# Definition talk:Gamma Function/Integral Form

I think the Mellin Transform should be a theorem. Even though the result is immediate and would just be "by definition of such and such". My reasoning is that someone looking up the Gamma function should not be bothered by a definition of something else which may be of no interest to him or her. --GFauxPas (talk) 14:11, 27 November 2016 (EST)

- Well, not a theorem because that's how the Mellin transform is defined. --prime mover (talk) 15:57, 27 November 2016 (EST)

### Bounds of Integration

See my query on math.SE. It's worth mentioning that this integral is in fact doubly improper, because the integrand might not be defined at $0$. But I have no source, other than math.SE. I'd put up an explanation, but my sources gloss over this technicality. In any event, the page needs to explicitly state what kind of integral this is: improper complex Riemann, or Lebesgue. --GFauxPas (talk) 20:35, 29 November 2016 (EST)

- My advice, as always, is to hunt down a text which addresses the issue properly. --prime mover (talk) 02:27, 30 November 2016 (EST)