Equation of Straight Line in Plane/Normal Form
Theorem
Let $\LL$ be a straight line such that:
- the perpendicular distance from $\LL$ to the origin is $p$
- the angle made between that perpendicular and the $x$-axis is $\alpha$.
Then $\LL$ can be defined by the equation:
- $x \cos \alpha + y \sin \alpha = p$
Polar Form
Let $\LL$ be defined in normal form:
- $x \cos \alpha + y \sin \alpha = p$
Then $\LL$ can be presented in polar coordinates as:
- $r \map \cos {\theta - \alpha} = p$
Proof 1
Let $A$ be the $x$-intercept of $\LL$.
Let $B$ be the $y$-intercept of $\LL$.
Let $A = \tuple {a, 0}$ and $B = \tuple {0, b}$.
From the Equation of Straight Line in Plane: Two-Intercept Form, $\LL$ can be expressed in the form:
- $(1): \quad \dfrac x a + \dfrac y a = 1$
Then:
\(\ds p\) | \(=\) | \(\ds a \cos \alpha\) | Definition of Cosine of Angle | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds a\) | \(=\) | \(\ds \dfrac p {\cos \alpha}\) |
\(\ds p\) | \(=\) | \(\ds b \sin \alpha\) | Definition of Sine of Angle | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds b\) | \(=\) | \(\ds \dfrac p {\sin \alpha}\) |
Substituting for $a$ and $b$ in $(1)$:
\(\ds \dfrac x a + \dfrac y a\) | \(=\) | \(\ds 1\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds \dfrac {x \cos \alpha} p + \dfrac {y \sin \alpha} p\) | \(=\) | \(\ds 1\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds x \cos \alpha + y \sin \alpha\) | \(=\) | \(\ds p\) |
$\blacksquare$
Proof 2
Let $P = \tuple {x, y}$ be an arbitrary point on $\LL$.
Let $O$ be the origin of the Cartesian plane in which $\LL$ is embedded.
Let $PQ$ be the perpendicular dropped from $P$ to the $x$-axis.
Let $QS$ be the perpendicular dropped from $Q$ to the line $ON$.
Let $PR$ be the perpendicular dropped from $P$ to the line $QS$.
By definition of cosine:
- $OS = OQ \cos \alpha$
By definition of sine:
- $PR = PQ \sin \alpha$
Then:
\(\ds p\) | \(=\) | \(\ds ON\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds OS + SN\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds OS + PR\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds OQ \cos \alpha + PQ \sin \alpha\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds x \cos \alpha + y \sin \alpha\) |
$\blacksquare$
Also known as
The normal form of a straight line in the plane is also known as the canonical form.
Some sources refer to it as the $\tuple {p, \alpha}$ form, after the symbols conventionally used to define it.
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 10$: Formulas from Plane Analytic Geometry: $10.6$: Normal Form for Equation of Line
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- 1933: D.M.Y. Sommerville: Analytical Conics (3rd ed.) ... (previous) ... (next): Chapter $\text {II}$. The Straight Line: $4$. Special forms of the equation of a straight line: $(5)$ Normal or canonical form