# Definition talk:Field Automorphism

Either in this definition or in that of Definition:Field Homomorphism, it has to be required that $1$ is sent to $1$. Otherwise, the resulting morphism may be trivial (everything is sent to $0$) and this not an automorphism. --barto (talk) 15:42, 28 January 2017 (EST)
This is what happens when deviating from the convention that ring morphisms preserve $1$. Many theorem and definition statements become tricky... --barto (talk) 16:35, 28 January 2017 (EST)