Derivative of Composite Function/Examples/(a x^2 + b x + c)^3
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Example of Derivative of Composite Function
- $\map {\dfrac \d {\d x} } {\paren {a x^2 + b x + c}^3} = 3 \paren {2 a x + b} \paren {a x^2 + b x + c}^2$
Proof
Let $u = a x^2 + b x + c$.
Let $y = u^3$.
Thus we have:
- $y = \paren {a x^2 + b x + c}^3$
and so:
\(\ds \dfrac {\d y} {\d x}\) | \(=\) | \(\ds \dfrac {\d y} {\d u} \dfrac {\d u} {\d x}\) | Derivative of Composite Function | |||||||||||
\(\ds \) | \(=\) | \(\ds 3 u^2 \paren {\map {\dfrac \d {\d x} } {a x^2} + \map {\dfrac \d {\d x} } {b x} + \map {\dfrac \d {\d x} } c}\) | Power Rule for Derivatives, Sum Rule for Derivatives | |||||||||||
\(\ds \) | \(=\) | \(\ds 3 u^2 \paren {2 a x + b}\) | Power Rule for Derivatives, Derivative of Constant | |||||||||||
\(\ds \) | \(=\) | \(\ds 3 \paren {2 a x + b} \paren {a x^2 + b x + c}^2\) | simplification |
$\blacksquare$
Sources
- 1953: L. Harwood Clarke: A Note Book in Pure Mathematics ... (previous) ... (next): $\text {II}$. Calculus: Differentiation: Exercises $\text {IX}$: $29$.