Double Pointed Topology is not T0/Proof 2
Theorem
Let $T_1 = \struct {S, \tau_S}$ be a topological space.
Let $D = \struct {A, \set {\O, A} }$ be the indiscrete topology on an arbitrary doubleton $A = \set {a, b}$.
Let $T = \struct {T_1 \times D, \tau}$ be the double pointed topological space on $T_1$.
Then $T$ is not a $T_0$ (Kolmogorov) space.
Proof
By definition, the double pointed topology $\tau$ on $T_1$ is the product topology on $T_1 \times D$.
By definition, $D$ is the indiscrete space on a doubleton.
Aiming for a contradiction, suppose $T$ is a $T_0$ (Kolmogorov) space.
Then from Product Space is $T_0$ iff Factor Spaces are $T_0$ it follows that $D$ is also a $T_0$ (Kolmogorov) space.
But from Indiscrete Non-Singleton Space is not $T_0$, $D$ is not a $T_0$ (Kolmogorov) space.
The result follows by Proof by Contradiction.
$\blacksquare$