Equation of Vertical Line

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Theorem

Let $\LL$ be a vertical line embedded in the Cartesian plane $\CC$.


Then the equation of $\LL$ can be given by:

$x = a$

where $\tuple {a, 0}$ is the point at which $\LL$ intersects the $x$-axis.


Graph-of-vertical-line.png


Proof

From the Normal Form of Equation of Straight Line in Plane, a general straight line can be expressed in the form:

$x \cos \alpha + y \sin \alpha = p$

where:

$p$ is the length of a perpendicular $\PP$ from $\LL$ to the origin.
$\alpha$ is the angle made between $\PP$ and the $x$-axis.

As $\LL$ is vertical, then by definition $\PP$ is horizontal.

By definition, the horizontal line through the origin is the $x$-axis itself.

Thus $\alpha = 0$ and $p = a$

Hence the equation of $\LL$ becomes:

\(\ds x \cos 0 + y \sin 0\) \(=\) \(\ds a\)
\(\ds \leadsto \ \ \) \(\ds x\) \(=\) \(\ds a\) Sine of Zero is Zero, Cosine of Zero is One

Hence the result.

$\blacksquare$


Also see