Definition talk:Equidistance
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I used Givant's definition for $R^2$ and extrapolated it to $R^n$. Is it correct? --GFauxPas 19:54, 25 January 2012 (EST)
- It certainly appears to be, and I'm quite sure it is. --Lord_Farin 02:28, 26 January 2012 (EST)