Distance Function of Metric Space is Continuous

From ProofWiki
Jump to navigation Jump to search


Let $M = \struct {A, d}$ be a metric space.

Let $\tau_A$ be the topology on $A$ induced by $d$.

Let $\struct {A \times A, \tau}$ be the product space of $\struct {A, \tau_A}$ and itself.

Then the distance function $d: A \times A \to \R$ is a continuous mapping.


Let $d_\infty: \paren{A \times A}\times \paren{A \times A} \to \R$ be the metric on $A \times A$ defined by:

$\map {d_\infty} {\tuple{x, y}, \tuple{x', y'} } = \max \set{\map d {x, x'}, \map d {y, y'} }$

By P-Product Metric Induces Product Topology, $\tau$ is the topology on $A \times A$ induced by $d_\infty$.

Let $\epsilon \in \R_{>0}$ be a strictly positive real number.

Let $\tuple {x_0, y_0} \in A \times A$.

Suppose that $\tuple {x, y} \in A \times A$ and $\map {d_\infty} {\tuple{x, y}, \tuple{x_0, y_0} } < \dfrac 1 2 \epsilon$.


\(\displaystyle \size {\map d {x, y} - \map d {x_0, y_0} }\) \(\le\) \(\displaystyle \size {\map d {x, y} - \map d {x_0, y} } + \size {\map d {x_0, y} - \map d {x_0, y_0} }\) Triangle Inequality for Real Numbers
\(\displaystyle \) \(\le\) \(\displaystyle \map d {x, x_0} + \map d {y, y_0}\) Reverse Triangle Inequality
\(\displaystyle \) \(<\) \(\displaystyle \epsilon\) by the definition of $d_\infty$

The result follows from the definition of a continuous mapping.