Diophantus of Alexandria/Arithmetica/Book 1/Problem 17/Solution
Jump to navigation
Jump to search
Problem
- The sums of $4$ numbers, omitting each of the numbers in turn, are $22$, $24$, $27$ and $20$ respectively
What are the numbers?
Solution
\(\ds a\) | \(=\) | \(\ds 9\) | ||||||||||||
\(\ds b\) | \(=\) | \(\ds 7\) | ||||||||||||
\(\ds c\) | \(=\) | \(\ds 4\) | ||||||||||||
\(\ds d\) | \(=\) | \(\ds 11\) |
Sources
- c. 250: Diophantus of Alexandria: Arithmetica: Book $\text I$: Problem $17$
- 1910: Sir Thomas L. Heath: Diophantus of Alexandria (2nd ed.): The Arithmetica: Book $\text {I}$: $17$
- 1992: David Wells: Curious and Interesting Puzzles ... (previous) ... (next): The First Pure Number Puzzles: $25$