Divisor Count of 180
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Example of Use of Divisor Count Function
- $\map {\sigma_0} {180} = 18$
where $\sigma_0$ denotes the divisor count function.
Proof
From Divisor Count Function from Prime Decomposition:
- $\ds \map {\sigma_0} n = \prod_{j \mathop = 1}^r \paren {k_j + 1}$
where:
- $r$ denotes the number of distinct prime factors in the prime decomposition of $n$
- $k_j$ denotes the multiplicity of the $j$th prime in the prime decomposition of $n$.
We have that:
- $180 = 2^2 \times 3^2 \times 5$
Thus:
\(\ds \map {\sigma_0} {180}\) | \(=\) | \(\ds \map {\sigma_0} {2^2 \times 3^2 \times 5^1}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \paren {2 + 1} \paren {2 + 1} \paren {1 + 1}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 18\) |
The divisors of $180$ can be enumerated as:
- $1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180$
This sequence is A018321 in the On-Line Encyclopedia of Integer Sequences (N. J. A. Sloane (Ed.), 2008).
$\blacksquare$