Derivative of Power of Function/Proof 1
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Theorem
Let $\map u x$ be a differentiable real function of $x$.
Let $n$ be a real number such that $n \ne -1$.
Then:
- $\map {\dfrac \d {\d x} } {\map u x^n} = n \map u x^{n - 1} \map {\dfrac \d {\d x} } {\map u x}$
Proof
\(\ds \map {\frac \d {\d x} } {\map u x^n}\) | \(=\) | \(\ds \map {\frac \d {\d u} } {\map u x^n} \map {\frac \d {\d x} } {\map u x}\) | Chain Rule for Derivatives | |||||||||||
\(\ds \) | \(=\) | \(\ds n \map u x^{n - 1} \map {\frac {\d u} {\d x} } {\map u x}\) | Derivative of Hyperbolic Sine |
$\blacksquare$