) homomorphism.


Then $\phi$ is a semigroup isomorphism iff $\phi$ is a bijection.


Monoid Isomorphism

Let $\left({S, \circ}\right)$ and $\left({T, *}\right)$ be monoids.

Let $\phi: S \to T$ be a (monoid) homomorphism.


Then $\phi$ is a monoid isomorphism if and only if $\phi$ is a bijection.


Group Isomorphism

Let $\struct {G, \circ}$ and $\struct {H, *}$ be groups.

Let $\phi: G \to H$ be a (group) homomorphism.


Then $\phi$ is a group isomorphism if and only if $\phi$ is a bijection.


Ring Isomorphism

Let $\left({R, +, \circ}\right)$ and $\left({S, \oplus, *}\right)$ be rings.

Let $\phi: R \to S$ be a (ring) homomorphism.


Then $\phi$ is a ring isomorphism if and only if $\phi$ is a bijection.


$F$-Isomorphism

Let $R, S$ be rings with unity.

Let $F$ be a subfield of both $R$ and $S$.


Let $\varphi: R \to S$ be an $F$-homomorphism such that $\varphi$ is bijective.


Then $\varphi$ is an $F$-isomorphism.


The relationship between $R$ and $S$ is denoted $R \ \cong_F \ S$.


Field Isomorphism

Let $\left({F, +, \circ}\right)$ and $\left({K, \oplus, *}\right)$ be fields.

Let $\phi: F \to K$ be a (field) homomorphism.


Then $\phi$ is a field isomorphism if and only if $\phi$ is a bijection.


R-Algebraic Structure Isomorphism

Let $\left({S, \ast_1, \ast_2, \ldots, \ast_n, \circ}\right)_R$ and $\left({T, \odot_1, \odot_2, \ldots, \odot_n, \otimes}\right)_R$ be $R$-algebraic structures.

Let $\phi: S \to T$ be an $R$-algebraic structure homomorphism.


Then $\phi$ is an $R$-algebraic structure isomorphism iff $\phi$ is a bijection.


Field Isomorphism

Let $\left({F, +, \circ}\right)$ and $\left({K, \oplus, *}\right)$ be fields.

Let $\phi: F \to K$ be a (field) homomorphism.


Then $\phi$ is a field isomorphism if and only if $\phi$ is a bijection.


Ordered Structure Isomorphism

An ordered structure isomorphism from an ordered structure $\left({S, \circ, \preceq}\right)$ to another $\left({T, *, \preccurlyeq}\right)$ is a mapping $\phi: S \to T$ that is both:

$(1): \quad$ An isomorphism, i.e. a bijective homomorphism, from the structure $\left({S, \circ}\right)$ to the structure $\left({T, *}\right)$
$(2): \quad$ An order isomorphism from the ordered set $\left({S, \preceq}\right)$ to the ordered set $\left({T, \preccurlyeq}\right)$.


Isomorphic Copy

Let $\phi: S \to T$ be an isomorphism.

Let $x \in S$.


Then $\phi \left({x}\right) \in T$ is known as the isomorphic copy of $x$ (under $\phi$).


Also see


Linguistic Note

The word isomorphism derives from the Greek morphe (μορφή) meaning form or structure, with the prefix iso- meaning equal.

Thus isomorphism means equal structure.


Sources