Doubleton Class of Equal Sets is Singleton Class
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Theorem
Let $V$ be a basic universe.
Let $a, b \in V$ be sets.
Consider the doubleton class $\set {a, b}$.
Let $a = b$.
Then:
- $\set {a, b} = \set a$
where $\set a$ denotes the singleton class of $a$.
Proof
Let $A = \set {a, b}$
The existence of $A$ is shown in Doubleton Class can be Formed from Two Sets:
- $A := \set {x: \paren {x = a \lor x = b} }$
Let $a = b$.
Then:
\(\ds A\) | \(=\) | \(\ds \set {a, b}\) | Definition of $A$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \set {a, a}\) | as $a = b$ | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds x \in \set {a, a}\) | \(\iff\) | \(\ds \paren {x = a \lor x = a}\) | Definition of $A$ | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds x \in \set {a, a}\) | \(\iff\) | \(\ds x = a\) | Rule of Idempotence | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds x \in \set {a, a}\) | \(\iff\) | \(\ds x \in \set a\) | Definition of Singleton Class |
$\blacksquare$
Sources
- 2010: Raymond M. Smullyan and Melvin Fitting: Set Theory and the Continuum Problem (revised ed.) ... (previous) ... (next): Chapter $2$: Some Basics of Class-Set Theory: $\S 4$ The pairing axiom