Definition talk:Arbitrarily Large

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I don't understand the last sentence. There is no $a$ for which such a statement can apply, because any such $a$ you think of there will be an $x$ such that $P(x)$. I believe this sentence is a holdover from "sufficiently large", and I believe it should be deleted. --prime mover 18:53, 18 March 2012 (EDT)

(Whoops.) Yeah. I'll delete it. Abcxyz 19:12, 18 March 2012 (EDT)