Distinct Matroid Elements are Parallel iff Each is in Closure of Other/Lemma
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Theorem
Let $M = \struct {S, \mathscr I}$ be a matroid.
Let $a, b \in S$.
Let $\set a$ and $\set b$ be independent.
Then $\set {a, b}$ is dependent if and only if:
- $a \in \map \sigma {\set b}$
and
- $b \in \map \sigma {\set a}$
where $\sigma: \powerset S \to \powerset S$ denotes the closure operator of $M$.
Proof
\(\ds \set {a, b}\) | \(\notin\) | \(\ds \mathscr I\) | ||||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \set a \cup \set b\) | \(\notin\) | \(\ds \mathscr I\) | Union of Disjoint Singletons is Doubleton | ||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds a\) | \(\in\) | \(\ds \map \sigma {\set b}\) | Element Depends on Independent Set iff Union with Singleton is Dependent | ||||||||||
\(\, \ds \land \, \) | \(\ds b\) | \(\in\) | \(\ds \map \sigma {\set a}\) | Element Depends on Independent Set iff Union with Singleton is Dependent |
$\blacksquare$